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An aqueous solution is \(14.0 \%\) ammonium chloride, \(\mathrm{NH}_{4} \mathrm{Cl}\), by mass. The density of the solution is \(1.040 \mathrm{~g} / \mathrm{mL}\). What are the molality, mole fraction, and molarity of \(\mathrm{NH}_{4} \mathrm{Cl}\) in the solution?

Short Answer

Expert verified
Molality is 3.047 mol/kg, mole fraction is 0.0525, molarity is 2.724 mol/L.

Step by step solution

01

Understand Mass Percent

The solution is given as 14.0% ammonium chloride by mass. This means there are 14 grams of NHâ‚„Cl in every 100 grams of the solution.
02

Calculate Mass of Solvent

We have 100 g of solution with 14 g of NHâ‚„Cl, so the mass of the solvent (water) is 100 g - 14 g = 86 g.
03

Convert Mass of Water to moles

Water has a molar mass of 18 g/mol. Convert the mass of water to moles: \[ \frac{86 \text{ g}}{18 \text{ g/mol}} = 4.778 \text{ mol} \]
04

Calculate Moles of NHâ‚„Cl

The molar mass of NHâ‚„Cl is 53.5 g/mol. Convert the mass of NHâ‚„Cl to moles: \[ \frac{14 \text{ g}}{53.5 \text{ g/mol}} = 0.262 \text{ mol} \]
05

Calculate Molality

Molality (m) is calculated using the formula: \[ m = \frac{\text{moles of solute}}{\text{kilograms of solvent}} \]Substitute the values we found: \[ m = \frac{0.262 \text{ mol}}{0.086 \text{ kg}} = 3.047 \text{ mol/kg} \]
06

Calculate Mole Fraction of NHâ‚„Cl

The mole fraction is calculated using the formula: \[ X = \frac{\text{moles of NHâ‚„Cl}}{\text{total moles}} \]The total moles is the sum of the moles of NHâ‚„Cl and the moles of water: \[ X = \frac{0.262}{0.262 + 4.778} = 0.0525 \]
07

Calculate Molarity

Molarity (M) is calculated using the formula: \[ M = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \]First convert the mass of solution to volume using density: \[ \frac{100 \text{ g}}{1.040 \text{ g/mL}} = 96.15 \text{ mL} = 0.09615 \text{ L} \]Finally, calculate Molarity: \[ M = \frac{0.262}{0.09615} = 2.724 \text{ mol/L} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molality
Molality is a measure of concentration defined as the number of moles of solute per kilogram of solvent. Unlike molarity, which depends on the total volume, molality is purely mass-based. This makes it independent of temperature and pressure changes, a handy feature for experiments where conditions can fluctuate.
To calculate molality, we use the formula:
  • Molality (\( m \) ) = \( \frac{\text{moles of solute}}{\text{kilograms of solvent}} \)
In the exercise, ammonium chloride (\( \text{NH}_4\text{Cl} \) ) was the solute, and the remaining mass of the solution was the solvent (water). We converted the mass of water from grams to kilograms to find the amount of solvent used in the calculation. Thus, molality turns out to be a practical measure when dealing with boiling points or colligative properties, as these depend on the mass of the solvent used.
Molarity
Molarity refers to the concentration of a solution expressed in moles of solute per liter of solution. It is a common concentration measure used in chemistry for reactions that occur in solution. To calculate molarity, you need to know the solution's volume in liters.
The formula is:
  • Molarity (\( M \) ) = \( \frac{\text{moles of solute}}{\text{liters of solution}} \)
In this particular example, a critical step involved converting the mass of the solution to volume, using its density (\( 1.040 \text{ g/mL} \) ). By obtaining the volume in liters, we were able to find the molarity by dividing the moles of ammonium chloride by this volume. Molarity is sensitive to volume changes, such as those caused by temperature fluctuations, which is always something to remember when preparing solutions.
Mole Fraction
Mole fraction is a way of expressing concentration as the ratio of the number of moles of a component to the total number of moles in the solution. Unlike molality and molarity, mole fraction is unitless and gives a sense of the proportion of the solute in the mixture relative to all components.
The mole fraction calculation requires:
  • Mole Fraction (\( X \) ) = \( \frac{\text{moles of component}}{\text{total moles in solution}} \)
In our task, mole fraction was derived by dividing the moles of \( \text{NH}_4\text{Cl} \) by the sum of moles of \( \text{NH}_4\text{Cl} \) and the moles of water. This measure can be particularly useful when analyzing solutions' vapor pressures or chemical potential, providing clear insights into molecular composition dynamics without depending on the physical conditions of the system.

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