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Name the following molecular compounds. a. \(\mathrm{ClF}_{4}\) b. \(\mathrm{CS}_{2}\) c. \(\mathrm{PF}_{3}\) d. \(\mathrm{SF}_{6}\)

Short Answer

Expert verified
a) Chlorine tetrafluoride, b) Carbon disulfide, c) Phosphorus trifluoride, d) Sulfur hexafluoride.

Step by step solution

01

Name the First Element

Identify the first element in the compound formula and write its name. For compound (a) \( \mathrm{ClF}_{4} \), the first element is chlorine, so we start with "chlorine." For (b) \( \mathrm{CS}_{2} \), the first element is carbon. In (c) \( \mathrm{PF}_{3} \), the first element is phosphorus. For (d) \( \mathrm{SF}_{6} \), the first element is sulfur.
02

Identify Prefix for the Second Element

Determine the prefix for the second element based on the number of atoms from its subscript. For \( \mathrm{ClF}_{4} \), there are four fluorine atoms, so we use "tetra-". For \( \mathrm{CS}_{2} \), two sulfur atoms mean "di-". In \( \mathrm{PF}_{3} \), three fluorine atoms require "tri-". And for \( \mathrm{SF}_{6} \), six fluorine atoms mean "hexa-".
03

Name the Second Element with Suffix Change

Write the name of the second element with the suffix 'ide' replacing the last part of its name. In \( \mathrm{ClF}_{4} \), fluorine becomes "tetrafluoride"; in \( \mathrm{CS}_{2} \), sulfur becomes "disulfide"; in \( \mathrm{PF}_{3} \), fluorine becomes "trifluoride"; and in \( \mathrm{SF}_{6} \), fluorine becomes "hexafluoride".
04

Combine Names to Form the Molecular Compound Name

Combine the names from the above steps to get the full names of the compounds. \( \mathrm{ClF}_{4} \) becomes chlorine tetrafluoride, \( \mathrm{CS}_{2} \) becomes carbon disulfide, \( \mathrm{PF}_{3} \) becomes phosphorus trifluoride, and \( \mathrm{SF}_{6} \) becomes sulfur hexafluoride.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Nomenclature
Chemical nomenclature is the system of rules and names used for naming chemical compounds. It helps in identifying the composition of a compound quickly and consistently, making it easier to communicate complex information about chemical substances.

In the context of molecular compounds, chemical nomenclature involves referring to non-metal elements that form compounds through covalent bonds. These compounds consist of two or more non-metals sharing electrons. The naming rules allow chemists and students alike to denote specific molecules just by reading or writing their chemical names.

There are several key rules in chemical nomenclature:
  • Write the name of the more electropositive atom first and the more electronegative atom second.
  • Use prefixes to denote the number of each type of atom.
  • Modify the name of the second atom using the suffix '-ide.'


Mastering chemical nomenclature helps students in understanding the unique nature of each compound and allows them to predict reactive tendencies and other chemical properties.
Binary Molecular Compounds
Binary molecular compounds are composed of two different non-metal elements. These are fundamental in the study of chemistry as they constitute a large proportion of the compounds encountered in various reactions.

A molecular compound such as chlorine tetrafluoride ClF_4, for instance, consists of chlorine and fluorine atoms. One distinguishes it as binary because it contains precisely two different elements.

Characteristics of binary molecular compounds include:
  • They're usually identified by two-element formulas.
  • They bond through sharing pairs of electrons (covalent bonding).
  • They are generally gases or liquids at room temperature.


Recognizing and understanding the formation of binary molecular compounds paves the way for disciplines like organic chemistry and helps in predicting the way compounds react with each other in various environments.
Naming Conventions
Naming conventions in chemistry are sets of systematic guidelines used to ensure uniformity in the naming of chemical substances. These conventions are crucial for conveying clear and consistent information.

When naming binary molecular compounds, specific naming conventions are applied:
  • The first element in the formula is named using its standard element name.
  • The second element’s name is modified with the '-ide' suffix.
  • Prefixes such as mono-, di-, tri-, tetra-, penta- are used to indicate the number of atoms of each element in the compound, although the prefix "mono-" is often omitted for the first element.


For instance, with a compound like ClF_4, "chlorine" is the first element, and four atoms of fluorine are represented with the prefix "tetra-" followed by "fluoride," to give us the name chlorine tetrafluoride. Similarly, CS_2 would be named carbon disulfide.

By following these conventions, chemists ensure clear communication, avoid ambiguity, and maintain coherence in textual and verbal chemical exchanges worldwide.

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Most popular questions from this chapter

Natural carbon, which has an atomic weight of 12.011 amu, consists of carbon- 12 and carbon- 13 isotopes. Given that the mass of carbon-13 is 13.00335 amu, what would be the average atomic weight (in amu) of a carbon sample prepared by mixing equal numbers of carbon atoms from a sample of natural carbon and a sample of pure carbon-13?

A sample of metallic element \(X\), weighing 4.315 g, combines with \(0.4810 \mathrm{~L}\) of \(\mathrm{Cl}_{2}\) gas (at normal pressure and \(20.0^{\circ} \mathrm{C}\) ) to form the metal chloride with the formula XCl. If the density of \(\mathrm{Cl}_{2}\) gas under these conditions is 2.948 \(\mathrm{g} / \mathrm{L},\) what is the mass of the chlorine? The atomic weight of chlorine is 35.45 amu. What is the atomic weight of \(X\) ? What is the identity of \(\mathrm{X} ?\)

Obtain the fractional abundances for the two naturally occurring isotopes of europium. The masses of the isotopes are \({ }^{151} \mathrm{Eu}, 150.9196 \mathrm{amu} ;{ }^{153} \mathrm{Eu}, 152.9209 \mathrm{amu} .\) The atomic weight is 151.9641 amu.

The element europium exists in nature as two isotopes: \({ }^{151} \mathrm{Eu}\) has a mass of \(150.9196 \mathrm{amu},\) and \({ }^{153} \mathrm{Eu}\) has a mass of 152.9209 amu. The average atomic mass of europium is 151.96 amu. a. Calculate the relative abundance of the two europium isotopes. b. Graph each fractional abundance value as a y-axis value in association with its corresponding mass value on the \(\mathrm{x}\) -axis. Starting from each \(\mathrm{x}\) -axis value, where \(\mathrm{y}=0\), draw a vertical line up to the fractional abundance value. The result will approximate the type of visual graph a mass spectrometer would yield for europium in the \(150-155\) amu range.

Solid sodium metal reacts with water, giving a solution of sodium hydroxide and releasing hydrogen gas. Write a balanced equation for the reaction using complete formulas for the compounds with phase labels.

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