Chapter 18: Problem 128
\( K_{s p}\) for silver chloride at \(25.0^{\circ} \mathrm{C}\) is \(1.782 \times 10^{-10}\) At \(35.0^{\circ} \mathrm{C}, K_{s p}\) is \(4.159 \times 10^{-10} .\) What are \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) for the reaction?
Short Answer
Expert verified
\(\Delta H^{\circ} = -\frac{7293 \,\text{J/mol}}{\text{R}}\) and \(\Delta S^{\circ} = 0.12 \, \text{J/mol K}\).
Step by step solution
01
Understand the Context
We are tasked with finding the enthalpy change (\(\Delta H^{\circ}\)) and entropy change (\(\Delta S^{\circ}\)) for the dissolution reaction of silver chloride (AgCl) by using the solubility product constant (\(K_{sp}\)) at two different temperatures.
02
Use the Van't Hoff Equation
The Van't Hoff equation is given by \[ \ln K_{sp} = -\frac{\Delta H^{\circ}}{R} \left(\frac{1}{T}\right) + \frac{\Delta S^{\circ}}{R} \] where \(R\) is the universal gas constant (8.314 \, J/mol \, K).
03
Convert Temperatures to Kelvin
Convert the given Celsius temperatures to Kelvin:- For 25.0°C: \[ T_1 = 25.0 + 273.15 = 298.15 \, \text{K} \]- For 35.0°C: \[ T_2 = 35.0 + 273.15 = 308.15 \, \text{K} \]
04
Calculate Natural Logarithms of Ksp
Compute the natural logarithm of the solubility product constants:- \(K_{sp1} = 1.782 \times 10^{-10}\), then \[ \ln K_{sp1} = \ln(1.782 \times 10^{-10}) \approx -21.8504\] - \(K_{sp2} = 4.159 \times 10^{-10}\), then \[ \ln K_{sp2} = \ln(4.159 \times 10^{-10}) \approx -21.0132\]
05
Set up System of Equations
Using the Van't Hoff equation at both temperatures, we get two equations:1. \( -21.8504 = -\frac{\Delta H^{\circ}}{R} \left(\frac{1}{298.15}\right) + \frac{\Delta S^{\circ}}{R}\)2. \( -21.0132 = -\frac{\Delta H^{\circ}}{R} \left(\frac{1}{308.15}\right) + \frac{\Delta S^{\circ}}{R}\)
06
Solve for ΔH° and ΔS°
Subtract the first equation from the second to eliminate (\(\frac{\Delta S^{\circ}}{R}\)):\[ \Delta (\ln K_{sp}) = \left(\frac{1}{T_1} - \frac{1}{T_2}\right) \frac{\Delta H^{\circ}}{R} \]Plug in known values to find (\(\Delta H^{\circ}\)):\[ (-21.0132 + 21.8504) = \left(\frac{1}{298.15} - \frac{1}{308.15}\right) \frac{\Delta H^{\circ}}{8.314} \]Solve for (\(\Delta H^{\circ}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Van't Hoff Equation
The Van't Hoff equation is a powerful tool in chemical thermodynamics that helps us understand how equilibrium constants, like the solubility product constant (K_{sp}), change with temperature. It relates these constants to the thermodynamic parameters of enthalpy change (\Delta H^{\circ}) and entropy change (\Delta S^{\circ}).This equation is given by:\[\ln K_{sp} = -\frac{\Delta H^{\circ}}{R} \left(\frac{1}{T}\right) + \frac{\Delta S^{\circ}}{R}\]where:
- \(K_{sp}\) is the solubility product constant.
- \(R\) is the universal gas constant, valued at 8.314 J/mol K.
- \(T\) represents temperature in Kelvin.
Enthalpy Change
Enthalpy change, represented as \(\Delta H^{\circ}\), is a central concept in thermodynamics. It signifies the total energy change in a reaction - accounting for both internal energy and the energy associated with pressure-volume work.
- A positive \(\Delta H^{\circ}\) implies an endothermic reaction, where heat is absorbed.
- A negative \(\Delta H^{\circ}\) indicates an exothermic reaction, as heat is released.
Entropy Change
Entropy change, denoted as \(\Delta S^{\circ}\), relates to the degree of disorder or randomness in a chemical system. It plays an essential role in determining the spontaneity of a reaction when paired with enthalpy changes.
- A positive \(\Delta S^{\circ}\) implies an increase in randomness or disorder during the reaction.
- A negative \(\Delta S^{\circ}\) suggests a reduction in disorder.
Solubility Product Constant
The solubility product constant, \(K_{sp}\), quantifies the solubility of a sparingly soluble salt in water at a specific temperature. It is a special type of equilibrium constant that signifies the extent to which a compound dissociates into its ions in solution.The expression for \(K_{sp}\) of a generic salt \(AB\) is:\[K_{sp} = [A^+]^m[B^-]^n\]where \([A^+]\) and \([B^-]\) are the molar concentrations of the ions, and \(m\) and \(n\) are their respective stoichiometric coefficients.Understanding \(K_{sp}\) is crucial when analyzing a compound’s solubility across different temperatures. If \(K_{sp}\) increases with temperature, the solubility also increases, which often occurs for endothermic processes. Conversely, a decrease in \(K_{sp}\) with rising temperature indicates reduced solubility.