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Scandium- 41 is an artificially produced radioactive isotope. It decays by emitting a single positron. Write the nuclear equation for this decay.

Short Answer

Expert verified
The nuclear equation for Scandium-41 decay is \( ^{41}_{21}Sc \rightarrow ^{41}_{20}Ca + ^{0}_{+1}e \).

Step by step solution

01

Identify Scandium-41

Scandium-41 is represented with the nuclear notation \( ^{41}_{21}Sc \), where 41 is the mass number and 21 is the atomic number of Scandium. This indicates the number of protons in the nucleus.
02

Determine the Decay Process

Scandium-41 undergoes positron emission, where a positron is emitted from the nucleus. A positron is a positively charged electron, represented by \( ^{0}_{+1}e \). In this process, a proton is converted into a neutron.
03

Write the Nuclear Equation

During positron emission in Scandium-41, the atomic number decreases by 1 (from 21 to 20) as a proton converts to a neutron, while the mass number remains the same (41). This results in a Calcium-41 nucleus. The nuclear equation is written as:\[ ^{41}_{21}Sc \rightarrow ^{41}_{20}Ca + ^{0}_{+1}e \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radioactive Decay
Radioactive decay is a natural process by which an unstable atomic nucleus loses energy by emitting radiation. This process can result in the transformation of an element into another. In nuclear physics, decay types include alpha decay, beta decay, and gamma decay, among others.
For Scandium-41, radioactive decay occurs through positron emission. This involves a transformation within the atom's nucleus, leading to changes in its structure. Students often study these decay processes to understand how different isotopes achieve stability.
Remember, through radioactive decay, the nucleus reaches a lower energy state. This is a way for the atom to become more stable. However, while undergoing this transformation, radiation is often emitted, which may be hazardous.
Positron Emission
Positron emission is a type of beta decay. It occurs when a proton in the nucleus is transformed into a neutron. This process emits a positron, which is essentially a positively charged electron, denoted as \( ^{0}_{+1}e \). In equations, it typically appears as a byproduct of the decay process.
In the specific case of Scandium-41, it undergoes positron emission as part of its radioactive decay. This causes a proton to be converted into a neutron, thereby reducing the atomic number by one, while the mass number remains unchanged.
This emission is significant since it illustrates how elements transmute into other elements. The end result of such an emission can take the form of an entirely different element with new properties, as seen when Scandium-41 decays into Calcium-41.
Scandium-41
Scandium-41 is an artificially produced radioactive isotope known for its inability to remain stable over time. It is not found naturally and is typically synthesized in laboratories. Its nuclear notation is \( ^{41}_{21}Sc \), where the top number is the mass number, and the bottom number is the atomic number.
As an unstable isotope, Scandium-41 is prone to undergo radioactive decay via positron emission. This property makes it an ideal subject for studying radioactive processes. It serves as a practical example for understanding how isotopes transition to lower energy states.
In practice, recognizing the decay products of such isotopes can be crucial for various scientific applications, including medical imaging and other technologies that rely on radioactive tracers.
Mass Number
The mass number is a crucial component that represents the total number of protons and neutrons in an atom's nucleus. This is usually indicated as the top number in nuclear notation. For Scandium-41, the mass number is 41.
Although positron emission results in a change in the atomic number, the mass number often remains unchanged, as seen in Scandium-41's decay to Calcium-41. This constancy is because the process involves the transformation of a proton to a neutron, thus, not altering the total nucleons.
Understanding mass numbers helps in predicting the behavior of isotopes during nuclear reactions and helps students comprehend how nuclear equations balance out.
Atomic Number
The atomic number indicates the number of protons in an atom's nucleus and determines the element's identity. In nuclear notation, it's the bottom number. Scandium features an atomic number of 21.
With positron emission, like with Scandium-41, there is a change in the atomic number as a proton is transformed into a neutron. Thus, the atomic number decreases, leading Scandium-41 with an atomic number of 21 to transform into Calcium-41 with an atomic number of 20.
Comprehending atomic numbers is crucial for understanding chemical properties and predicting outcomes of radioactive processes. They explain why different isotopes display varying behaviors despite having identical mass numbers.

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Most popular questions from this chapter

The half-life of calcium- 47 is 4.536 days and it decays by the emission of a beta particle. a. Write a balanced equation for the decay of Ca-47. If \(10.0 \mu \mathrm{g}\) of \(\mathrm{Ca}-47\) is needed for an experiment, what mass of \({ }^{47} \mathrm{CaSO}_{4}\) must be ordered if it takes \(48 \mathrm{~h}\) for it to arrive from the supplier?

A \(4.00 \times 10^{-2}-\) mol sample of a radioisotope has an activity of 56.5 Ci. What is the decay constant of the isotope (in /s)?

Polonium- 210 has a half-life of 138.4 days, decaying by alpha emission. Suppose the helium gas originating from the alpha particles in this decay was collected. What volume of helium at \(25^{\circ} \mathrm{C}\) and \(735 \mathrm{mmHg}\) could be obtained from \(1.0000 \mathrm{~g}\) of polonium dioxide, \(\mathrm{PoO}_{2},\) in a period of \(48.0 \mathrm{~h} ?\)

Polonium- 216 decays to lead- 212 by emission of an alpha particle. Which of the following is the nuclear equation for this radioactive decay? a) \({ }^{216} \mathrm{Po} \longrightarrow{ }_{84}^{212} \mathrm{~Pb}+{ }_{-1}^{0} \mathrm{e}\) b \({ }_{84}^{216} \mathrm{Po} \longrightarrow{ }_{82}^{212} \mathrm{~Pb}+{ }_{2}^{4} \mathrm{He}\) c) \({ }_{84}^{216} \mathrm{Po}+{ }_{2}^{4} \mathrm{He} \longrightarrow{ }_{82}^{212} \mathrm{~Pb}\) d) \({ }_{84}^{216} \mathrm{Po} \longrightarrow{ }_{82}^{212} \mathrm{~Pb}+{ }_{1}^{0} \mathrm{e}\) \(e_{84}^{216} \mathrm{Po}+2_{-1}^{0} \mathrm{e} \longrightarrow{ }_{82}^{212} \mathrm{~Pb}+4_{0}^{1} \mathrm{n}\)

In what major way has the discovery of transuranium elements affected the form of modern periodic tables?

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