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If \(20.0 \%\) of a sample of zinc- 65 decays in \(69.9 \mathrm{~d}\), what is the half-life of this isotope (in days)?

Short Answer

Expert verified
The half-life of zinc-65 is approximately 244 days.

Step by step solution

01

Understand the Given Information

We are given that 20% of a sample has decayed in 69.9 days. We need to find the half-life of zinc-65 in days.
02

Recall the Exponential Decay Formula

The exponential decay formula is given by \( N(t) = N_0 e^{-kt} \), where \( N(t) \) is the remaining quantity after time \( t \), \( N_0 \) is the initial quantity, and \( k \) is the decay constant.
03

Determine the Remaining Quantity

Since 20% has decayed, the remaining quantity is 80% of the initial, or \( N(t) = 0.8 N_0 \).
04

Use the Decay Formula for the Specific Case

Substitute \( N(t) = 0.8N_0 \) and \( t = 69.9 \) in the formula: \[ 0.8N_0 = N_0 e^{-69.9k} \]. Simplify to \( 0.8 = e^{-69.9k} \).
05

Solve for the Decay Constant \( k \)

Take the natural logarithm of both sides to eliminate the exponent: \( \ \ln(0.8) = -69.9k \). Solve for \( k \): \( k = -\frac{\ln(0.8)}{69.9} \).
06

Use the Decay Constant to Find Half-Life

The half-life \( T_{1/2} \) is related to the decay constant by \( T_{1/2} = \frac{\ln(2)}{k} \). Substitute the value of \( k \) from the previous step to find the half-life.
07

Calculate the Half-Life

Using the expression \( T_{1/2} = \frac{\ln(2)}{-\ln(0.8)/69.9} \), do the arithmetic to find \( T_{1/2} \): \( T_{1/2} \approx 244 \) days.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Decay
Exponential decay is a process where the quantity of a substance decreases by a consistent percentage over equal time intervals. It's commonly used to describe the behavior of radioactive isotopes, like zinc-65. A key feature of exponential decay is that the rate of decay is proportional to the amount of substance present at any time. This is captured in the equation: \[ N(t) = N_0 e^{-kt} \] where:- \( N(t) \) is the amount remaining at time \( t \),- \( N_0 \) is the initial amount,- \( k \) is the decay constant.In an exponential decay scenario, the decay constant defines how quickly a substance loses mass. This concept is crucial when calculating half-lives, as it allows us to model the decrease in substance over time.
Decay Constant
The decay constant, denoted by \( k \), is a critical parameter in describing radioactive decay through exponential decay processes. It represents the probability per unit time that a single nucleus will decay, which means higher values of \( k \) indicate faster decay.The decay constant is related to the half-life by the formula:\[ T_{1/2} = \frac{\ln(2)}{k} \] To calculate \( k \), you can rearrange the exponential decay formula for specific observations. For example, in the case of zinc-65, if 20% of the sample decays over a certain time period (e.g., 69.9 days), we use:- Starting with the equation \( 0.8 = e^{-69.9k} \)- Taking the natural logarithm of both sides: \( \ln(0.8) = -69.9k \)- Solving for \( k \):\[ k = -\frac{\ln(0.8)}{69.9} \] Understanding \( k \) provides insights into the speed at which a radioactive isotope, like zinc-65, approaches its half-life.
Natural Logarithm
The natural logarithm, represented as \( \ln \), is a mathematical function essential for solving exponential equations in the contexts of growth and decay.Natural logarithms are based on Euler's number \( e \) (approximately 2.718) and help in determining values that involve exponential relationships. When dealing with the exponential decay of a substance like zinc-65, natural logarithms are used to solve for unknowns, such as the decay constant or time variables.For instance, when solving \( 0.8 = e^{-69.9k} \), taking the natural logarithm of both sides - \( \ln(0.8) = -69.9k \) - allows us to isolate \( k \), enabling further calculations. Understanding how to apply the natural logarithm is crucial for computations involving decay.
Zinc-65
Zinc-65 is a radioactive isotope that undergoes decay over time, a characteristic that allows scientists to study its behavior using principles of exponential decay. As a research isotope, zinc-65 has applications in both environmental studies and medical fields. Tracking its decay helps ascertain the isotope's half-life, a fundamental property that indicates how long it takes the isotope to reduce by half. The unique decay characteristics of zinc-65 make it a suitable subject for demonstrating calculations involving half-life. By understanding the process of decay in zinc-65, students gain insight into broader decay processes in other isotopes. When tasked with problems related to zinc-65's decay, such as finding its half-life, students apply concepts such as exponential decay, decay constants, and natural logarithms to achieve a solution.

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