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Nitrogen monoxide, \(\mathrm{NO},\) is believed to react with chlorine according to the following mechanism: $$ \begin{aligned} \mathrm{NO}+\mathrm{Cl}_{2} & \rightleftharpoons \mathrm{NOCl}_{2} & \text { (elementary reaction) } \\ \mathrm{NOCl}_{2}+\mathrm{NO} \longrightarrow 2 \mathrm{NOCl} & \text { (elementary reaction) } \end{aligned} $$ Identify any reaction intermediate. What is the overall equation?

Short Answer

Expert verified
The reaction intermediate is \( \mathrm{NOCl}_{2} \), and the overall reaction is \( 2\mathrm{NO} + \mathrm{Cl}_{2} \rightarrow 2\mathrm{NOCl} \)."

Step by step solution

01

Understanding the Reaction Mechanism

In analyzing a reaction mechanism, we examine the sequence of elementary reactions. Here, each elementary reaction involves a set of reactants converting directly to products. Let's consider the given reactions: 1. \( \mathrm{NO} + \mathrm{Cl}_{2} \rightleftharpoons \mathrm{NOCl}_{2} \) 2. \( \mathrm{NOCl}_{2} + \mathrm{NO} \longrightarrow 2\mathrm{NOCl} \)
02

Identifying Reaction Intermediates

A reaction intermediate is a species that is formed in one step of the mechanism and consumed in another. From the reactions:- \( \mathrm{NOCl}_{2} \) is produced in the first reaction and consumed in the second.Thus, \( \mathrm{NOCl}_{2} \) is a reaction intermediate.
03

Writing the Overall Reaction

To find the overall reaction, combine all elementary reactions, canceling out the intermediates.1. From the first reaction: \( \mathrm{NO} + \mathrm{Cl}_{2} \rightarrow \mathrm{NOCl}_{2} \)2. From the second reaction: \( \mathrm{NOCl}_{2} + \mathrm{NO} \rightarrow 2\mathrm{NOCl} \)Both reactions combine to give:\[2\mathrm{NO} + \mathrm{Cl}_{2} \rightarrow 2\mathrm{NOCl}\] This equation shows the conversion of two moles of \( \mathrm{NO} \) and one mole of \( \mathrm{Cl}_2 \) directly to two moles of \( \mathrm{NOCl} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Elementary Reactions
Elementary reactions are simple reactions that occur in a single step. In these reactions, reactants are directly converted into products without any intermediate processes. Given their nature, they involve only a small number of molecules, usually two or three. This makes elementary reactions straightforward to analyze and understand.

In our given scenario, we have two elementary reactions:
  • \( \mathrm{NO} + \mathrm{Cl}_{2} \rightleftharpoons \mathrm{NOCl}_{2} \)
  • \( \mathrm{NOCl}_{2} + \mathrm{NO} \rightarrow 2\mathrm{NOCl} \)
Each reaction represents a distinct elementary process. The first reaction shows the reversible formation of \( \mathrm{NOCl}_{2} \) from \( \mathrm{NO} \) and \( \mathrm{Cl}_{2} \), indicating equilibrium conditions. Meanwhile, the second reaction continues with \( \mathrm{NOCl}_{2} \) reacting with another \( \mathrm{NO} \) molecule to produce \( \mathrm{NOCl} \).

Understanding elementary reactions is crucial since they provide the building blocks for reaction mechanisms. They help us break down complex chemical processes into simpler, more digestible parts.
Reaction Intermediate
A reaction intermediate is a molecular entity that appears in a multi-step reaction mechanism but not in the overall balanced equation for the chemical change. Intermediates often exist only momentarily and are quickly consumed by subsequent steps in the mechanism. This transient nature makes them quite fascinating.

In this exercise, the intermediate is \( \mathrm{NOCl}_{2} \). It plays a crucial role in linking the elementary reactions together. First, it forms as a product of the initial reaction \( \mathrm{NO} + \mathrm{Cl}_{2} \rightleftharpoons \mathrm{NOCl}_{2} \). Then, it reacts with another molecule of \( \mathrm{NO} \) to produce \( \mathrm{NOCl} \).

It's important to note that intermediates like \( \mathrm{NOCl}_{2} \) are essential for the process but do not appear in the final reaction equation. Their existence helps us understand the detailed pathway by which the reaction progresses and provides insights into potential catalyst opportunities or reaction optimization.
Overall Reaction Equation
In chemical kinetics, the overall reaction equation represents the net result of a series of elementary reactions. To derive this, one combines all the individual reactions in the series and cancels out any intermediates and side products. The result is an equation that indicates the total change occurring from reactants to products.

For this exercise, we need to take both elementary reactions:
  • \( \mathrm{NO} + \mathrm{Cl}_{2} \rightarrow \mathrm{NOCl}_{2} \)
  • \( \mathrm{NOCl}_{2} + \mathrm{NO} \rightarrow 2\mathrm{NOCl} \)
We identify \( \mathrm{NOCl}_{2} \) as the intermediate and eliminate it from the overall equation, as it doesn't appear as a reactant or product in substantial quantities.

Combining these reactions and canceling \( \mathrm{NOCl}_{2} \), we are left with:\[2\mathrm{NO} + \mathrm{Cl}_{2} \rightarrow 2\mathrm{NOCl}\]

This overall reaction equation tells us that two moles of nitrogen monoxide \( (\mathrm{NO}) \) react with one mole of chlorine \( (\mathrm{Cl}_2) \) to produce two moles of \( \mathrm{NOCl} \), neatly summarizing the effects of the mechanism as a whole. Understanding the overall reaction helps chemists predict yields and determine stoichiometric relationships critical for practical applications.

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Most popular questions from this chapter

The reaction \(\mathrm{A} \longrightarrow \mathrm{B}+\mathrm{C}\) is found to be zero order. If it takes \(5.2 \times 10^{2}\) seconds for an initial concentration of A to go from \(0.50 M\) to \(0.25 M\), what is the rate constant for the reaction?

For the reaction of hydrogen with iodine $$ \mathrm{H}_{2}(g)+\mathrm{I}_{2}(g) \longrightarrow 2 \mathrm{HI}(g) $$ relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide.

Tertiary butyl chloride reacts in basic solution according to the equation $$ \left(\mathrm{CH}_{3}\right)_{3} \mathrm{CCl}+\mathrm{OH}^{-} \longrightarrow\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}+\mathrm{Cl}^{-} $$ The accepted mechanism for this reaction is $$ \begin{array}{l} \left(\mathrm{CH}_{3}\right)_{3} \mathrm{CCl} \longrightarrow\left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}^{+}+\mathrm{Cl}^{-} \\\ \left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}^{+}+\mathrm{OH}^{-} \longrightarrow\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH} \end{array} $$ What should be the rate law for this reaction?

Ammonium nitrite, \(\mathrm{NH}_{4} \mathrm{NO}_{2},\) decomposes in solution, as shown here. $$ \mathrm{NH}_{4} \mathrm{NO}_{2}(a q) \longrightarrow \mathrm{N}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(I) $$ The concentration of \(\mathrm{NH}_{4}^{+}\) ion at the beginning of an experiment was \(0.500 \mathrm{M}\). After 3.00 hours, it was \(0.432 \mathrm{M}\). What is the average rate of decomposition of \(\mathrm{NH}_{4} \mathrm{NO}_{2}\) in this time interval?

Methyl chloride, \(\mathrm{CH}_{3} \mathrm{Cl}\), reacts in basic solution to give methanol. $$ \mathrm{CH}_{3} \mathrm{Cl}+\mathrm{OH}^{-} \longrightarrow \mathrm{CH}_{3} \mathrm{OH}+\mathrm{Cl}^{-} $$ This reaction is believed to occur in a single step. If so, what should be the rate law?

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