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Identify which of the following species are Br酶nsted-Lowry acids and which are Br酶nsted-Lowry bases in water. In each case give the chemical formula for the conjugate member of the conjugate acid-base pair: (a) \(\mathrm{HCNO}(a q)\) (b) \(\mathrm{OBr}^{-}(a q)\) (c) \(\mathrm{HClO}_{3}(a q)\) (d) \(\mathrm{CH}_{3} \mathrm{NH}_{3}^{*}(a q)\) (e) \(\mathrm{ClNH}_{2}(a q)\) (f) \(\mathrm{HONH}_{2}(a q)\)

Short Answer

Expert verified
(a) HCNO: acid, conjugate base CNO鈦. (b) OBr鈦: base, conjugate acid HOBr. (c) HClO鈧: acid, conjugate base ClO鈧冣伝. (d) CH鈧僋H鈧冣伜: acid, conjugate base CH鈧僋H鈧. (e) ClNH鈧: base, conjugate acid ClNH鈧冣伜. (f) HONH鈧: acid, conjugate base HONH鈦.

Step by step solution

01

Understand Br酶nsted-Lowry Theory

A Br酶nsted-Lowry acid is a species that donates a proton (H鈦), while a Br酶nsted-Lowry base is a species that accepts a proton. The conjugate base is formed when the acid donates a proton, and the conjugate acid is formed when the base accepts a proton.
02

Analyze HCNO(aq)

HCNO is a Br酶nsted-Lowry acid because it can donate a proton (H鈦) to form the conjugate base CNO鈦. The proton donating ability is due to the presence of the hydrogen atom, which can be released as H鈦.
03

Analyze OBr鈦(aq)

OBr鈦 is a Br酶nsted-Lowry base because it can accept a proton to form its conjugate acid, HOBr. The presence of a negative charge indicates its potential to accept a proton.
04

Analyze HClO鈧(aq)

HClO鈧 is a Br酶nsted-Lowry acid because it can donate a proton to water to form ClO鈧冣伝, its conjugate base. The hydrogen in the acid structure is capable of being released as a proton (H鈦).
05

Analyze CH鈧僋H鈧冣伜(aq)

CH鈧僋H鈧冣伜 is a Br酶nsted-Lowry acid because it can donate a proton to form CH鈧僋H鈧, its conjugate base. Typically, the proton is lost from the nitrogen, changing the charge from +1 to neutral.
06

Analyze ClNH鈧(aq)

ClNH鈧 is a Br酶nsted-Lowry base because it can accept a proton to form ClNH鈧冣伜, its conjugate acid. The presence of lone pairs on the nitrogen enables it to accept H鈦 ions.
07

Analyze HONH鈧(aq)

HONH鈧 can act as a Br酶nsted-Lowry acid by donating a proton to form HONH鈦. Thus, it is a proton donor.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid-Base Reactions
Acid-base reactions are fundamental chemical processes extensively described by the Br酶nsted-Lowry theory. According to this theory, an acid is a substance that can donate a proton ( H^+ ) in a reaction, while a base is defined as a substance that can accept a proton. Understanding these reactions is essential, as they are integral to many natural and industrial processes.
Consider HCNO(aq) as an example of an acid under Br酶nsted-Lowry premises. This compound can release a proton to become its conjugate base, CNO^-. On the other hand, a compound like OBr^- can grab a free proton, illustrating its nature as a base by transforming into HOBr, its conjugate acid. These reactions involve transferring protons, which are pivotal in the formation of new substances and equilibrium conditions in water.
Conjugate Acid-Base Pairs
Conjugate acid-base pairs are crucial concepts when discussing Br酶nsted-Lowry theory. These pairs are born from the initial action of either donating or accepting a proton. For any given acid, when it releases a proton, what remains becomes its conjugate base. Similarly, when a base accepts a proton, the resultant compound is its conjugate acid.
Taking HClO_3(aq) as an illustration, when it donates a proton, it leaves behind ClO_3^- as its conjugate base. Conversely, when substances like CH_3NH_3^+(aq) donate a proton, they transform into their conjugate base CH_3NH_2. Whether in an aqueous solution or other medium, every acid or base reaction results in these pairs, contributing significantly to the overall chemical balance.
Proton Transfer
Proton transfer is the hallmark of any Br酶nsted-Lowry acid-base reaction, facilitating the transformation of substances through the movement of protons ( H^+ ions). This transfer is what defines which of the reactants behaves as an acid and which as a base. Generally, an acid will send off a proton to be received by a base.
Instances such as ClNH_2(aq) demonstrate base characteristics by accepting a proton to become ClNH_3^+. Similarly, HONH_2 can act as an acid by shedding a proton, forming HONH^-. These exchanges not only determine the identity of the reactants as acids or bases but also drive many chemical reactions by altering the composition and charge of the involved species. This dynamic is key to understanding the perpetual movement and balance of substances in various environments.

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Most popular questions from this chapter

The \(\mathrm{pH}\) of a \(0.050\) -M aqueous solution of pyruvic acid, \(\mathrm{CH}_{3} \mathrm{COCOOH}(a q)\), an intermediate in the metabolism of glucose, is found to be 1.91. Calculate \(K_{\mathrm{a}}\), the acid- dissociation constant, for pyruvic acid.

Although the \(\mathrm{pH}\) of neutral water is said to be \(7.00\) at \(25^{\circ} \mathrm{C}\), the experimentally measured \(\mathrm{pH}\) of a typical water sample is about \(5.6 .\) This is true both for tap water and for samples of store-bought distilled or deionized water that contain no dissolved metal ions. Explain this observation.

Explain why a \(0.10\) -M aqueous solution of sodium hydroxide, \(\mathrm{NaOH}(a q)\), is highly basic, whereas a \(0.10\) -M aqueous solution of methanol, \(\mathrm{CH}_{3} \mathrm{OH}(a q)\), is essentially neutral.

Uric acid is an end product of the metabolism of certain biological compounds. Gout is a disease of the joints that is due to the precipitation of sodium urate crystals. Given that under physioogical conditions \(\mathrm{HC}_{3} \mathrm{H}_{3} \mathrm{~N}_{4} \mathrm{O}_{3}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \leftrightharpoons \mathrm{C}_{3} \mathrm{H}_{3} \mathrm{~N}_{4} \mathrm{O}_{5}^{-}(a q)+\mathrm{H}_{3} \mathrm{O}^{+}(a q)\) uric acid urate ion with \(K_{\mathrm{a}}=1.6 \times 10^{-6} \mathrm{M}\) at \(25^{\circ} \mathrm{C}\). Determine the \(\mathrm{pH}\) values for which [urate] \(>\) [uric acid]

Sodium propanoate, \(\mathrm{NaCH}_{3} \mathrm{CH}_{2} \mathrm{COO}(s)\), is used as a food preservative. Calculate the \(\mathrm{pH}\) at \(25^{\circ} \mathrm{C}\) of a \(0.20-\mathrm{M}\) solution of \(\mathrm{NaCH}_{3} \mathrm{CH}_{2} \mathrm{COO}(a q)\), taking \(K_{\mathrm{a}}=1.4 \times 10^{-5} \mathrm{M}\) for propanoic acid.

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