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The Weston standard cell is given by \(\mathrm{Cd}(\mathrm{Hg}, 12.5 \% \mathrm{Cd})\left|\mathrm{CdSO}_{4}(a q, \mathrm{satd})\right| \mathrm{Hg}_{2} \mathrm{SO}_{4}(s) \mid \mathrm{Hg}(l)\) Write the reaction equation that occurs in the cell. Ten Weston standard cells that use a saturated \(\operatorname{CdSO}_{4}(a q)\) solution are maintained at the U.S. Bureau of Standards as the official unit of voltage. The voltage of each cell is virtually constant at \(1.01857 \mathrm{~V}\) at \(25^{\circ} \mathrm{C}\). Explain why the voltage remains constant. Here \(\mathrm{Cd}(\mathrm{Hg}, 12.5 \% \mathrm{Cd})\) stands for a cadmium mercury amalgam containing \(12.5 \%\) cadmium in mercury by mass.

Short Answer

Expert verified
The reaction is: \( \text{Cd(Hg)} + \text{Hg}_2\text{SO}_4 \rightarrow \text{CdSO}_4 + 2\text{Hg} \). Voltage remains constant due to stable conditions.

Step by step solution

01

Identify the Components of the Cell

The Weston standard cell is comprised of the following components: the anode (Cd(Hg)), cathode (Hg2SO4), and electrolyte (CdSO4(satd)). This setup defines the electrochemical reaction occurring within the cell.
02

Write the Half-Reaction for the Anode

At the anode, oxidation occurs. The reaction for cadmium is: \( \text{Cd(Hg)} \rightarrow \text{Cd}^{2+} + 2e^- \). This equation represents the oxidation of cadmium to cadmium ions, releasing electrons.
03

Write the Half-Reaction for the Cathode

At the cathode, reduction occurs. The reaction for mercurous sulfate is: \( \text{Hg}_2\text{SO}_4 + 2e^- \rightarrow 2\text{Hg} + \text{SO}_4^{2-} \). This equation represents the reduction of Hg2SO4 to mercury and sulfate ions.
04

Combine the Half-Reactions to Form the Cell Reaction

To find the overall cell reaction, combine the anode and cathode half-reactions: \( \text{Cd(Hg)} + \text{Hg}_2\text{SO}_4 \rightarrow \text{CdSO}_4 + 2\text{Hg} \). This combined equation shows the complete electrochemical process in the cell.
05

Explain the Constant Voltage of the Cell

The voltage of the Weston cell remains constant because it operates under standard conditions, with a saturated solution of \( \text{CdSO}_4 \), ensuring constant ion concentration. The equilibrium of the electrochemical reactions is maintained, resulting in a stable voltage output.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Electrochemical Reactions
An electrochemical reaction is a process where chemical energy is converted into electrical energy, or vice versa. In the context of a Weston standard cell, these reactions occur at the electrodes within the cell.
This cell acts as a source of consistent voltage through a chemical reaction that involves the flow of electrons from one substance to another. Specifically, in an electrochemical cell,
  • The anode is the negative electrode where oxidation occurs, releasing electrons.
  • The cathode is the positive electrode where reduction takes place, accepting electrons.
The reactions at these electrodes are crucial to maintaining the cell's function, as they directly affect the transfer and movement of electrons, contributing to the cell's overall voltage output.
Each electrochemical reaction in the Weston cell helps facilitate the conversion of cadmium from the amalgam at the anode into ions and the conversion of mercurous sulfate at the cathode into mercury. This forms the basis of the steady and reliable electrical output of the cell.
Exploring Cell Voltage
The cell voltage, often called electromotive force (EMF), is the measure of the electrical potential difference between the two electrodes in an electrochemical cell. In the case of the Weston standard cell, this voltage is precisely maintained at 1.01857 V at 25°C.
Several factors contribute to this stable voltage:
  • Standard conditions, such as temperature and pressure, remain constant.
  • The concentration of electrolytes is kept saturation, ensuring consistent ion availability.
The equilibrium condition of the electrochemical reactions is critical here.
It ensures that the cell operates with minimal changes over time, which is why Weston cells were historically used as standard references for measuring voltage.
The minimal variance in the cell's voltage is due to the highly predictable and controlled reactions at the electrodes.
This makes it a reliable unit of voltage for precision measurements.
Comprehending Half-Reactions
Half-reactions are a way to represent the oxidation and reduction processes separately in an electrochemical reaction. They are essential for understanding how overall reactions occur inside the cell and help to predict the direction of electron flow.
The Weston standard cell involves two key half-reactions:
  • Anode Reaction (Oxidation): Here, the cadmium in the amalgam oxidizes by losing two electrons. This can be shown as: \[ \text{Cd(Hg)} \rightarrow \text{Cd}^{2+} + 2e^- \]
  • Cathode Reaction (Reduction): This is where mercurous sulfate gains electrons, transforming into elemental mercury and sulfate ions: \[ \text{Hg}_2\text{SO}_4 + 2e^- \rightarrow 2\text{Hg} + \text{SO}_4^{2-} \]
These half-reactions not only define the individual processes occurring at each electrode but also combine to form the overall reaction for the cell.
The understanding of these separate reactions is crucial for determining the cell's voltage and ensuring the effective operation of the electrochemical cell.

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