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The chemical xylene is used as a solvent and in the synthesis of polyester fibers. Chemical analysis shows that xylene is \(90.50 \%\) carbon and \(9.50 \%\) hydrogen by mass. A \(2.334\) -gram sample of xylene was vaporized in a sealed \(500.0\) -milliliters container at \(100.0^{\circ} \mathrm{C}\), producing a pressure of \(1.346 \mathrm{~atm}\). Use these data to determine the molecular formula of xylene.

Short Answer

Expert verified
The molecular formula of xylene is \( \text{C}_8\text{H}_{10} \).

Step by step solution

01

Convert Volume to Liters

To work with the ideal gas law, we first convert the volume from milliliters to liters. The volume is given as \(500.0\) mL, which is equivalent to \(0.500\) L.
02

Use Ideal Gas Law to Find Moles of Vapor

Use the ideal gas law: \[ PV = nRT \]Where:- \( P = 1.346 \) atm (pressure)- \( V = 0.500 \) L (volume)- \( R = 0.0821 \) L·atm/mol·K (ideal gas constant)- \( T = 373.15 \) K (temperature in Kelvin, converted from \(100.0^{\,\circ} \mathrm{C} \))Rearrange to solve for \( n \) (number of moles):\[ n = \frac{PV}{RT} = \frac{1.346 \times 0.500}{0.0821 \times 373.15} \]Calculate \( n \).
03

Calculate Molar Mass of Xylene

The mass of xylene is \(2.334 \) grams. Using the moles calculated previously:\[ \text{Molar Mass} = \frac{\text{mass}}{\text{moles}} = \frac{2.334}{n} \]Calculate the molar mass.
04

Determine Empirical Formula

Given that xylene is \(90.50\%\) carbon and \(9.50\%\) hydrogen, assume a \(100\) g sample to find moles of each element:- Carbon: \( \frac{90.50}{12.01} \)- Hydrogen: \( \frac{9.50}{1.008} \)Calculate the mole ratio of carbon to hydrogen and simplify to find the empirical formula.
05

Find Molecular Formula

Compare the empirical formula mass to the molar mass from Step 3 to find the ratio:\[ \text{Ratio} = \frac{\text{Molar Mass}}{\text{Empirical Formula Mass}} \]Multiply the subscripts in the empirical formula by this ratio to determine the molecular formula.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The ideal gas law is a fundamental principle that helps relate the physical properties of a gas. It can be expressed with the formula:\[ PV = nRT \]In this equation, \( P \) represents pressure measured in atmospheres, \( V \) stands for the volume in liters, \( n \) refers to the number of moles of gas, \( R \) is the ideal gas constant (0.0821 L·atm/mol·K), and \( T \) is the temperature in Kelvin. The ideal gas law allows us to calculate any one of the variables if the others are known.In the analysis of xylene, we convert all measurements accordingly:- Volume: Convert from milliliters to liters by dividing by 1000.- Temperature: Convert Celsius to Kelvin by adding 273.15.By rearranging the ideal gas law to solve for moles \( n \):\[ n = \frac{PV}{RT} \]we can find the quantity of gas present, which is an essential step for further calculations.
Empirical Formula
An empirical formula represents the simplest whole-number ratio of atoms within a compound. To determine this, we convert the percent composition of each element to moles. For xylene: - Carbon is 90.50% by mass. Divide this by carbon's atomic mass, 12.01 g/mol. - Hydrogen is 9.50% by mass. Divide this by hydrogen's atomic mass, 1.008 g/mol. These calculations give us the number of moles of each element. We then establish the simplest ratio by dividing all values by the smallest one obtained. This simplified ratio forms the empirical formula, giving us a foundational understanding of the compound's composition. For xylene, this ensures we know the basic atomic structure before determining its full molecular formula.
Molar Mass Calculation
Molar mass is an important concept, representing the mass of one mole of a substance. It’s calculated by dividing the mass of the sample by the number of moles.For xylene, we first found moles using the ideal gas law:\[ n = \frac{PV}{RT} \]With the known mass of the sample \( 2.334 \) grams and the calculated moles \( n \), the molar mass can be determined:\[ \text{Molar Mass} = \frac{\text{mass}}{\text{moles}} = \frac{2.334}{n} \]This step is crucial, as it connects the physical mass of the compound with its chemical identity, allowing us to bridge between the empirical formula and the actual structure, the molecular formula.
Percent Composition Analysis
Percent composition analysis involves determining the percentage by mass of each element within a compound. This is crucial for the initial steps of identifying the empirical formula. For example, in xylene: - Carbon forms 90.50% of the compound's weight. - Hydrogen accounts for 9.50% of the weight. By assuming a 100 g sample, these percentages directly translate to mass. From here, we calculate the moles for each element by dividing the mass by the respective atomic weights. This process provides insight into the element proportions, forming the basis for solving both empirical and molecular formulas, highlighting the relationship between the chemical makeup and its atomic components.

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Most popular questions from this chapter

Explain what factors not accounted for by the ideal-gas equation are corrected for by the van der Waals constants \(a\) and \(b\).

Explosions occur when a substance decomposes rapidly with the production of a large volume of gases. When detonated, TNT (trinitrotoluene), decomposes according to the equation $$ \begin{aligned} 2 \mathrm{C}_{7} \mathrm{H}_{5}\left(\mathrm{NO}_{2}\right)_{3}(s) & \rightarrow \\ 2 \mathrm{C}(s)+12 \mathrm{CO}(g)+5 \mathrm{H}_{2}(g)+3 \mathrm{~N}_{2}(g) \end{aligned} $$ What is the total volume of gases produced from \(1.00\) kilogram of TNT at \(0^{\circ} \mathrm{C}\) and \(1.00\) atm? What pressure is produced if the reaction is confined to a 50 -liter container at \(500^{\circ} \mathrm{C}\) ? Assume that you can use the ideal-gas equation.

If the temperature of a gas is doubled, how much is the root-mean-square speed of the molecules comprising the gas increased?

The pressure in a ceramic vessel that contained nitrogen gas dropped from 1850 Torr to 915 Torr in \(30.0\) minutes. When the same vessel was filled with another gas, the pressure dropped from 1850 Torr to 915 Torr in \(54.3\) minutes. Calculate the molecular mass of the second gas, assuming that the gases effuse from the container.

While working after school in his high school chemistry laboratory, Joel Hildebrand (Chapter 12 Frontispiece) showed that the formula for a certain oxide of nitrogen published in a college chemistry textbook as \(\mathrm{N}_{2} \mathrm{O}_{2}\) was wrong. He did so by demonstrating that two volumes of the oxide in question combined with one volume of oxygen to form one volume of the brown gas, dinitrogen tetroxide. Use Gay-Lussac's law of combining volumes to identify the correct formula for this oxide of nitrogen.

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