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Give an example of a neutralization reaction. Label the acid, base, and salt.

Short Answer

Expert verified
HCl (acid) + NaOH (base) 鈫 NaCl (salt) + H鈧侽.

Step by step solution

01

Identify the Acid

A neutralization reaction involves an acid and a base reacting to form water and a salt. We'll use hydrochloric acid (HCl) as our acid. HCl is a strong acid that fully dissociates in water to produce hydrogen ions (H鈦) and chloride ions (Cl鈦).
02

Identify the Base

Next, we'll choose sodium hydroxide (NaOH) as the base. Sodium hydroxide is a strong base that dissociates in water to provide hydroxide ions (OH鈦) and sodium ions (Na鈦).
03

Write the Chemical Equation

The chemical equation for the reaction of hydrochloric acid with sodium hydroxide is: \[ \text{HCl}_{(aq)} + \text{NaOH}_{(aq)} \rightarrow \text{NaCl}_{(aq)} + \text{H}_2\text{O}_{(l)} \]In this equation, HCl and NaOH react to form NaCl and water. The reaction is as follows:- \( \text{H}^+ + \text{Cl}^- + \text{Na}^+ + \text{OH}^- \rightarrow \text{Na}^+ + \text{Cl}^- + \text{H}_2\text{O} \)The sodium and chloride ions are spectator ions, and the key reaction is the formation of water.
04

Identify the Products

In this reaction, the first product is water (H鈧侽), which forms from the combination of hydrogen ions (H鈦) from the acid and hydroxide ions (OH鈦) from the base. The second product is sodium chloride (NaCl), the salt, which forms from the cations (Na鈦) and anions (Cl鈦).
05

Label the Components

- Acid: Hydrochloric acid (HCl) - Base: Sodium hydroxide (NaOH) - Salt: Sodium chloride (NaCl) The neutralization reaction leads to the formation of water and the soluble salt NaCl.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid-Base Reaction
An acid-base reaction, commonly known as neutralization, takes place when an acid and a base react to form water and a salt. Essential components of such a reaction include:
  • Acids: Substances that donate protons (H+ ions) in solution. They typically taste sour and can turn blue litmus paper red.
  • Bases: Substances that accept protons or donate hydroxide ions (OH鈦). They are usually slippery to the touch and turn red litmus paper blue.
In this process, the hydrogen ions from the acid combine with the hydroxide ions from the base to form water. Additionally, other ions from the acid and base join to form a salt. The overall result is a balanced reaction and typically a neutral pH. Understanding this concept is crucial, as it demonstrates how substances can interact to produce neutral solutions, often with practical applications in everyday life.
Strong Acid
Strong acids are a specific category within acids that completely dissociate in water. This means they release all of their hydrogen ions into the solution, resulting in a high concentration of H+ ions. Some common strong acids include:
  • Hydrochloric acid (HCl)
  • Sulfuric acid (H鈧係O鈧)
  • Nitric acid (HNO鈧)
In the given example, hydrochloric acid (HCl) plays the role of the strong acid. When HCl is dissolved in water, it fully breaks down into hydrogen ions (H+) and chloride ions (Cl鈦). This complete dissociation is key to its strength, making it very effective in driving neutralization reactions. Due to their full dissociation, strong acids tend to have a significantly lower pH value, typically less than 1.
Strong Base
Much like strong acids, a strong base is characterized by its complete dissociation in water. Strong bases fully release hydroxide ions (OH鈦) when dissolved, drastically increasing the solution's basicity. Notable strong bases include:
  • Sodium hydroxide (NaOH)
  • Potassium hydroxide (KOH)
  • Calcium hydroxide (Ca(OH)鈧)
In our example, sodium hydroxide (NaOH) is the chosen strong base. It dissociates entirely in water, yielding sodium ions (Na+) and hydroxide ions (OH鈦). The presence of these hydroxide ions increases the solution's ability to neutralize acids efficiently. As these ions fully dissociate, the pH of strong base solutions tends to be very high, typically around 13 to 14.
Formation of Water
One of the central products of a neutralization reaction is water. This occurs when hydrogen ions (H鈦) from the acid combine with hydroxide ions (OH鈦) from the base:\[\text{H}^+ + \text{OH}^- \rightarrow \text{H}_2\text{O}\]This combination is key to neutralizing the acid and base, producing a stable water molecule.
The formation of water marks the end of the neutralization process and is a significant reason why the reaction results in a substance with a neutral pH. Water is considered neutral because it does not donate additional hydroxide ions or hydrogen ions once formed, maintaining stability in the solution. The generation of water from these ions highlights the balanced and efficient nature of neutralization reactions.
Spectator Ions
Spectator ions are ions that exist in the same form on both the reactant and product sides of a chemical equation. They essentially "watch" the reaction happen without directly participating in the chemical change. In neutralization reactions, they help balance the overall equation but do not affect the formation of water.
For example, consider the reaction between hydrochloric acid and sodium hydroxide:
  • Sodium ions (Na鈦) and chloride ions (Cl鈦) are spectator ions.
During this reaction:\[\text{H}^+ + \text{Cl}^- + \text{Na}^+ + \text{OH}^- \rightarrow \text{Na}^+ + \text{Cl}^- + \text{H}_2\text{O}\]The Na+ and Cl鈦 ions remain unchanged throughout the process and do not contribute to the water formation. Recognizing spectator ions helps simplify the reaction mechanism, allowing us to focus on the molecules that truly undergo chemical change.

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Most popular questions from this chapter

Mercury(II) nitrate is treated with hydrogen sulfide, \(\mathrm{H}_{2} \mathrm{~S},\) forming a precipitate and a solution. Write the molecular equation and the net ionic equation for the reaction. An acid is formed; is it strong or weak? Name each of the products. If \(65.65 \mathrm{~g}\) of mercury(II) nitrate and \(4.26 \mathrm{~g}\) of hydrogen sulfide are mixed in \(395.0 \mathrm{~g}\) of water to form \(54.16 \mathrm{~g}\) of precipitate, what is the mass of the solution after the reaction?

Obtain the oxidation number for the element noted in each of the following. (a) \(\mathbf{N}\) in \(\mathrm{N}_{2}\) (b) \(\mathrm{Cr}\) in \(\mathrm{CrO}_{4}^{2-}\) (c) \(\mathrm{Zn}\) in \(\mathrm{Zn}(\mathrm{OH})_{4}^{2-}\) (d) As in \(\mathrm{H}_{2} \mathrm{AsO}_{3}^{-}\)

You have a sample of a rat poison whose active ingredient is thallium(I) sulfate. You analyze this sample for the mass percentage of active ingredient by adding potassium iodide to precipitate yellow thallium(I) iodide. If the sample of rat poison weighed \(759.0 \mathrm{mg}\) and you obtained \(212.2 \mathrm{mg}\) of the dry precipitate, what is the mass percentage of the thallium(I) sulfate in the rat poison?

Decide whether a reaction occurs for each of the following. If it does not, write \(N R\) after the arrow. If it does, write the balanced molecular equation; then write the net ionic eauation. (a) \(\mathrm{Al}(\mathrm{OH})_{3}+\mathrm{HNO}_{3} \longrightarrow\) (b) \(\mathrm{NaBr}+\mathrm{HClO}_{4} \longrightarrow\) (c) \(\mathrm{CaCl}_{2}+\mathrm{NaNO}_{3} \longrightarrow\) (d) \(\mathrm{MgSO}_{4}+\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2} \longrightarrow\)

How many milliliters of \(0.126 \mathrm{M} \mathrm{HClO}_{4}\) (perchloric acid) are required to give \(0.150 \mathrm{~mol} \mathrm{HClO}_{4} ?\)

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