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Colorless nitric oxide, NO, combines with oxygen to form nitrogen dioxide, \(\mathrm{NO}_{2},\) a brown gas. $$ 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{NO}_{2}(g) ; \Delta H=-114 \mathrm{~kJ} $$ What is the enthalpy change per gram of nitric oxide?

Short Answer

Expert verified
The enthalpy change per gram of NO is \(-1.9\ \text{kJ/g}\).

Step by step solution

01

Calculate the Molar Mass of NO

First, we need to determine the molar mass of nitric oxide (NO). The atomic masses are approximately 14.01 g/mol for nitrogen (N) and 16.00 g/mol for oxygen (O). Adding these gives the molar mass of NO: \(14.01 + 16.00 = 30.01\ g/mol\).
02

Determine Enthalpy Change Per Mole of NO

The balanced chemical equation shows that the reaction releases \(-114\) kJ of energy per 2 moles of NO. Therefore, the enthalpy change per mole of NO can be calculated by dividing the total enthalpy change by 2: \[\Delta H = \frac{-114\ \text{kJ}}{2\ \text{moles of NO}} = -57\ \text{kJ/mol NO}.\]
03

Calculate Enthalpy Change Per Gram of NO

Finally, use the molar mass of NO to find the enthalpy change per gram. Since there are 30.01 grams in a mole of NO, divide the enthalpy change per mole by the molar mass: \[\Delta H = \frac{-57\ \text{kJ/mol}}{30.01\ \text{g/mol}} = -1.9\ \text{kJ/g}.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nitric Oxide
Nitric oxide, often abbreviated as NO, is a colorless gas under normal conditions. It plays a significant role both in biological systems and in the atmosphere.
Nitric oxide is produced naturally by the lightning strike process and is also emitted from automobile engines and power stations. It contributes to the formation of smog and acid rain when reacting with other compounds.
One interesting feature of nitric oxide is that it acts as a signaling molecule in the human body and plays a vital role in various physiological processes, including vasodilation, where blood vessels widen.
NO's simple molecular structure consists of one nitrogen atom and one oxygen atom. Understanding its role in environmental chemistry and physiology is important for grasping its broader implications.
Molar Mass
In chemistry, the concept of molar mass is critical, especially when you need to calculate how much of a substance is involved in a reaction. Molar mass refers to the weight of one mole of a given substance.
It's typically expressed in grams per mole (g/mol) and can be calculated using the atomic masses of the elements involved.
For nitric oxide, NO, the molar mass is calculated by adding the atomic mass of nitrogen (approximately 14.01 g/mol) to that of oxygen (approximately 16.00 g/mol). Adding these values together yields a molar mass for NO of 30.01 g/mol.
Molar mass is a fundamental concept not only for understanding chemical equations but also for converting between moles and grams in practical chemistry scenarios. It helps to quantify the reactants and products involved in chemical reactions accurately.
Chemical Reaction
Chemical reactions describe how substances interact to form new products. These interactions involve the breaking and forming of chemical bonds.
In the case of nitric oxide, NO, combining with oxygen, Oeue, to form nitrogen dioxide, NOdueue, is a typical example of a chemical reaction.
The balanced chemical equation for this process is:\[2 \, \text{NO}(g) + \text{O}_2(g) \rightarrow 2 \, \text{NO}_2(g)\]This equation shows the stoichiometry of the reaction—how many moles of each reactant are needed and how many moles of product are formed.
The enthalpy change of the reaction, denoted by \(\Delta H\), tells us about the energy change that accompanies the reaction. In this reaction, \(\Delta H = -114 \, \text{kJ}\), indicating that it releases energy, making it exothermic. Understanding the process of a chemical reaction helps in grasping how substances change and how energy is involved, which is crucial for fields ranging from industrial chemistry to biology and environmental science.

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Most popular questions from this chapter

When solid iron burns in oxygen gas (at constant pressure) to produce \(\mathrm{Fe}_{2} \mathrm{O}_{3}(s), 1651 \mathrm{~kJ}\) of heat is released for every \(4 \mathrm{~mol}\) of iron burned. How much heat is released when \(10.3 \mathrm{~g} \mathrm{Fe}_{2} \mathrm{O}_{3}(s)\) is produced (at constant pressure)? What additional information would you need to calculate the heat released to produce this much \(\mathrm{Fe}_{2} \mathrm{O}_{3}(s)\) if you burned iron in ozone gas, \(\mathrm{O}_{3}(g)\), instead of \(\mathrm{O}_{2}(g)\) ?

A rebreathing gas mask contains potassium superoxide, \(\mathrm{KO}_{2}\), which reacts with moisture in the breath to give oxygen. $$ 4 \mathrm{KO}_{2}(s)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 4 \mathrm{KOH}(s)+3 \mathrm{O}_{2}(g) $$ Estimate the grams of potassium superoxide required to supply a person's oxygen needs for one hour. Assume a person requires \(1.00 \times 10^{2} \mathrm{kcal}\) of energy for this time period. Further assume that this energy can be equated to the heat of combustion of a quantity of glucose, \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6},\) to \(\mathrm{CO}_{2}(g)\) and \(\mathrm{H}_{2} \mathrm{O}(l)\). From the amount of glucose required to give \(1.00 \times 10^{2} \mathrm{kcal}\) of heat, calculate the amount of oxygen consumed and hence the amount of \(\mathrm{KO}_{2}\) required. The \(\Delta H_{f}^{\circ}\) for glucose \((s)\) is \(-1273 \mathrm{~kJ} / \mathrm{mol}\).

A \(29.1-\mathrm{mL}\) sample of \(1.05 \mathrm{M} \mathrm{KOH}\) is mixed with \(20.9 \mathrm{~mL}\) of \(1.07 M \mathrm{HBr}\) in a coffee-cup calorimeter (see Section 6.6 of your text for a description of a coffee-cup calorimeter). The enthalpy of the reaction, written with the lowest whole-number coefficients, is \(-55.8 \mathrm{~kJ}\). Both solutions are at \(21.8^{\circ} \mathrm{C}\) prior to mixing and reacting. What is the final temperature of the reaction mixture? When solving this problem, assume that no heat is lost from the calorimeter to the surroundings, the density of all solutions is \(1.00 \mathrm{~g} / \mathrm{mL},\) and volumes are additive.

Carbon disulfide burns in air, producing carbon dioxide and sulfur dioxide. $$ \mathrm{CS}_{2}(l)+3 \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{SO}_{2}(g) ; \Delta H=-1077 \mathrm{~kJ} $$ What is \(\Delta H\) for the following equation? $$ \frac{1}{2} \mathrm{CO}_{2}(g)+\mathrm{SO}_{2}(g) \longrightarrow \frac{1}{2} \mathrm{CS}_{2}(l)+\frac{3}{2} \mathrm{O}_{2}(g) $$

Chlorine dioxide, \(\mathrm{ClO}_{2},\) is a reddish yellow gas used in bleaching paper pulp. The average speed of a \(\mathrm{ClO}_{2}\) molecule at \(25^{\circ} \mathrm{C}\) is \(306 \mathrm{~m} / \mathrm{s}\). What is the kinetic energy (in joules) of a \(\mathrm{ClO}_{2}\) molecule moving at this speed?

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