/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 The electrolysis of water is oft... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The electrolysis of water is often done by passing a current through a dilute solution of sulfuric acid. What is the function of the sulfuric acid?

Short Answer

Expert verified
Sulfuric acid increases the conductivity of water, allowing electrolysis to occur efficiently.

Step by step solution

01

Understanding Electrolysis Context

In electrolysis, an electric current is used to drive a non-spontaneous chemical reaction. When water is electrolyzed, hydrogen gas is produced at the cathode, and oxygen gas is produced at the anode.
02

Role of Sulfuric Acid

Sulfuric acid enhances the process of electrolysis by increasing the conductivity of water. Water on its own is a poor conductor of electricity because it has very few ions present in pure form.
03

Conductivity Enhancement

Sulfuric acid dissociates into ions when added to water: \( H_2SO_4 \rightarrow 2H^+ + SO_4^{2-} \). These ions facilitate the flow of electric current through the solution, ensuring effective electrolysis.
04

Conclusion on Function

The primary function of sulfuric acid in the electrolysis of water is to provide additional ions in the solution, thereby increasing its electrical conductivity and allowing the process to occur efficiently.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sulfuric Acid in Electrolysis
Sulfuric acid plays an instrumental role in the electrolysis of water. During electrolysis, an electric current is used to initiate and drive a chemical reaction that wouldn't occur on its own. Water, in its pure form, has very few ions and thus is a poor conductor of electricity.

When sulfuric acid is dissolved in water, it dissociates into positively charged hydrogen ions (\( H^+ \) and negatively charged sulfate ions (\( SO_4^{2-} \). These ions increase the number of charge carriers in the solution, greatly enhancing its conductivity.

Thus, the primary function of sulfuric acid is to provide these additional ions, which facilitates the movement of electric charge and ensures that electrolysis proceeds smoothly and efficiently. Without sulfuric acid, the efficiency of the electrolysis process would be significantly reduced.
Understanding Ionic Conductivity
Ionic conductivity is a critical concept when discussing electrolysis and sulfuric acid's role within it. Conductivity, at its core, is the ability of a substance to transmit electricity. In solutions like water with dissolved ions, this occurs through the movement of those ions.

In pure water, there are relatively few ions available to carry electric charge, making it a poor conductor. However, by adding sulfuric acid, the solution is filled with free-moving hydrogen ions (\( H^+ \)) and sulfate ions (\( SO_4^{2-} \)). This results in a noteworthy boost in ionic conductivity, allowing more effective and efficient transmission of electric current.

Without sufficient ionic conductivity provided by these additional ions, the electrical current required to trigger and maintain the electrolysis process would struggle to flow through the solution. Thus, adding sulfuric acid fundamentally transforms the solution's nature from being a weak conductor to a powerful electrolyte.
The Role of Electric Current
Electric current is the driving force behind the electrolysis process. It consists of a flow of electric charge, facilitated by the movement of ions in a solution. In the context of electrolysis, the electric current initiates the breakdown of water molecules into hydrogen and oxygen gases.

Here is how it works:
  • At the cathode (negative electrode), hydrogen ions (\( H^+ \)) receive electrons to form hydrogen gas (\( H_2 \)).
  • At the anode (positive electrode), water molecules release electrons, producing oxygen gas and hydrogen ions.
The passage of electric current through the dilute sulfuric acid solution ensures that these reactions continue steadily, releasing gas at each electrode. This continuous flow is essential for the production of gases and the completion of the electrolysis process.

A solid understanding of the relationship between electric current and ionic movement underscores the importance of having a conductive medium, such as the sulfuric acid-infused solution, to facilitate efficient electrolysis.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the voltaic cell $$\operatorname{Zn}(s)\left|\mathrm{Zn}^{2+}(a q) \| \mathrm{Cr}^{3+}(a q)\right| \mathrm{Cr}(s)$$ Write the half-cell reactions and the overall cell reaction. Make a sketch of this cell and label it. Include labels showing the anode, cathode, and direction of electron flow.

You have \(1.0 \mathrm{M}\) solutions of \(\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}\) and \(\mathrm{AgNO}_{3}\) along with Al and Ag electrodes to construct a voltaic cell. The salt bridge contains a saturated solution of \(\mathrm{KCl}\). Complete the picture associated with this problem by a. writing the symbols of the elements and ions in the appropriate areas (both solutions and electrodes). b. identifying the anode and cathode. c. indicating the direction of electron flow through the external circuit. d. indicating the cell potential (assume standard conditions, with no current flowing). e. writing the appropriate half-reaction under each of the containers. f. indicating the direction of ion flow in the salt bridge. g. identifying the species undergoing oxidation and reduction. h. writing the balanced overall reaction for the cell.

In an analytical determination of arsenic, a solution containing arsenious acid, \(\mathrm{H}_{3} \mathrm{AsO}_{3},\) potassium iodide, and a small amount of starch is electrolyzed. The electrolysis produces free iodine from iodide ion, and the iodine immediately oxidizes the arsenious acid to hydrogen arsenate ion, \(\mathrm{HAsO}_{4}^{2-} .\) $$ \begin{aligned} \mathrm{I}_{2}(a q)+\mathrm{H}_{3} \mathrm{AsO}_{3}(a q)+\mathrm{H}_{2} \mathrm{O}(l) & \longrightarrow \\ 2 \mathrm{I}^{-}(a q) &+\mathrm{HAsO}_{4}{ }^{2-}(a q)+4 \mathrm{H}^{+}(a q) \end{aligned} $$ When the oxidation of arsenic is complete, the free iodine combines with the starch to give a deep blue color. If, during a particular run, it takes \(65.4 \mathrm{~s}\) for a current of \(10.5 \mathrm{~mA}\) to give an endpoint (indicated by the blue color), how many grams of arsenic are present in the solution?

Give the mathematical relationships between the members of each possible pair of the three quantities \(\Delta G^{\circ},\) \(E_{\text {cell }}^{\circ}\), and \(K\).

A standard electrochemical cell is made by dipping a silver electrode into a \(1.0 \mathrm{M} \mathrm{Ag}^{+}\) solution and a cadmium electrode into a \(1.0 \mathrm{M} \mathrm{Cd}^{2+}\) solution. a. What is the spontaneous chemical reaction, and what is the maximum potential produced by this cell? b. What would be the effect on the potential of this cell if sodium sulfide were added to the \(\mathrm{Cd}^{2+}\) half-cell and CdS were precipitated? Why? c. What would be the effect on the potential of the cell if the size of the silver electrode were doubled?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.