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Write the electron configurations of \(\mathrm{Sn}\) and \(\mathrm{Sn}^{2+}\).

Short Answer

Expert verified
Sn: [Kr] 5s虏 4d鹿鈦 5p虏; Sn虏鈦: [Kr] 5s虏 4d鹿鈦

Step by step solution

01

Determine Total Electrons for Sn

Start by identifying the atomic number of tin (Sn), which is 50. This means a neutral tin atom has 50 electrons.
02

Write Electron Configuration for Sn

Use the Aufbau principle to fill orbitals in the sequence of increasing energy. The configuration for 50 electrons is as follows:\[1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^6 \, 4s^2 \, 3d^{10} \, 4p^6 \, 5s^2 \, 4d^{10} \, 5p^2\]
03

Determine Total Electrons for Sn^{2+}

The Sn^{2+} ion has lost 2 electrons. Therefore, it will have 48 electrons.
04

Write Electron Configuration for Sn^{2+}

Remove two electrons from the highest energy level orbital in the electron configuration of neutral Sn. Thus, remove 2 electrons from the 5p orbital.The configuration for Sn^{2+} is:\[1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^6 \, 4s^2 \, 3d^{10} \, 4p^6 \, 5s^2 \, 4d^{10}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sn atom
The Sn atom, which stands for tin, is an element found in group 14 of the periodic table. Tin's atomic number is 50, indicating it has 50 protons in its nucleus and, when neutral, an equal number of electrons. Sn has similarities with other elements in its group, such as carbon and lead, but differs in its atomic mass and electron configuration.
When discussing the electron configuration of Sn, it is crucial to understand it as an arrangement of electrons around an atom's nucleus. The electron configuration not only tells us about the electrons in various energy levels but also reveals information about the reactivity and bonding characteristics of the element.
For the Sn atom, the electron configuration is given as \[1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^6 \, 4s^2 \, 3d^{10} \, 4p^6 \, 5s^2 \, 4d^{10} \, 5p^2\].
This notation shows that the electrons are filled into subshells starting from the lowest energy level to the highest following principles like Aufbau's principle.
Sn^{2+} ion
The Sn^{2+} ion is formed when a tin atom loses two electrons. In this ionized form, the tin atom has a net positive charge of two, usually referred to as tin(II).
The process of ionization affects an atom鈥檚 electron configuration, as electrons are removed from the highest energy orbitals. In the case of Sn, electrons are removed from the 5p orbital. After ionization, the electron configuration for \( ext{Sn}^{2+}\) becomes \[1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^6 \, 4s^2 \, 3d^{10} \, 4p^6 \, 5s^2 \, 4d^{10}\].
This results in the Sn^{2+} ion having a stable electron configuration that explains some of the unique chemical behavior of divalent tin, such as its tendency to form specific covalent bonds and compounds in reactions.
Aufbau principle
The Aufbau principle is a fundamental guideline used in chemistry to understand the electron configuration of atoms. The term 'Aufbau' in German means "building up," which accurately describes this principle as it dictates the way electrons are added to an atom.
According to the Aufbau principle:
  • Electrons fill the lowest available energy orbitals first before moving to higher energy levels.
  • The sequence of filling is based on increasing energy levels and subshells (s, p, d, f).
  • Overlap and mixing of energy levels can occur, such as 4s being filled before 3d.
In practice, the Aufbau principle is followed to determine the electron configurations of elements like Sn. This method provides a systematic way to fill orbitals, resulting in stable configurations and predicting the chemical characteristics.
Orbital filling
Orbital filling is the process of adding electrons into orbitals according to prescribed rules and energy levels. It follows a systematic pattern known as the electron configuration, where specific rules dictate the order of filling.
Some important rules include:
  • Pauli's Exclusion Principle: States that no two electrons can occupy the same quantum state simultaneously within an atom.
  • Hund's Rule: Within a subshell, electrons occupy all the orbitals singly before any orbital is doubly filled with electrons of opposite spins.
For atoms like Sn, electrons start filling from the 1s orbital and ascend sequentially through each energy level, filling subshells in a specific sequence like 2p, 3s, 3p, etc., until all 50 electrons are placed. This structured filling leads to a complete and stable electron configuration.
Understanding orbital filling helps explain the electron arrangements and stability of both neutral and ionized atoms, such as the Sn^{2+} ion, by predicting how changes in electron configuration can alter chemical behavior and interactions.

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Most popular questions from this chapter

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When atoms of the hypothetical element \(\mathrm{X}\) are placed together, they rapidly undergo reaction to form the \(\mathrm{X}_{2}\) molecule: \(\mathrm{X}(g)+\mathrm{X}(g) \longrightarrow \mathrm{X}_{2}(g)\) A. Would you predict that this reaction is exothermic or endothermic? Explain. Is the bond enthalpy of \(\mathrm{X}_{2}\) a positive or a negative B. Is the bond enthalpy of \(\mathrm{X}_{2}\) a positive or a negative quantity? Why? C. Suppose \(\Delta H\) for the reaction is \(-500 \mathrm{~kJ} / \mathrm{mol}\). Estimate the bond enthalpy of the \(\mathrm{X}_{2}\) molecule. D. Another hypothetical molecular compound, \(\mathrm{Y}_{2}(g)\) has a bond enthalpy of \(750 \mathrm{~kJ} / \mathrm{mol}\), and the molecular compound \(\mathrm{XY}(g)\) has a bond enthalpy of \(1500 \mathrm{~kJ} / \mathrm{mol}\). Using bond enthalpy information, calculate \(\Delta H\) for the following reaction. $$\mathrm{X}_{2}(g)+\mathrm{Y}_{2}(g) \longrightarrow 2 \mathrm{XY}(g)$$ E, Given the following information, as well as the information previously presented, predict whether or not the hypothetical ionic compound \(\mathrm{AX}\) is likely to form. In this compound, A forms the \(\mathrm{A}^{+}\) cation, and \(\mathrm{X}\) forms the \(\mathrm{X}^{-}\) anion. Be sure to justify your answer. Reaction: \(\mathrm{A}(g)+\frac{1}{2} \mathrm{X}_{2}(g) \longrightarrow \mathrm{AX}(s)\) The first ionization energy of \(\mathrm{A}(g)\) is \(400 \mathrm{~kJ} / \mathrm{mol}\). The electron affinity of \(\mathrm{X}(g)\) is \(525 \mathrm{~kJ} / \mathrm{mol}\). The lattice energy of \(\mathrm{AX}(s)\) is \(100 \mathrm{~kJ} / \mathrm{mol}\). F. If you predicted that no ionic compound would form from the reaction in Part e, what minimum amount of \(\mathrm{AX}(s)\) lattice energy might lead to compound formation?

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