Chapter 22: Problem 32
Calculate the solubility of \(\mathrm{AgC}_{6} \mathrm{H}_{5} \mathrm{COO}(s)\) in grams per liter in an aqueous solution buffered at \(\mathrm{pH}=4.00\) at \(25^{\circ} \mathrm{C} .\) Given \(K_{\mathrm{a}}=6.3 \times 10^{-5} \mathrm{M}\) for \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}(a q)\) and that \(K_{\mathrm{sp}}=2.5 \times 10^{-5} \mathrm{M}^{2}\) for \(\mathrm{AgC}_{6} \mathrm{H}_{5} \mathrm{COO}(s)\).
Short Answer
Step by step solution
Write the Dissociation Equations
Determine the Effect of pH on Benzoate Ion
Calculate Equilibrium Concentrations
Setup the K_sp Expression
Solve for Ag+ Concentration
Calculate Solubility in g/L
Final Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Solubility Product Constant
For example, in the dissociation of silver benzoate \( \text{AgC}_6\text{H}_5\text{COO(s)} \), the solubility product is given by the expression:\[K_{sp} = [\text{Ag}^+][\text{C}_6\text{H}_5\text{COO}^-]\]This equation signifies that the product of the equilibrium concentrations of the ions \([\text{Ag}^+]\) and \([\text{C}_6\text{H}_5\text{COO}^-]\) in solution must not exceed \( K_{sp} \).
- A small \( K_{sp} \) value implies that the salt is not very soluble in water.
- \( K_{sp} \) values are unique to each compound and vary with temperature.
Acid Dissociation Constant
Considering our exercise, the benzene acid \( \text{C}_6\text{H}_5\text{COOH} \) partially dissociates in water as follows:\[\text{C}_6\text{H}_5\text{COOH} \rightleftharpoons \text{C}_6\text{H}_5\text{COO}^- + \text{H}^+\]The expression for the \( K_a \) is:\[K_a = \frac{[\text{C}_6\text{H}_5\text{COO}^-][\text{H}^+]}{[\text{C}_6\text{H}_5\text{COOH}]}\]
- A higher \( K_a \) value indicates a stronger acid that ionizes more completely.
- Weak acids, such as benzoic acid, have low \( K_a \) values.
Equilibrium Concentration of Ions
For the given problem, the equilibrium concentration of \([\text{C}_6\text{H}_5\text{COO}^-]\) was calculated using the acid dissociation constant \( K_a \) and the concentration of hydrogen ions \([\text{H}^+]\).
- Given \( K_a = 6.3 \times 10^{-5} \) and \([\text{H}^+] = 10^{-4} \), the concentration \([\text{C}_6\text{H}_5\text{COO}^-] = 0.63 \) M.
- The concentration \([\text{Ag}^+]\) was then calculated to be \( 3.97 \times 10^{-5} \) M using the \( K_{sp} \) expression.
Solubility in Buffered Solutions
Buffers resist changes in pH upon the addition of an acid or base because they contain significant amounts of both a weak acid and its conjugate base.
In this scenario, the solution is buffered at pH 4. This means that the \([\text{H}^+]\) concentration remains constant at \( 10^{-4} \) M, influencing the solubility of silver benzoate.
- The buffering effect ensures consistent ion concentrations, ensuring the ongoing physical and chemical stability of the solution.
- The given solubility of \( 0.0086 \) g/L was calculated by maintaining this buffered condition while considering the \( K_{sp} \) and \( K_a \).