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Classify each of the following as strong electrolytes, weak electrolytes, or nonelectrolytes in aqueous solution: HI, \(\mathrm{NH}_{4} \mathrm{Br}, \mathrm{CH}_{3} \mathrm{COOH}\) (acetic acid), KOH, \(\mathrm{CH}_{3} \mathrm{OH}\) (methanol).

Short Answer

Expert verified
HI, NH4Br, and KOH are strong electrolytes; CH3COOH is a weak electrolyte; CH3OH is a nonelectrolyte.

Step by step solution

01

Define Electrolytes and Nonelectrolytes

Strong electrolytes completely dissociate into ions in an aqueous solution, weak electrolytes partially dissociate, and nonelectrolytes do not dissociate into ions at all.
02

Classify HI

Hydroiodic acid (HI) is a strong acid and hence a strong electrolyte because it completely ionizes in water to form H鈦 and I鈦 ions.
03

Classify NH4Br

Ammonium bromide ( NH_{4}Br), a soluble ionic compound, completely dissociates into NH_{4}^{+} and Br^{-} ions in aqueous solution, making it a strong electrolyte.
04

Classify CH3COOH

Acetic acid ( CH_{3}COOH) is a weak electrolyte as it partially dissociates in water, forming CH_{3}COO^{-} and H^{+} ions.
05

Classify KOH

Potassium hydroxide (KOH) is a strong base and a strong electrolyte, as it dissociates completely in water to K^{+} and OH^{-} ions.
06

Classify CH3OH

Methanol ( CH_{3}OH) is an organic compound that does not ionize in water, so it is a nonelectrolyte.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Strong Electrolytes
Strong electrolytes are substances that completely dissociate into ions when dissolved in water. This means that in an aqueous solution, these compounds break apart into their constituent ions, leading to excellent electrical conductivity.
For example, hydroiodic acid (HI) is a strong electrolyte. In water, it dissociates entirely into hydrogen ions (\( ext{H}^+ \) ) and iodide ions (\( ext{I}^- \) ). Similarly, potassium hydroxide (KOH) is a strong base that dissociates completely into potassium ions (\( ext{K}^+ \) ) and hydroxide ions (\( ext{OH}^- \) ).
Ammonium bromide (\( ext{NH}_4 ext{Br} \) ) is another strong electrolyte, fully dissociating into ammonium (\( ext{NH}_4^+ \) ) and bromide ions (\( ext{Br}^- \) ) in solution. Strong electrolytes are critical in many chemical reactions and are frequently encountered in industrial and laboratory settings.
  • They contribute to the strong conductivity of solutions.
  • They are often used in various applications, from batteries to electrochemical reactions.
Weak Electrolytes
Weak electrolytes only partially dissociate in aqueous solutions. This results in a mixture of dissolved ions and un-ionized molecules.
The partial dissociation leads to relatively low electrical conductivity in comparison to strong electrolytes. Acetic acid (\( ext{CH}_3 ext{COOH} \) ) is a classic example of a weak electrolyte. Only a small fraction of acetic acid molecules dissociate into acetate ions (\( ext{CH}_3 ext{COO}^- \) ) and hydrogen ions (\( ext{H}^+ \) ) when dissolved in water.
Despite their limited ionization, weak electrolytes are significant in many fields, including environmental sciences and pharmacology, due to their equilibrium between the ionized and unionized forms.
  • They are less efficient at conducting electricity compared to strong electrolytes.
  • They establish an equilibrium state in solutions, important for buffer systems.
Nonelectrolytes
Nonelectrolytes are substances that do not dissociate into ions in an aqueous solution. These compounds, when dissolved in water, remain intact as neutral molecules. As a result, nonelectrolytes do not conduct electricity because there are no charged particles available to carry an electrical current.
Methanol (\( ext{CH}_3 ext{OH} \) ) is a good example of a nonelectrolyte. When methanol is dissolved in water, it stays as whole \( ext{CH}_3 ext{OH} \) molecules without forming ions.
Nonelectrolytes are widely used in various applications where electrical conductivity is not required or desired.
  • They are used in making solutions that should not conduct electricity, for instance in cosmetics or other consumer products.
  • They are integral in organic chemistry research and processes.

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Most popular questions from this chapter

Hydrogen peroxide can be prepared by the reaction of barium peroxide with sulfuric acid according to the equation $$ \mathrm{BaO}_{2}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \rightarrow \mathrm{BaSO}_{4}(s)+\mathrm{H}_{2} \mathrm{O}_{2}(a q) $$ How many milliliters of \(3.75 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}(a q)\) are required to react completely with \(17.6\) grams of \(\mathrm{BaO}_{2}(s) ?\)

What volume of \(0.865 \mathrm{M} \mathrm{CaCl}_{2}(a q)\) is required to precipitate all the \(\mathrm{Ag}^{+}(a q)\) from \(35.0\) milliliters of \(0.500 \mathrm{M} \mathrm{AgNO}_{3}(a q) ?\) How many grams of \(\mathrm{AgCl}(s)\) will precipitate?

To test the purity of \(\mathrm{NaOH}(s)\) after its manufacture, \(0.400\) grams are dissolved in enough water to make \(100.0\) milliliters of solution. The solution is titrated with \(0.100 \mathrm{M}\) HCl \((a q)\) to determine the concentration of \(\mathrm{NaOH}(a q) .\) It is found that \(25.0\) milliliters of \(\mathrm{NaOH}(a q)\) is neutralized by \(23.2\) milliliters of HCl \((a q)\). Calculate the purity of the solid \(\mathrm{NaOH}(s)\). What assumption do you have to make?

How many grams of a \(\mathrm{CaCl}_{2}(a q)\) solution that is \(14 \% \mathrm{CaCl}_{2}\) by mass contains \(3.25\) grams of \(\mathrm{CaCl}_{2}(s) ?\)

A sample of KOH \((a q)\) was found to contain \(8.75 \%\) water by mass. How many grams of this material are required to make 500 milliliters of a \(6.00 \mathrm{M}\) \(\mathrm{KOH}(a q)\) solution?

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