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Give the conjugate base to each of the following species regarded as acids a \(\mathrm{HSO}_{4}^{-}\) b \(\mathrm{PH}_{4}^{+}\) c HSe \(^{-}\) d \(\mathrm{HOBr}\)

Short Answer

Expert verified
a. \(\mathrm{SO}_{4}^{2-}\), b. \(\mathrm{PH}_{3}\), c. \(\mathrm{Se}^{2-}\), d. \(\mathrm{OBr}^{-}\).

Step by step solution

01

Understanding Conjugate Base

A conjugate base is formed when an acid donates a proton (H鈦) to another species. Identifying the conjugate base involves removing an H鈦 ion from the acid species.
02

Finding Conjugate Base of \(\mathrm{HSO}_{4}^{-}\)

The species \(\mathrm{HSO}_{4}^{-}\) can donate an H鈦 ion. When it loses a hydrogen ion, it becomes \(\mathrm{SO}_{4}^{2-}\). So, the conjugate base of \(\mathrm{HSO}_{4}^{-}\) is \(\mathrm{SO}_{4}^{2-}\).
03

Finding Conjugate Base of \(\mathrm{PH}_{4}^{+}\)

The species \(\mathrm{PH}_{4}^{+}\) donates an H鈦 ion and turns into \(\mathrm{PH}_{3}\). Therefore, the conjugate base of \(\mathrm{PH}_{4}^{+}\) is \(\mathrm{PH}_{3}\).
04

Finding Conjugate Base of \(\mathrm{HSe}^{-}\)

The species \(\mathrm{HSe}^{-}\) can donate an H鈦 ion to form \(\mathrm{Se}^{2-}\). Thus, the conjugate base of \(\mathrm{HSe}^{-}\) is \(\mathrm{Se}^{2-}\).
05

Finding Conjugate Base of \(\mathrm{HOBr}\)

The species \(\mathrm{HOBr}\) donates a proton H鈦 to become \(\mathrm{OBr}^{-}\). Therefore, the conjugate base of \(\mathrm{HOBr}\) is \(\mathrm{OBr}^{-}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid-Base Reactions
Acid-base reactions are fundamental chemical reactions involving the transfer of protons (H鈦 ions) between molecules. In these reactions, acids donate protons to bases, which accept them.
This transfer causes the acid to transform into its conjugate base, while the base becomes its conjugate acid. These transformations are at the heart of how acids and bases interact in chemistry.

For instance, when an acid like \( \mathrm{HSO}_4^{-} \)donates an \(H^+\) ion, it becomes \(\mathrm{SO}_4^{2-}\), an example of forming a conjugate base through a typical acid-base reaction.
This basic understanding helps in identifying how molecules change when participating in acid-base chemistry and is essential for predicting reactions and products in chemistry.
Proton Donor
An acid is often referred to as a proton donor because it has the capacity to donate a hydrogen ion (H鈦) to a solution or another molecular entity.
This donation process is the crux of what defines a chemical species as an acid.

Each time an acid donates an \(H^+\) ion, a shift occurs in its chemical structure, leading to the formation of a corresponding conjugate base.
Understanding which species act as proton donors can help you determine the course of a chemical reaction.
  • An example is \( \mathrm{PH}_4^{+} \), which donates an \(H^+\) and transforms into \( \mathrm{PH}_3 \).
  • Similarly, \( \mathrm{HSe}^{-} \), upon donating an \(H^+\), becomes \( \mathrm{Se}^{2-} \).
Every proton donation effectively changes the structure and reactivity of the involved species, which underscores the transformative power of acids in chemical reactions.
Conjugate Acid
In the realm of chemistry, conjugate acids are the species formed when a base gains a hydrogen ion (H鈦) during acid-base reactions.
This is essentially the reverse process of acids becoming conjugate bases.

After the base accepts a proton, it becomes what chemists call a conjugate acid. For instance, if \( \mathrm{OBr}^{-} \) accepts an \(H^+\), it would become \( \mathrm{HOBr} \), a potential conjugate acid.
This transformation illustrates the inherent duality in acid-base chemistry, where each reaction has an acid-base pair of conjugates. Understanding how conjugate acids are formed can aid in predicting the flow of ions and molecules in chemical solutions.
  • This concept underscores the reversible nature of acid-base interactions, which are never static but involve dynamic exchanges of protons.
  • Knowing the conjugate acid of a base is crucial when analyzing solution pH and acid-base balance.
Ionization
Ionization is the process by which a molecule gains or loses an ion, transforming into charged particles.
In the context of acid-base chemistry, ionization usually involves the release of a hydrogen ion (H鈦) from an acid.

This separation leaves the molecule with a negative charge, forming not only the conjugate base but also altering the electrical charge balance in the solution.
When an acid like \( \mathrm{HOBr} \) releases an \(H^+\), it undergoes ionization to become \( \mathrm{OBr}^{-} \).
This process is central to determining whether solutions are acidic or basic in nature. Ionization is largely responsible for the conductivity of solutions and their reactions to other substances.
  • Understanding ionization is key to mastering the interplay of solutes in solutions.
  • The degree of ionization affects how effectively an acid or base interacts in a reaction.
Ionization provides insight into reaction dynamics and is an essential concept for exploring more complex chemical reactions.

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Most popular questions from this chapter

Self-contained environments, such as that of a space station, require that the carbon dioxide exhaled by people be continuously removed. This can be done by passing the air over solid alkali hydroxide, in which carbon dioxide reacts with hydroxide ion. What ion is produced by the addition of \(\mathrm{OH}^{-}\) ion to \(\mathrm{CO}_{2}\) ? Use the Lewis concept to explain this.

The nitride ion and the amide ion, \(\mathrm{NH}_{2}^{-}\), have greater attractions for the hydronium ion than the hydroxide ion does. Write the equations for the reactions that occur when calcium nitride and sodium amide are added to water (each gives \(\mathrm{NH}_{3}\) ). Which is the stronger base, the nitride ion or the amide ion? Why? What is the meaning of the statement that the hydroxide ion is the strongest base that can exist in water?

For each of the following, write the complete chemical equation for the acid- base reaction that occurs. Describe each using Br酶nsted language (if appropriate) and then using Lewis language (show electron-dot formulas). a The \(\mathrm{HS}^{-}\) ion reacts in water to produce \(\mathrm{H}_{2} \mathrm{~S}\). b) Cyanide ion, \(\mathrm{CN}^{-}\), reacts with \(\mathrm{Fe}^{3+}\)

Ethanol, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH},\) can undergo auto- ionization. Write the chemical equation for this auto-ionization. Explain how you arrived at this equation. At room temperature, the ion product for this self-ionization is \(1.0 \times 10^{-20} .\) What is the concentration of each ion at this temperature? Show how you arrived at these concentrations.

Natural gas frequently contains hydrogen sulfide, \(\mathrm{H}_{2} \mathrm{~S}\). \(\mathrm{H}_{2} \mathrm{~S}\) is removed from natural gas by passing it through aqueous ethanolamine, \(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (an ammonia derivative), which reacts with the hydrogen sulfide. Write the equation for the reaction. Identify each reactant as either a Lewis acid or a Lewis base. Explain how you arrived at your answer.

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