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Use Le Ch芒telier's principle to predict the direction in which the acid- dissociation equilibrium described by the following equation shifts in response to the indicated change in conditions: $$ \mathrm{CO}_{2}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l) \leftrightharpoons \mathrm{H}_{3} \mathrm{O}^{+}(a q)+\mathrm{HCO}_{\mathrm{s}}^{-}(a q) $$ if (a) \(\left[\mathrm{CO}_{2}\right]\) is decreased (b) \(\left[\mathrm{HCO}_{3}^{-}\right]\) is decreased (c) [ \(\mathrm{H}_{3} \mathrm{O}^{4}\) ] is decreased (d) the solution is diluted with water

Short Answer

Expert verified
(a) Left; (b) Right; (c) Right; (d) Right

Step by step solution

01

Understanding Le Ch芒telier's Principle

Le Ch芒telier's Principle states that if a stress is applied to a system at equilibrium, the system will adjust itself in such a way as to counteract the effect of the stress and re-establish equilibrium. Typical stresses include changes in concentration, pressure, volume, and temperature.
02

Analyze the Effect of Decreasing [CO鈧俔

If \([\mathrm{CO}_{2}]\) is decreased, the equilibrium will shift towards the side that produces \([\mathrm{CO}_{2}]\), which is the left side (reactants). This shift attempts to replace the \([\mathrm{CO}_{2}]\) that was removed.
03

Analyze the Effect of Decreasing [HCO鈧冣伝]

If \(\mathrm{HCO}_3^鈭抃) is decreased, the equilibrium will shift towards the right (products) to produce more \(\mathrm{HCO}_3^鈭抃) in response to the reduction.
04

Analyze the Effect of Decreasing [H鈧僌鈦篯

If \([\mathrm{H}_{3} \mathrm{O}^{+}]\) is decreased, the equilibrium will shift towards the right (products) to produce more \([\mathrm{H}_{3} \mathrm{O}^{+}]\).
05

Analyze the Effect of Dilution with Water

Diluting the solution with water reduces the concentration of both products and reactants. However, since water is a reactant, dilution favors a shift to the side with the greater amount of aqueous species, often driving the equilibrium towards the side with fewer water molecules, which here is the right (products).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid-Dissociation Equilibrium
An acid-dissociation equilibrium refers to the state when an acid donates a proton to form its conjugate base, while a water molecule accepts the proton to form hydronium ions. In the given equation, carbon dioxide (\( \text{CO}_2 \text{(aq)} \)) reacts with water to form \( \text{H}_3\text{O}^+ \text{(aq)} \) and bicarbonate ions (\( \text{HCO}_3^- \text{(aq)} \)). This process occurs in a reversible way until a chemical equilibrium is reached. When \( \text{CO}_2 \) is added, the acidity of a solution increases due to more \( \text{H}_3\text{O}^+ \) ions forming. This balance between reactants and products ensures that the forward and reverse reaction rates are equal when the system is at equilibrium. When a change, like removing some \( \text{CO}_2 \), takes place, the equilibrium is disturbed, prompting the system to adjust to restore balance.
Equilibrium Shift
An equilibrium shift happens when the balance between forward and reverse reactions is disturbed, often due to changes in concentration, pressure, or temperature. According to Le Ch芒telier's Principle, the system will try to minimize the effects of this disturbance by shifting in a direction that counteracts the change. For instance, when \( [\text{CO}_2] \) is decreased, the equilibrium shifts left to make more \( \text{CO}_2 \). Conversely, decreasing \( [\text{HCO}_3^-] \) or \( [\text{H}_3\text{O}^+] \) causes the equilibrium to shift right, generating more products. Each shift aims to replace what's been removed, re-stabilizing the system's equilibrium.
Chemical Equilibrium
Chemical equilibrium is a state where the concentrations of reactants and products remain unchanged over time. This doesn't mean reactions stop; rather, the rate at which reactants turn into products equals the rate products revert to reactants.The reaction \( \text{CO}_2(aq) + 2\text{H}_2\text{O}(l) \leftrightharpoons \text{H}_3\text{O}^+(aq) + \text{HCO}_3^-(aq) \) exemplifies this. At equilibrium, the system achieves a balance that is only influenced when external changes are applied. These adjustments trigger shifts as described by Le Ch芒telier's Principle.
Reaction Conditions Change
Changes in reaction conditions affect the chemical equilibrium, causing the system to respond and shift to a new equilibrium position. These changes can include alterations in concentration, temperature, volume, or, as with dilution, the solvent.In our context, dilution with water decreases the concentration of both reactants and products, yet it increases solvent volume. As water is a reactant, the system often shifts to offset this increase, typically favoring the side with more non-water species, in this case, moving toward the products.
  • As \( [\text{CO}_2] \), \( [\text{HCO}_3^-] \), or \( [\text{H}_3\text{O}^+] \) decreases, equilibrium shifts help restore lost equilibrium parts.
  • Dilution often influences equilibrium differently than changes like concentration, due to changes in solvency and reactant roles.
Each alteration requires examining how the change might be countered by a directional shift, intricately depending on the properties of the substances involved.

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Most popular questions from this chapter

The acid-dissociation constant at \(25^{\circ} \mathrm{C}\) for the equilibrium described by $$ \begin{aligned} \left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{5+}(a q)+& \mathrm{H}_{2} \mathrm{O}(l) \leftrightharpoons \\ & \mathrm{H}_{3} \mathrm{O}^{+}(a q)+\left[\mathrm{Fe}(\mathrm{OH})\left(\mathrm{H}_{2} \mathrm{O}\right)_{\xi}\right]^{2+}(a q) \end{aligned} $$ is \(K_{\mathrm{a}}=6.7 \times 10^{-3} \mathrm{M} .\) Calculate the \(\mathrm{pH}\) of a \(0.20-\mathrm{M}\) solution of \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}(a q)\) at \(25^{\circ} \mathrm{C}\).

Calculate the \(\mathrm{pH}\) of an aqueous solution that is \(0.20 \mathrm{M}\) in \(\mathrm{CsOH}(a q)\) at \(25^{\circ} \mathrm{C}\). Is the solution acidic or basic?

The \(\mathrm{pH}\) of the contents of the human stomach can be as low as \(1.0 .\) Calculate the value of \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) in the stomach when the \(\mathrm{pH}=1.0\).

A student observes that when lithium metal, \(\mathrm{Li}(s)\), is added to water, the solution bubbles and the \(\mathrm{pH}\) becomes basic; whereas when lithium chloride, \(\mathrm{LiCl}(s)\), is added to water, the solution remains neutral. Explain these observations.

Calculate the \(\mathrm{pH}\) and the concentrations of the other species in a \(0.10-\mathrm{M}\) aqueous solution of chloroacetic acid, \(\mathrm{ClCH}_{2} \mathrm{COOH}(a q)\), given that \(K_{\mathrm{a}}=\) \(1.4 \times 10^{-5} \mathrm{M}\) at \(25^{\circ} \mathrm{C}\)

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