Chapter 11: Problem 154
How much heat must be added to \(50.0 \mathrm{~g}\) of solid sodium, \(\mathrm{Na},\) at \(25.0^{\circ} \mathrm{C}\) to give the liquid at its melting point, \(97.8^{\circ} \mathrm{C} ?\) The heat capacity of solid sodium is \(28.2 \mathrm{~J} /\) \((\mathrm{K} \cdot \mathrm{mol}),\) and its heat of fusion is \(2.60 \mathrm{~kJ} / \mathrm{mol}\)
Short Answer
Step by step solution
Calculate Moles of Sodium
Calculate Heat to Raise Temperature
Calculate Heat for Phase Change
Add the Heat Values
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molar Mass Calculation
To find out how many moles are in a sample, use the formula:
- Moles of substance = \(\frac{\text{Mass of substance}}{\text{Molar mass of substance}}\)
Heat Capacity
This means it requires 28.2 joules of energy to increase the temperature of 1 mole of sodium by 1 Kelvin. It is a very useful property in calculating the heat needed for a temperature change.
Consider the temperature change from \(25.0^{\circ} \text{C} \) to \(97.8^{\circ} \text{C}\). The temperature change (\(\Delta T\)) is therefore \(72.8 \, \text{K}\). By multiplying the number of moles, heat capacity, and the temperature difference, you can calculate the required heat. In our case:
\[\text{Heat} (q_1) = n \times C \times \Delta T\]
\[q_1 = 2.174 \, \text{mol} \times 28.2 \, \frac{\text{J}}{\text{K} \cdot \text{mol}} \times 72.8 \, \text{K} \approx 4460.2 \, \text{J}\]
Phase Change Calculations
For sodium, the heat of fusion is \(2.60 \, \mathrm{kJ/mol}\), or \(2600 \, \mathrm{J/mol}\).
To calculate the heat needed for this transition, the formula is:
- Heat required = \(n \times \Delta H_f\)
For \(2.174 \, \text{mol}\) of sodium, plug in the values to find:
\[q_2 = 2.174 \, \text{mol} \times 2600 \, \frac{\text{J}}{\text{mol}} = 5652.4 \, \text{J}\]
Specific Heat Formula
- \(q = m \cdot C_s \cdot \Delta T\)
- \(q\) is the heat added or removed
- \(m\) is the mass of the substance
- \(C_s\) is the specific heat capacity (per gram, different from molar heat capacity)
- \(\Delta T\) is the change in temperature