/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 Arrange the following quantities... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Arrange the following quantities in order of increasing volume: (a) \(10 \mathrm{~L}\) (b) \(100 \mathrm{~mL}\) (c) 0.10 ML (d) \(1.0 \times 10^{3} \mu \mathrm{L}\) (e) \(20 \mathrm{cL}\) (f) \(1.0 \times 10^{4} \mathrm{~nL}\)

Short Answer

Expert verified
The increasing order is: f, d, b, e, a, c.

Step by step solution

01

Convert All Quantities to Liters

To compare the volumes effectively, convert all quantities to liters (L).- **(a)** Already in liters: \(10 \mathrm{~L}\).- **(b)** Milliliters to liters: \(100 \mathrm{~mL} = 0.1 \mathrm{~L}\).- **(c)** Megaliters to liters: \(0.10 \mathrm{~ML} = 100,000 \mathrm{~L}\).- **(d)** Microliters to liters: \(1.0 \times 10^{3} \mu \mathrm{L} = 0.001 \mathrm{~L}\).- **(e)** Centiliters to liters: \(20 \mathrm{~cL} = 0.2 \mathrm{~L}\).- **(f)** Nanoliters to liters: \(1.0 \times 10^{4} \mathrm{~nL} = 0.00001 \mathrm{~L}\).
02

List the Volumes in Liters

Write each converted volume to make it easy to compare:- (a) \(10 \mathrm{~L}\)- (b) \(0.1 \mathrm{~L}\)- (c) \(100,000 \mathrm{~L}\)- (d) \(0.001 \mathrm{~L}\)- (e) \(0.2 \mathrm{~L}\)- (f) \(0.00001 \mathrm{~L}\)
03

Arrange Volumes in Increasing Order

Now, sort the volumes from smallest to largest:1. (f) \(0.00001 \mathrm{~L}\)2. (d) \(0.001 \mathrm{~L}\)3. (b) \(0.1 \mathrm{~L}\)4. (e) \(0.2 \mathrm{~L}\)5. (a) \(10 \mathrm{~L}\)6. (c) \(100,000 \mathrm{~L}\)
04

Present the Original Order

Reorder the original quantities (a-f) based on the arranged order above:1. (f) \(1.0 \times 10^{4} \mathrm{~nL}\)2. (d) \(1.0 \times 10^{3} \mu \mathrm{L}\)3. (b) \(100 \mathrm{~mL}\)4. (e) \(20 \mathrm{cL}\)5. (a) \(10 \mathrm{~L}\)6. (c) 0.10 ML

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Units of Measurement
Units of measurement provide a standard to quantify physical quantities like volume, mass, and length. This standardization is crucial because it allows for consistency in communication and comparison. For volume, we have a variety of units: from liters, which are common in everyday contexts, to milliliters, centiliters, microliters, megaliters, and nanoliters used in more specific scientific settings. Each unit of measurement is based on multiples of ten, making conversion between them quite straightforward. When you work with volume measurements, it's important to understand the prefixes:
  • "milli" means one-thousandth ( 1 ml = 0.001 L).
  • "centi" stands for one-hundredth (1 cL = 0.01 L).
  • "micro" means one-millionth (1 µL = 0.000001 L).
  • "mega" indicates a million times bigger (1 ML = 1,000,000 L).
  • "nano" implies one-billionth (1 nL = 0.000000001 L).
Understanding these relationships allows for easier conversion and consistency in measurements across different contexts.
Metric System
The metric system is a globally recognized system used to measure quantities like volume, length, and mass. It's structured around base units and prefixes in powers of ten, making conversions consistent and simple. In the context of volume, the metric system's base unit is the liter (L):
  • Larger quantities use prefixes like "mega," implying one million (e.g., megaliter).
  • Smaller quantities use micro, milli, centi, and nano, indicating subdivisions of the base unit (e.g., milliliter, microliter, nanoliter).
Using this system offers great flexibility in expressing various volumes without confusion. Its advantage is the ease of converting between different scales by simply moving the decimal point. For instance, converting 1000 milliliters to liters is straightforward since 1 mL = 0.001 L, so 1000 mL equates to 1 L. This systematic approach is the metric system's key strength, ensuring that anyone familiar with the basics can calculate and convert across various units.
Measurement Comparison
Comparing measurements is an essential skill allowing one to determine relationships between different quantities. When it comes to comparing volumes, the first step is to convert all measurements to the same unit. This process aligns the values on a common scale, enabling direct evaluation. From our example, given volumes include different units such as liters, milliliters, and nanoliters. To arrange them in increasing order, we converted each to liters. This conversion simplifies the task, allowing an easy line-up in size. Once all values are expressed in the same unit, look at the decimal places:
  • The smallest value appears first.
  • Subsequent values increase in size.
In this linear arrangement, determining the largest or smallest and comparing relative sizes becomes straightforward. Uniform units make comparisons intuitive, so standard conversions are always an advantageous step in analysis.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Horsepower is a unit of power; one horsepower\((1 \mathrm{hp})\) is equivalent to 745 watts. The world record for climbing a 25 -feet rope was set by Garvin Smith in Los Angeles in 1947 , when he climbed the 25 feet in \(4.7\) seconds. Assuming that \(\mathrm{Mr}\). Smith has a mass of \(65 \mathrm{~kg}\), calculate the average power (in both watts and horsepower) that he generated during his climb.

Aluminum has a density of \(2.70 \mathrm{~g} \cdot \mathrm{cm}^{-5}\). If a sheet of aluminum foil measuring \(20.5\) centimeters in length and \(15.2\) centimeters in width has a mass of \(1.683\) grams, what is the thickness of the foil in millimeters?

A physics student measures the speed of sound in air as \(352 \mathrm{~m} \cdot \mathrm{s}^{-1}\). A reference source lists the speed as being \(344 \mathrm{~m} \cdot \mathrm{s}^{-1}\). Calculate the percentage error in the student's experimental result.

The U.S. penny was originally minted entirely of copper. However, after the year 1857 the U.S. penny was made of a variety of metals because of the high cost of copper. Since 1982 pennies have been made of zinc plated with a thin layer of copper. The modern penny weighs \(2.500\) grams, has a diameter of \(19.05\) millimeters, and an average thickness of \(1.224\) millimeters. Given that the density of copper and zinc are \(8.96 \mathrm{~g} \cdot \mathrm{cm}^{-3}\) and \(7.13 \mathrm{~g} \cdot \mathrm{cm}^{-3}\), respectively, determine the percentage by mass of copper in a modern penny.

If a rock climber accidentally drops a 56 -gram piton from a height of 375 meters, what would its speed be before striking the ground? Ignore the effects of air resistance.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.