/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 A shampoo solution at \(25^{\cir... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A shampoo solution at \(25^{\circ} \mathrm{C}\) has a hydroxide-ion concentration of \(1.5 \times 10^{-9} M .\) Is the solution acidic, neutral, or basic?

Short Answer

Expert verified
The solution is acidic.

Step by step solution

01

Understanding the pH and pOH

A solution can be classified as acidic, neutral, or basic depending on the concentration of hydrogen ions ( [H^+] ) or hydroxide ions ( [OH^-] ). The neutral water at 25°C has equal concentrations of hydrogen ions and hydroxide ions, both equal to 1 imes 10^{-7} ext{M} . We use the relation pH + pOH = 14 to classify the solution.
02

Calculate the pOH

Given the [OH^-] = 1.5 imes 10^{-9} ext{M} , we calculate the pOH using the formula pOH = - ext{log}_{10}( [OH^-] ) . Thus, pOH = - ext{log}_{10}(1.5 imes 10^{-9}) . Using a calculator, this gives approximately: pOH = 8.82 .
03

Calculate the pH

Once we have the pOH, we use the relationship pH + pOH = 14 to find the pH: pH = 14 - pOH = 14 - 8.82 = 5.18.
04

Classify the Solution

At 25°C, a pH of 7 indicates neutrality. If pH < 7, it indicates the solution is acidic, whereas a pH > 7 indicates the solution is basic. Here, the calculated pH is 5.18, which is less than 7.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

pH and pOH
The terms pH and pOH are crucial in understanding the nature of solutions. They are logarithmic scales used to specify the acidity or basicity of a solution. While pH measures the concentration of hydrogen ions \(\text{[H}^+\) in a solution, pOH measures the concentration of hydroxide ions \(\text{[OH}^-\). The scales are inversely related and add up to 14 at 25°C:- If the pH is below 7, the solution is acidic.- A pH of 7 is neutral.- If the pH is above 7, the solution is basic.Correspondingly, pOH works in the opposite manner:- A pOH below 7 indicates a basic solution.- A pOH of 7 is neutral.- A pOH above 7 indicates an acidic solution.To find pH from pOH, you use the formula \( \text{pH} + \text{pOH} = 14 \), making it easy to switch between the two when necessary.
solution classification
Classifying a solution as acidic, neutral, or basic depends on its pH level at a given temperature, commonly 25°C. At this temperature, the pH scale ranges from 0 to 14, providing a clear framework for classification: - **Acidic:** Solutions with a pH less than 7. They have higher concentrations of hydrogen ions compared to hydroxide ions. - **Neutral:** A pH of exactly 7. In pure water, the concentrations of hydrogen and hydroxide ions are equal (1 x 10^{-7} M). - **Basic:** Solutions with a pH greater than 7, indicating more hydroxide ions than hydrogen ions. Remember, this categorization is standard for 25°C. Temperature changes can affect the ion concentrations slightly, but for most practical purposes, this is stable. Therefore, knowing the pH can help determine whether a shampoo or any other solution leans towards being acidic, neutral, or basic.
hydroxide-ion concentration
Hydroxide-ion concentration (\( \text{[OH}^-] \)) is a measure of how many hydroxide ions are present in a solution. A higher concentration of these ions generally indicates a more basic solution. Given this concentration, we can determine a solution's basicity or acidity.To work with hydroxide-ion concentration, it is essential to know how it relates to pOH:- The formula \( \text{pOH} = -\log_{10}(\text{[OH}^-]} \) helps calculate the pOH of a solution from its hydroxide-ion concentration.From there, the relationship between pH and pOH is used to determine the pH, a critical step in ongoing solution classification. In the original exercise, the hydroxide-ion concentration of the shampoo solution is given as 1.5 \times 10^{-9} M, leading to a calculated pOH of 8.82. From this, we find a pH of 5.18 using \( \text{pH} + \text{pOH} = 14 \), indicating the solution is acidic. Understanding \( \text{[OH}^-] \) and its impact allows a precise grasp of solution properties, crucial for fields like chemistry and product formulation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Liquid ammonia undergoes autoionization similar to that of water: $$ \mathrm{NH}_{3}(l)+\mathrm{NH}_{3}(l) \rightleftharpoons \mathrm{NH}_{4}^{+}(l)+\mathrm{NH}_{2}^{-}(l) $$ How would you define an acid and a base similar to the way these terms are defined by the Brønsted-Lowry concept for aqueous solutions? Write the expression for the ionproduct constant, \(K_{a m},\) for this autoionization. The value of \(K_{a m}\) is \(5.1 \times 10^{-27}\). What is the concentration of \(\mathrm{NH}_{4}^{+}\) in a neutral solution of liquid ammonia? Suppose you dissolve \(\mathrm{NH}_{4} \mathrm{I}\) in liquid ammonia to give \(\mathrm{NH}_{4}{ }^{+}\) and \(\mathrm{I}^{-}\) ions. Similarly, you dissolve \(\mathrm{KNH}_{2}\) (potassium amide) in liquid ammonia to give a solution of \(\mathrm{K}^{+}\) and \(\mathrm{NH}_{2}^{-}\) ions. Which of these two solutions is acidic and which basic according to your definitions? Now, suppose you add the two solutions together. Write an equation for the neutralization reaction.

The \(\mathrm{pH}\) of a cup of coffee \(\left(\right.\) at \(\left.25^{\circ} \mathrm{C}\right)\) was found to be 5.12. What is the hydronium-ion concentration?

Give the conjugate acid to each of the following species regarded as bases. a \(\mathrm{ClO}^{-}\) b \(\mathrm{AsH}_{3}\) c \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) d) \(\mathrm{TeO}_{3}^{2-}\)

Ethanol, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH},\) can undergo auto- ionization. Write the chemical equation for this auto-ionization. Explain how you arrived at this equation. At room temperature, the ion product for this self-ionization is \(1.0 \times 10^{-20} .\) What is the concentration of each ion at this temperature? Show how you arrived at these concentrations.

A saturated solution of magnesium hydroxide is \(3.2 \times 10^{-4} \mathrm{M} \mathrm{Mg}(\mathrm{OH})_{2}\). What are the hydronium-ion and hydroxide-ion concentrations in the solution at \(25^{\circ} \mathrm{C} ?\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.