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Hydrogen sulfide is oxidized by chlorine in aqueous solution. $$ \mathrm{H}_{2} \mathrm{~S}(a q)+\mathrm{Cl}_{2}(a q) \longrightarrow \mathrm{S}(s)+2 \mathrm{HCl}(a q) $$ The experimental rate law is $$ \text { Rate }=k\left[\mathrm{H}_{2} \mathrm{~S}\right]\left[\mathrm{Cl}_{2}\right] $$ What is the reaction order with respect to \(\mathrm{H}_{2} \mathrm{~S}\) and with respect to \(\mathrm{Cl}_{2} ?\) What is the overall order?

Short Answer

Expert verified
\( \mathrm{H}_2 \mathrm{S} \) is first order, \( \mathrm{Cl}_2 \) is first order; overall order is second order.

Step by step solution

01

Identify Reaction Rate Law Elements

The given rate law is \( \text{Rate} = k[\mathrm{H}_2 \mathrm{S}][\mathrm{Cl}_2] \). In this expression, the rate is proportional to the concentration of \( \mathrm{H}_2 \mathrm{S} \) and \( \mathrm{Cl}_2 \). Each substance present in the rate law has an associated exponent indicating its reaction order.
02

Determine Order with Respect to \(\mathrm{H}_2 \mathrm{S}\)

In the rate law expression \( \text{Rate} = k[\mathrm{H}_2 \mathrm{S}][\mathrm{Cl}_2] \), the concentration of \( \mathrm{H}_2 \mathrm{S} \) is raised to the first power, indicating that the reaction is first order with respect to \( \mathrm{H}_2 \mathrm{S} \).
03

Determine Order with Respect to \(\mathrm{Cl}_2\)

Similarly, in the rate law, the concentration of \( \mathrm{Cl}_2 \) is also raised to the first power, indicating that the reaction is first order with respect to \( \mathrm{Cl}_2 \).
04

Calculate Overall Reaction Order

The overall reaction order is the sum of the orders with respect to each reactant. Since both \( \mathrm{H}_2 \mathrm{S} \) and \( \mathrm{Cl}_2 \) are each first order, the overall reaction order is \( 1 + 1 = 2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Law
The rate law is a mathematical expression that describes the speed of a chemical reaction depending on the concentrations of the reactants. It provides a direct relationship between the concentrations of reactants and the rate of reaction. The general form of a rate law is:\[ \text{Rate} = k[A]^{m}[B]^{n}\]Here, \(k\) is the rate constant, \(A\) and \(B\) are the reactants, and \(m\) and \(n\) are the reaction orders with respect to those reactants. The rate law helps in understanding how changes in concentration affect the reaction rate. By knowing the rate law, scientists can predict how fast a reaction will proceed under different conditions.
  • The rate constant \(k\) is specific to each reaction and can be influenced by factors like temperature and catalyst presence.
  • The exponents \(m\) and \(n\) indicate the reaction order with respect to each reactant and are usually determined through experiments.
Understanding the rate law is crucial for controlling and optimizing chemical reactions, which is especially important in industrial processes and research environments.
First Order Reaction
A first order reaction refers to a reaction where the rate is directly proportional to the concentration of one reactant. In other words, if you double the concentration of this reactant, the reaction rate will also double. This relationship is expressed in the rate law as an exponent of one for the reactant concentration.In the example rate law: \[ \text{Rate} = k[\mathrm{H}_2 \mathrm{S}][\mathrm{Cl}_2]\] both \(\mathrm{H}_2 \mathrm{S}\) and \(\mathrm{Cl}_2\) have exponents of one. This means the reaction is first order with respect to each of these reactants.
  • First order reactions have a linear relationship between reactant concentration and rate.
  • They often show a constant half-life, which is the time needed for the concentration of the reactant to reduce to half of its initial value.
Recognizing first order reactions is important as it simplifies the analysis of kinetic data and helps in determining reaction mechanisms.
Overall Reaction Order
The overall reaction order is the sum of the exponents in the rate law equation, representing the total power to which concentrations are raised. It gives a general idea of how the reaction rate is influenced by all the reactants involved. For example, in the rate law \[ \text{Rate} = k[\mathrm{H}_2 \mathrm{S}][\mathrm{Cl}_2]\] the reaction orders are both one for \( \mathrm{H}_2 \mathrm{S}\) and \( \mathrm{Cl}_2\). By adding these exponents together, the overall reaction order is calculated to be 2.
  • An overall reaction order of 2 indicates that the reaction rate depends on the concentration of reactants squared collectively.
  • Reactions with higher overall orders are generally more sensitive to changes in concentration.
This understanding allows chemists to predict how experimental manipulations can affect the reaction speed and can be critical in designing efficient chemical processes.

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Most popular questions from this chapter

What is the rate law for the following gas-phase elementary reaction? $$ 2 \mathrm{I}+\mathrm{H}_{2} \longrightarrow 2 \mathrm{HI} $$

A reaction of the form \(a \mathrm{~A} \longrightarrow\) Products is secondorder with a rate constant of \(0.725 \mathrm{~L} /(\mathrm{mol} \cdot \mathrm{s})\). If the initial concentration of \(\mathrm{A}\) is \(0.760 \mathrm{~mol} / \mathrm{L},\) what is the molar concentration of A after \(88.8 \mathrm{~s}\) ?

Urea, \(\left(\mathrm{NH}_{2}\right)_{2} \mathrm{CO},\) can be prepared by heating ammonium cyanate, \(\mathrm{NH}_{4} \mathrm{OCN}\). $$ \mathrm{NH}_{4} \mathrm{OCN} \longrightarrow\left(\mathrm{NH}_{2}\right)_{2} \mathrm{CO} $$ This reaction may occur by the following mechanism: $$ \begin{array}{l} \mathrm{NH}_{4}^{+}+\mathrm{OCN}^{-} \stackrel{k_{1}}{{ }_{k_{-1}}} \mathrm{NH}_{3}+\mathrm{HOCN} \quad \text { (fast, equilibrium) } \\ \mathrm{NH}_{3}+\mathrm{HOCN} \stackrel{k_{2}}{\longrightarrow}\left(\mathrm{NH}_{2}\right)_{2} \mathrm{CO} \end{array} $$ What is the rate law predicted by this mechanism?

Nitrogen dioxide decomposes when heated. $$ 2 \mathrm{NO}_{2}(g) \longrightarrow 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) $$ During an experiment, the concentration of \(\mathrm{NO}_{2}\) varied with time in the following way: $$ \begin{array}{ll} \text { Time } & \text { INO }_{2} \text { ] } \\ 0.0 \text { min } & 0.1103 M \end{array} $$ \(\begin{array}{cc}1.0 . \min & 0.1076 M\end{array}\) $$ 0.1050 \mathrm{M} $$ \(2.0 \mathrm{~min}\) $$ \begin{array}{ll} 3.0 \mathrm{~min} & 0.1026 \mathrm{M} \end{array} $$ Obtain the average rate of decomposition of \(\mathrm{NO}_{2}\) in units of \(M / \mathrm{s}\) for each time interval.

The rate of a particular reaction quadruples when the temperature is increased from \(25^{\circ} \mathrm{C}\) to \(42^{\circ} \mathrm{C}\). Calculate the activation energy for this reaction.

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