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Aluminum hydroxide is an amphoteric substance. What does this mean? Write equations to illustrate.

Short Answer

Expert verified
Aluminum hydroxide can react as both an acid and a base, demonstrating its amphoteric nature.

Step by step solution

01

Define Amphoteric Substances

An amphoteric substance is one that can act as both an acid and a base, depending on the chemical environment. This dual ability allows it to undergo different types of reactions.
02

Write the acidic reaction equation

When aluminum hydroxide, \( \text{Al(OH)}_3 \), reacts with a strong base like sodium hydroxide (\( \text{NaOH} \)), it acts as an acid. The reaction is as follows: \[ \text{Al(OH)}_3 + \text{OH}^- \rightarrow \text{Al(OH)}_4^- \] Here, aluminum hydroxide donates a proton, acting in an acidic manner.
03

Write the basic reaction equation

When aluminum hydroxide reacts with a strong acid such as hydrochloric acid (\( \text{HCl} \)), it acts as a base. The reaction proceeds as follows: \[ \text{Al(OH)}_3 + 3\text{HCl} \rightarrow \text{AlCl}_3 + 3\text{H}_2\text{O} \] In this reaction, aluminum hydroxide accepts protons from the acid, displaying basic behavior.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid-Base Chemistry
Acid-base chemistry is a fascinating area of chemistry that explores how substances can react with each other through proton exchange. In simpler terms, it deals with the concepts of acids, which can donate protons (or hydrogen ions, \( H^+ \)), and bases, which can accept them.
An intriguing aspect of this chemistry is the behavior of amphoteric substances. These special substances, such as aluminum hydroxide, can act as either an acid or a base, depending on their reacting partner. This dual behavior is an essential concept that helps explain a variety of chemical reactions.
You can think of amphoteric substances as versatile participants in chemical processes. They can adapt based on the environment and react accordingly. Understanding this adaptability is key to mastering acid-base chemistry.
Aluminum Hydroxide Reactions
Aluminum hydroxide, \( \text{Al(OH)}_3 \), showcases its amphoteric nature through its interactions with acids and bases. Let's explore these reactions to understand its behavior.
When it comes in contact with a strong base, such as sodium hydroxide (\( \text{NaOH} \)), aluminum hydroxide acts as an acid. In this scenario, aluminum hydroxide donates a proton, thereby transforming into \( \text{Al(OH)}_4^- \). The reaction equation looks like this:
  • \( \text{Al(OH)}_3 + \text{OH}^- \rightarrow \text{Al(OH)}_4^- \)
On the flip side, when aluminum hydroxide encounters a strong acid, such as hydrochloric acid (\( \text{HCl} \)), it behaves as a base. Here, the aluminum hydroxide accepts protons from the acid, resulting in the formation of aluminum chloride and water, as shown in the following equation:
  • \( \text{Al(OH)}_3 + 3\text{HCl} \rightarrow \text{AlCl}_3 + 3\text{H}_2\text{O} \)
This versatility showcases why amphoteric substances like aluminum hydroxide are crucial in chemical reactions and industrial applications.
Proton Transfer
In the world of acid-base chemistry, proton transfer is a fundamental mechanism. It is the process by which a proton (\( H^+ \)) is transferred from one molecule to another. This process is at the heart of what defines acids and bases.
- **Acids** tend to donate protons, thus lowering the concentration of \( H^+ \) ions in the environment.
- **Bases** receive these protons, thereby playing the role of proton acceptors.
In the reactions of aluminum hydroxide mentioned previously, proton transfer occurs distinctly:
- When acting as an acid, aluminum hydroxide donates a proton to the base (\( \text{OH}^- \)), showcasing a classic proton donation reaction.
  • This leads to the formation of \( \text{Al(OH)}_4^- \).
- Conversely, when aluminum hydroxide acts as a base, it accepts protons from the acidic \( \text{HCl} \), thereby illustrating proton acceptance.
  • This results in the formation of \( \text{AlCl}_3 \) and water.
Understanding proton transfer helps demystify complex chemical interactions and serves as a cornerstone for students tackling more advanced topics in chemistry.

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Most popular questions from this chapter

A fertilizer contains phosphorus in two compounds, \(\mathrm{Ca}\left(\mathrm{H}_{2} \mathrm{PO}_{4}\right)_{2} \cdot \mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{CaHPO}_{4}\). The fertilizer contains \(30.0 \% \mathrm{Ca}\left(\mathrm{H}_{2} \mathrm{PO}_{4}\right)_{2} \cdot \mathrm{H}_{2} \mathrm{O}\) and \(10.0 \% \mathrm{CaHPO}_{4}\) (by mass). What is the mass percentage of phosphorus in the fertilizer?

According to an analysis, a sample of phosphate rock contains \(74.6 \% \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2},\) by mass. How many grams of phosphoric acid, \(\mathrm{H}_{3} \mathrm{PO}_{4},\) can be obtained from \(55.0 \mathrm{~g}\) of the phosphate rock according to the following reaction? \(\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s)+3 \mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow 3 \mathrm{CaSO}_{4}(s)+2 \mathrm{H}_{3} \mathrm{PO}_{4}(a q)\)

Discuss the bonding in each of the following molecules or ions. What is the expected molecular geometry? a \(\mathrm{Cl}_{2} \mathrm{O}\) b \(\mathrm{BrO}_{3}^{-}\) c \(\mathrm{BCl}_{3}\)

Sodium thiosulfate, \(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\), is prepared from sodium sulfite and sulfur: $$ 8 \mathrm{Na}_{2} \mathrm{SO}_{3}(a q)+\mathrm{S}_{8}(s) \longrightarrow 8 \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}(a q) $$ How many grams of \(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\) can be obtained from \(50.0 \mathrm{~g}\) of sulfur?

Describe the bonding (using valence bond theory) of the Group \(4 \mathrm{~A}\) atoms in each of the following: \(\mathrm{CCl}_{4}\) b \(\mathrm{HCN}\) c \(\mathrm{SiF}_{4}\) d \(\mathrm{CH}_{3} \mathrm{COOH}\) (acetic acid)

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