/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Explain why a carbonated beverag... [FREE SOLUTION] | 91Ó°ÊÓ

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Explain why a carbonated beverage must be stored in a closed container.

Short Answer

Expert verified
A closed container maintains pressure, keeping carbon dioxide dissolved, so the beverage stays fizzy.

Step by step solution

01

Understand the Properties of Carbonation

Carbonation in beverages is achieved by dissolving carbon dioxide gas into the liquid. This process requires keeping the gas under pressure within the container to maintain its solubility.
02

Recognize the Effects of Pressure

The pressure inside a closed container keeps the carbon dioxide dissolved in the liquid. When dissolved under pressure, carbon dioxide forms carbonic acid, giving the beverage its fizzy characteristic.
03

Observe What Happens When a Container is Opened

When the container is opened, the pressure is released. With the decrease in pressure, carbon dioxide is less soluble and begins to escape as bubbles, causing the beverage to go flat.
04

Conclude the Necessity of a Closed Container

A closed container is necessary to maintain internal pressure, keeping carbon dioxide in solution. This ensures the beverage retains its carbonation and desired taste until consumption.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Carbon Dioxide Solubility
Carbon dioxide solubility plays a crucial role in the carbonation of beverages. When we say that a beverage is carbonated, it means carbon dioxide gas has been dissolved into the liquid. This process is all about solubility, which in simple terms, is the ability of a gas (in this case, carbon dioxide) to dissolve in a liquid (like water, juice, or soda).

In a carbonated beverage, carbon dioxide is dissolved into the liquid under specific conditions to create a refreshing fizz. The amount of carbon dioxide that can dissolve in the beverage depends on various factors, primarily pressure and temperature. When the gas is dissolved, it often forms carbonic acid, which contributes to the unique tanginess of carbonated drinks. This solubility makes carbonated drinks bubbly and enjoyable to consume.

Understanding the solubility of carbon dioxide helps explain why drinks fizz, retain taste, and feel refreshing. It all starts with understanding how gases like carbon dioxide interact with liquids under different conditions.
Pressure Effects on Solubility
Pressure is a key factor in how well carbon dioxide dissolves in beverages. When carbon dioxide is added to a drink, it is usually done under high pressure. This is because increased pressure allows more gas to dissolve into the liquid. Think of it as squeezing more carbon dioxide molecules into the drink.

  • High pressure ensures more gas stays in the liquid.
  • Upon opening a bottle, the pressure is released, causing gas to escape as bubbles.

As long as the pressure inside the bottle or can is maintained, the carbon dioxide remains dissolved. This is why sealed containers are critical. The fizz and sensation we feel when drinking a soda directly relate to the pressure effect because the gas reverts to its gaseous state, forming the iconic bubbles.

Understanding pressure effects helps us maintain the desired fizz and flavor of carbonated drinks until we're ready to enjoy them.
Closed Container Necessity
A closed container is vital for maintaining carbonation in beverages. Without it, the carbon dioxide would not stay dissolved. Think of the closed container like a trap keeping the carbonation where it needs to be.

  • Seals keep the internal pressure high to retain the carbon dioxide.
  • Opening the container releases pressure and allows gas to escape.

When you open a can or bottle, the popping sound you often hear is the pressurized air being released. This is an indication that the internal environment necessary for solubility is no longer present. As pressure decreases, so does the solubility, leading the carbon dioxide to fizz out.

Thus, for beverages to stay bubbly and retain their taste, they need to be stored in closed containers. This controlled environment ensures the drink remains refreshing and enjoyable for consumption.

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Most popular questions from this chapter

Oxalic acid, \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\), occurs as the potassium or calcium salt in many plants, including rhubarb and spinach. An aqueous solution of oxalic acid is \(0.580 \mathrm{~m} \mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} .\) The density of the solution is \(1.022 \mathrm{~g} / \mathrm{mL}\). What is the molar concentration?

A beverage contains tartaric acid, \(\mathrm{H}_{2} \mathrm{C}_{4} \mathrm{H}_{4} \mathrm{O}_{6},\) a substance obtained from grapes during wine making. If the beverage is \(0.265 M\) tartaric acid, what is the molal concentration? The density of the solution is \(1.016 \mathrm{~g} / \mathrm{mL}\).

Analysis of a compound gave \(39.50 \%\) C, \(2.21 \%\) H, and \(58.30 \% \mathrm{Cl}\). When \(0.855 \mathrm{~g}\) of this solid was dissolved in \(7.50 \mathrm{~g}\) of naphthalene, the solution had a freezing point of \(78.0^{\circ} \mathrm{C}\). The pure solvent freezes at \(80.0^{\circ} \mathrm{C}\); its molal freezing point constant is \(6.8^{\circ} \mathrm{C} / \mathrm{m}\). a.What is the molecular formula of the compound? b.What is the molar mass of this compound to the nearest tenth of a gram?

Equal numbers of moles of two soluble, substances, substance A and substance \(\mathrm{B}\), are placed into separate 1.0 - \(\mathrm{L}\) samples of water. a. The water samples are cooled. Sample A freezes at \(-0.50^{\circ} \mathrm{C},\) and Sample \(\mathrm{B}\) freezes at \(-1.00^{\circ} \mathrm{C}\). Explain how the solutions can have different freezing points. b. You pour \(500 \mathrm{~mL}\) of the solution containing substance B into a different beaker. How would the freezing point of this 500 -mL portion of solution \(\mathrm{B}\) compare to the freezing point of the 1.0 - \(\mathrm{L}\) sample of solution \(\mathrm{A}\) ? c. Calculate the molality of the solutions of \(\mathrm{A}\) and \(\mathrm{B}\). Assume that \(i=1\) for substance \(\mathrm{A}\). d. If you were to add an additional \(1.0 \mathrm{~kg}\) of water to solution \(\mathrm{B}\), what would be the new freezing point of the solution? Try to write an answer to this question without using a mathematical formula.

The solubility of carbon dioxide in water is \(0.161 \mathrm{~g}\) \(\mathrm{CO}_{2}\) in \(100 \mathrm{~mL}\) of water at \(20^{\circ} \mathrm{C}\) and \(1.00 \mathrm{~atm} .\) A soft drink is carbonated with carbon dioxide gas at 5.50 atm pressure. What is the solubility of carbon dioxide in water at this pressure?

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