Chapter 4: Problem 11
\(\mathrm{A} \rightarrow\) Product, \(\frac{\mathrm{dx}}{\mathrm{dt}}=\mathrm{k}[\mathrm{A}]^{3}\) If a is the initial concentration and \((a-x)\) is the concentration of A after time \(t\), then rate constant is given by: (a) \(\mathrm{k}=\frac{1}{\mathrm{t}}\left[\frac{1}{(\mathrm{a}-\mathrm{x})}-\frac{1}{\mathrm{a}}\right]\) (b) \(\mathrm{k}=\frac{1}{2 \mathrm{t}}\left[\frac{1}{(\mathrm{a}-\mathrm{x})^{2}}-\frac{1}{\mathrm{a}^{2}}\right]\) (c) \(\mathrm{k}=\frac{2.303}{\mathrm{t}} \log \left(\frac{\mathrm{a}}{\mathrm{a}-\mathrm{x}}\right)\) (d) \(\mathrm{k}=\frac{\mathrm{x}}{\mathrm{t}}\)
Short Answer
Step by step solution
Understanding the Rate Law
Express Concentration of A
Substitute into the Rate Law
Separate Variables
Integrate Both Sides
Apply Initial Condition
Solve for k
Match with Options
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Rate law
This equation tells us how the concentration of \( A \) influences the reaction rate: it is directly proportional to \( [A]^3 \). This means that the reaction rate increases significantly with an increase in the concentration of \( A \).
- **Proportionality**: The rate is proportional to the concentration of \( A \).- **Exponent**: The exponent (3 in this case) indicates the importance of \( A \)'s role in the reaction speed.
- The higher the exponent, the more sensitive the reaction rate to changes in \( A \).
Rate constant
In our earlier example \( \frac{dx}{dt} = k[A]^3 \), \( k \) is the constant that allows you to calculate the actual rate of the reaction from known concentrations of \( A \).
- **Unit of \( k \):** The units of \( k \) depend on the overall order of the reaction. For a third-order reaction, like the one in our example, the units of \( k \) could be \( \text{L}^2 \, \text{mol}^{-2} \, \text{s}^{-1} \).
- **Temperature Dependency:** The rate constant usually changes with temperature, so it is specific to the conditions under which the reaction occurs.
This dependency is quantified by the Arrhenius equation, which links \( k \) with temperature in an exponential relationship.
Reaction order
- **For the given reaction**: It is a third-order reaction due to the exponent 3 on \( [A] \).
This means the rate is very sensitive to the concentration of \( A \). - **Determining order**: Reaction orders can be **0**, **1**, **2**, etc., or even fractional. Each specifies how many times the rate will increase if the concentration of a reactant is doubled.
A 0 order means the rate is independent of reactant concentration. - **Not directly tied to stoichiometry**: The reaction order isn't always the same as the stoichiometric coefficients; it's an experimentally determined value that provides insight into the molecularity of the reaction mechanism.
Integrated rate equation
- This equation exemplifies how the concentration \( (a-x) \) changes over time \( t \) and how the process determines the expression for the rate constant \( k \).
- **Utilization**: By using these integrated forms, one can determine the concentration of reactants or products at any point in time, knowing the initial conditions.
- **Initial condition**: Typically, the initial condition assumes the concentration is known \( (x=0 \text{ at } t=0) \), ensuring that computations reflect the actual chemical process.