Chapter 20: Problem 94
The naturally occurring isotope rubidium-87 decays by beta emission to strontium- 87 . This decay is the basis of a method for determining the ages of rocks. A sample of rock contains \(102.1 \mu \mathrm{g}{ }^{87} \mathrm{R} \mathrm{b}\) and \(5.0 \mu \mathrm{g}{ }^{87} \mathrm{Sr}\). What is the age of the rock? The half-life of rubidium- 87 is \(4.8 \times 10^{10} \mathrm{y}\)
Short Answer
Step by step solution
Identify Initial and Current Quantities
Determine the Number of Half-Lives
Use the Decay Formula
Solve for n
Calculate the Age of the Rock
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Rubidium-Strontium Dating
- Rubidium-87 is present in minerals from the time of their formation, but it decays over long periods.
- Strontium-87 accumulates as a result of the decay, providing scientists with clues about the rock's age.
- The current and original amounts of rubidium and strontium are used to estimate how many decay cycles, or half-lives, have elapsed.
- By understanding this decay cycle, researchers can determine the time since the rock or mineral was formed.
Half-Life Calculation
- This duration means that rubidium-87 is suitable for dating ancient formations because it remains in significant amounts even after billion-year time scales.
- In calculations, the number of elapsed half-lives is determined using the proportion of the original isotope to its remaining quantity.
- This method involves mathematical formulas that relate half-life to age.
Isotope Decay
- In radioactive decay, isotopes lose atomic particles which changes them to different elements or isotopes.
- Each decay cycle, characterized by a transition from one isotope to another, is a measurable and predictable process.
- This conversion assists in calculating the time elapsed since the rock was formed, using the balance of isotopes present.
Beta Emission in Chemistry
- A beta particle can be an electron or a positron, which is ejected from the nucleus.
- This process alters the atomic number while maintaining the atomic mass, effectively transforming the element into a new one.
- For rubidium-87, beta emission reduces the proton count in favor of strontium, which is one atomic number higher.