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The Henry's law constant for \(\mathrm{CO}_{2}(g)\) in water at \(25^{\circ} \mathrm{C}\) is \(29 \mathrm{bar} \cdot \mathrm{M}^{-1} .\) Estimate the concentration of dissolved \(\mathrm{CO}_{2}(g)\) in a carbonated soft drink pressurized with \(2.0\) bar of \(\mathrm{CO}_{2}(g)\).

Short Answer

Expert verified
The concentration of dissolved CO鈧 is 58 M.

Step by step solution

01

Identify Known Values

Henry's law relates the pressure of a gas above a liquid to its concentration in the liquid using the constant, which is given for CO鈧 as 29 bar路M鈦宦. The pressure of CO鈧 gas is 2.0 bar.
02

Apply Henry's Law

Use Henry's law equation, which is \( C = k_H \times P \), where \( C \) is the concentration of the gas in the liquid, \( k_H \) is the Henry's law constant, and \( P \) is the pressure of the gas above the liquid.
03

Calculate the Concentration

Substitute the known values into the Henry's law equation: \( k_H = 29 \ \mathrm{bar} \cdot \mathrm{M}^{-1} \), and \( P = 2.0 \ \mathrm{bar} \). Hence, \( C = 29 \times 2.0 = 58 \ \mathrm{M} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gas Solubility
Gas solubility refers to how much of a gas can dissolve in a liquid. It depends on several factors like temperature, pressure, and the nature of the gas and the liquid. When a gas is in contact with a liquid, some of its molecules will enter the liquid phase. The ability of these gas molecules to stay in the liquid is what we term as solubility. In general, gases dissolve better in liquids at lower temperatures. This is why fizzy drinks remain fizzy when chilled. However, pressure plays a crucial role as well. The more pressure applied, the more gas can be dissolved. Understanding gas solubility is important in fields like chemistry, medicine, and environmental science as it influences how gases interact with surroundings.
Pressure Concentration Relationship
The pressure concentration relationship is a key principle in understanding gas solubility, especially in the context of Henry's Law. Henry's Law provides a direct way to relate the concentration of a dissolved gas in a liquid to the pressure of the gas above that liquid. Mathematically, it's expressed as \( C = k_H \times P \), where \( C \) is the concentration, \( k_H \) is Henry's constant, and \( P \) is the pressure.
  • If the pressure of the gas increases, its concentration in the liquid also increases, assuming a constant Henry's constant.
  • Conversely, if the concentration in the liquid needs to increase, the pressure must also increase.
This relationship is foundational in predicting how a change in conditions, like pressure, affects how well a gas dissolves. It's crucial in industrial applications, where controlling gas dissolution is key, such as in water treatment and beverage carbonation.
CO2 Solubility in Water
Carbon dioxide \((\mathrm{CO}_2)\) is a common gas that dissolves in water, and understanding its solubility is crucial for various applications like carbonated drinks. At a given temperature, Henry's law helps us determine how much \(\mathrm{CO}_2\) can dissolve by using a specific constant.In the original exercise, to find the concentration of \(\mathrm{CO}_2\) in a drink, we used theHenry's law constant of \(29\, \mathrm{bar} \cdot \mathrm{M}^{-1}\) for \(25^{\circ} \mathrm{C}\).
  • This constant is specific to \(\mathrm{CO}_2\) and water, which tells us that for every 1 bar of pressure, 29 moles per liter of \(\mathrm{CO}_2\) can dissolve.
  • With the original pressure of 2.0 bar, we calculated a concentration of 58 M, meaning a significantly high amount of \(\mathrm{CO}_2\) could dissolve, which is typical for carbonated beverages.
This high solubility under pressure is utilized in soft drink bottling, ensuring fizz and flavor are maintained even after opening.

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Most popular questions from this chapter

The vapor pressure of pure water at \(25^{\circ} \mathrm{C}\) is \(23.76\) Torr. Use Raoult's law to estimate the vapor pressure of an aqueous solution at \(25^{\circ} \mathrm{C}\) containing \(20.00\) grams of sucrose, \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}(s)\), dissolved in \(195.0\) grams of water. Also calculate the vapor pressure lowering.

Calculate the vapor pressure of ethanol, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\), over 80 proof \((40.0 \%\) ethanol by volume) vodka at \(19^{\circ} \mathrm{C} .\) The vapor pressure of pure ethanol at \(19^{\circ} \mathrm{C}\) is \(40.0\) Torr. The density of ethanol is \(0.79 \mathrm{~g} \cdot \mathrm{mL}^{-1}\) and the density of water is \(1.00 \mathrm{~g} \cdot \mathrm{mL}^{-1}\).

Of the gases \(\mathrm{N}_{2}(g), \mathrm{O}_{2}(g)\), and \(\mathrm{CO}_{2}(g)\), which has the highest concentration in water at \(25^{\circ} \mathrm{C}\) when each gas has a pressure of \(1.0\) bar?

Calculate the mole fraction of isopropanol, \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHOH}\), in a solution that is \(70.0 \%\) isopropanol and \(30.0 \%\) water by volume. Take the density of water as \(1.00 \mathrm{~g} \cdot \mathrm{cm}^{-3}\) and the density of isopropanol as \(0.785 \mathrm{~g} \cdot \mathrm{cm}^{-3}\)

Calculate the vapor pressure lowering of the following aqueous solutions at \(25^{\circ} \mathrm{C}\left(P_{\mathrm{H}_{2} \mathrm{O}}^{\circ}=0.0317\right.\) bar \():\) (a) \(2.00 \mathrm{~m}\) sucrose, \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}(a q)\) (b) \(2.00 \mathrm{~m} \mathrm{NaCl}(a q)\) (c) \(2.00 \mathrm{~m} \mathrm{CaCl}_{2}(a q)\)

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