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Describe the contents of a carbon dioxide fire extinguisher at \(20^{\circ} \mathrm{C}\). Then describe it at \(35^{\circ} \mathrm{C}\). Explain the difference.

Short Answer

Expert verified
At both 20°C and 35°C, CO₂ in a fire extinguisher is mostly liquid. At 35°C, there's more gas due to higher vapor pressure.

Step by step solution

01

Understanding the physical state of carbon dioxide

Carbon dioxide can exist in different states: solid, liquid, and gas, depending on the temperature and pressure. In a fire extinguisher, carbon dioxide is stored under high pressure allowing it to remain in a liquid state at room temperature.
02

Examining contents at 20°C

At 20°C, inside the extinguishing cylinder, CO2 exists predominantly as a liquid with some gas on top, due to the pressure of the container. This pressure is high enough to keep the CO2 from simply vaporizing into the surrounding environment.
03

Examining contents at 35°C

At 35°C, the contents of the CO2 fire extinguisher remain similar to those at 20°C—mostly liquid with some gas above it. However, due to increased temperature, there is a higher vapor pressure, causing more CO2 to remain in the gaseous state.
04

Understanding the difference

The increase in temperature from 20°C to 35°C leads to an increased vapor pressure inside the extinguisher, causing some of the liquid CO2 to convert to gas. The overall contents remain a mixture of liquid and gas, but with a higher percentage of gas at 35°C due to the increased temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fire Extinguisher Operation
A fire extinguisher works by dousing flames with a substance that limits oxygen and heat, putting out the fire effectively. Inside a CO2 fire extinguisher, carbon dioxide is stored under high pressure as a liquid. When you activate the extinguisher, you release this high-pressure liquid into a lower pressure environment.
This rapid decompression causes the liquid CO2 to expand and absorb heat, converting into a gas known as dry ice-like snow. This cold discharge not only cools the fire but also creates a barrier between the fire's fuel and surrounding oxygen. In essence, CO2 removes heat and oxygen to extinguish the fire.
  • High pressure keeps CO2 in liquid form in the extinguisher.
  • Releasing the mechanism allows CO2 to rapidly expand and cool.
  • Effectively puts out fires by cutting off heat and oxygen.
Through this mechanism, CO2 extinguishers are particularly effective for electrical fires and flammable liquids. However, they might not be as effective on fuel-rich fires like wood or paper.
Liquid-Gas Equilibrium
Inside a CO2 fire extinguisher, there exists a delicate balance between the liquid and gaseous states of carbon dioxide. This balance is known as liquid-gas equilibrium. When the extinguisher is at rest, it contains a mix of liquid CO2 at the bottom and gaseous CO2 above it.
Liquid-gas equilibrium is influenced by the pressure and temperature inside the extinguisher. Under high pressure, liquid CO2 is maintained even though the temperature might be at room level. The gaseous CO2 sits above the liquid forming a dynamic equilibrium where vapor continually condenses to liquid and vice versa.
  • Balance between liquid state at bottom and gaseous state on top.
  • Equilibrium is dynamic - continual exchange between liquid and gas.
  • Pressure keeps more CO2 in liquid form at lower temperatures.
This equilibrium ensures the extinguisher works efficiently when needed, as some gas is always ready to eject rapidly when the extinguisher is activated.
Temperature Effects on Pressure
Temperature plays a significant role in determining the pressure inside a carbon dioxide fire extinguisher. As temperature increases, the kinetic energy of the CO2 molecules also increases, resulting in higher vapor pressure.
At 20°C, CO2 exists mainly as liquid with some gas on top, exerting a certain pressure to maintain equilibrium. When the temperature rises to 35°C, more of the liquid CO2 turns into gas due to higher vapor pressure, despite the container's rigid walls.
With higher temperature, vapor pressure causes the gas molecules to push harder against the container, increasing the gas volume proportion.
  • Increase in temperature leads to increase in vapor pressure.
  • More liquid converts to gas at higher temperatures.
  • Pressure rise is a result of increased molecular motion.
This temperature-induced pressure variation showcases why it's crucial to handle fire extinguishers within specified temperature limits to avoid over-pressurization and potential malfunction.

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Most popular questions from this chapter

The vapor pressure of a volatile liquid can be determined by slowly bubbling a known volume of gas through the liquid at a given temperature and pressure. In an experiment, a 5.40-L sample of nitrogen gas, \(\mathrm{N}_{2}\), at \(20.0^{\circ} \mathrm{C}\) and \(745 \mathrm{mmHg}\) is bubbled through liquid isopropyl alcohol, \(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O},\) at \(20.0^{\circ} \mathrm{C}\). Nitrogen containing the vapor of \(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}\) at its vapor pressure leaves the vessel at \(20.0^{\circ} \mathrm{C}\) and \(745 \mathrm{mmHg} .\) It is found that \(0.6149 \mathrm{~g} \mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}\) has evapo- rated. How many moles of \(\mathrm{N}_{2}\) are in the gas leaving the liquid? How many moles of alcohol are in this gaseous mixture? What is the mole fraction of alcohol vapor in the gaseous mixture? What is the partial pressure of the alcohol in the gaseous mixture? What is the vapor pressure of \(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}\) at \(20.0^{\circ} \mathrm{C} ?\)

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You may have seen the statement made that the liquid state is the stable state of water below \(100^{\circ} \mathrm{C}\) (but above \(0^{\circ} \mathrm{C}\) ), whereas the vapor state is the stable state above \(100^{\circ} \mathrm{C}\). Yet you also know that a pan of water set out on a table at \(20^{\circ} \mathrm{C}\) will probably evaporate completely in a few days, in which case, liquid water has changed to the vapor state. Explain what is happening here. What is wrong with the simple statement given at the beginning of this problem? Give a better statement.

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