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An atomic absorption method for determination of copper in fuel samples yielded a pooled standard deviation of \(s_{\text {pooled }}=0.27 \mu \mathrm{g} \mathrm{Cu} / \mathrm{mL}(s \rightarrow \sigma)\). The analysis of an oil from a reciprocating aircraft engine showed a copper content of \(7.91 \mu \mathrm{g} \mathrm{Cu} / \mathrm{mL}\). Calculate the 95 and \(99 \%\) confidence intervals for the result if it was based on (a) a single analysis, (b) the mean of 4 analyses, and (c) the mean of 16 analyses.

Short Answer

Expert verified
The 95% CI for single, 4, and 16 analyses are [7.3808, 8.4392], [7.6454, 8.1746], [7.7777, 8.0423]; 99% CI are [7.21448, 8.60552], [7.56224, 8.25776], [7.73612, 8.08388].

Step by step solution

01

Understanding Confidence Interval Concept

A confidence interval gives an estimated range of values which is likely to include an unknown population parameter. It is calculated as: \( \text{Mean} \pm (\text{Z-value for confidence level} \times \frac{s_\text{pooled}}{\sqrt{n}}) \) where \( n \) is the number of observations.
02

95% CI for a Single Analysis

For a single analysis (\(n = 1\)), use the Z-value for 95% confidence level, which is approximately 1.96. The confidence interval is calculated as:\[ 7.91 \pm (1.96 \times 0.27) \]This computes to \(7.91 \pm 0.5292\), resulting in a confidence interval of \([7.3808, 8.4392]\).
03

99% CI for a Single Analysis

For 99% confidence, the Z-value is approximately 2.576. The interval is:\[ 7.91 \pm (2.576 \times 0.27) \]Which calculates to \(7.91 \pm 0.69552\), resulting in a confidence interval of \([7.21448, 8.60552]\).
04

95% CI for the Mean of 4 Analyses

For \(n = 4\), the 95% confidence interval is:\[ 7.91 \pm (1.96 \times \frac{0.27}{2}) \]The interval becomes \(7.91 \pm 0.2646\), resulting in \([7.6454, 8.1746]\).
05

99% CI for the Mean of 4 Analyses

For 99% confidence and \(n = 4\):\[ 7.91 \pm (2.576 \times \frac{0.27}{2}) \]The interval is \(7.91 \pm 0.34776\), resulting in \([7.56224, 8.25776]\).
06

95% CI for the Mean of 16 Analyses

For \(n = 16\), the 95% confidence interval is:\[ 7.91 \pm (1.96 \times \frac{0.27}{4}) \]This yields \(7.91 \pm 0.1323\), resulting in \([7.7777, 8.0423]\).
07

99% CI for the Mean of 16 Analyses

For 99% confidence and \(n = 16\):\[ 7.91 \pm (2.576 \times \frac{0.27}{4}) \]The interval becomes \(7.91 \pm 0.17388\), resulting in \([7.73612, 8.08388]\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Absorption Spectroscopy
Atomic Absorption Spectroscopy (AAS) is a technique used in analytical chemistry to determine the concentration of specific elements within a sample. It relies on the absorption of light by free atoms, typically metal ions, in a gaseous state. The process involves:
  • Atomizing the sample using a flame or other means.
  • Passing light of a specific wavelength through the vaporized sample.
  • Measuring the amount of light absorbed by the atoms, which is proportional to the concentration of the element in the sample.
AAS is particularly advantageous because it is highly sensitive and specific for metal ions. Copper determination in complex samples like fuels or oils can be performed efficiently using this method. It provides reliable results even when dealing with small concentrations, making it ideal for quality and regulatory assessments in various industries.
Confidence Interval
A confidence interval (CI) gives an estimated range of values that is likely to contain an unknown population parameter, such as a mean or proportion, with a certain level of confidence. It is a crucial concept in statistics used to express the reliability of an estimate.
  • The general form of a CI is: \( \text{Estimation} \pm \text{Margin of error} \).
  • The margin of error depends on the confidence level (often 95% or 99%) and the variability of the data.
The confidence level represents the frequency at which the true parameter would lie within this interval in a series of repeated samples. A 95% confidence interval suggests that in 95 out of 100 similar cases, the calculated range would capture the true mean. Calculating confidence intervals helps in understanding the precision and reliability of an analytical method, ensuring that decisions based on data are based on sound statistical evidence.
Pooled Standard Deviation
The pooled standard deviation is a method used in statistics to estimate the overall standard deviation from several different samples with similar variances. This allows combining results from multiple experiments or trials to provide a comprehensive measure of variability and is especially useful when the standard deviations across groups are unequal.
  • The formula combines standard deviations from individual groups, weighted by their sample sizes.
  • This calculation assumes that the different groups have a common but unknown population variance.
In analytical chemistry, using a pooled standard deviation helps achieve more accurate and reliable estimates, particularly when analyzing complex samples like oils or metallic solutions. It aggregates data from various measurements, enhancing the confidence in the resultant analyses.
Copper Determination
Copper determination is a common analytical task, particularly in industries dealing with metals, fuels, and electronic goods. Methods like Atomic Absorption Spectroscopy are often employed due to their sensitivity and accuracy for detecting trace elements.
  • The process involves preparing samples, often using acids to dissolve metals into a measurable liquid form.
  • Through AAS, the copper concentration is determined based on the absorption of light by copper atoms in the gas phase.
  • Results are reported in micrograms per milliliter (\( \mu \text{g/mL} \)), reflecting the concentration of copper in the sample.
Accurate copper determination is vital for ensuring product quality and regulatory compliance, particularly in sectors where metal content affects performance or safety. Understanding the precise amount of copper can aid in process control, environmental monitoring, and safety assessments.

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Most popular questions from this chapter

The homogeneity of the chloride level in a water sample from a lake was tested by analyzing portions drawn from the top and from near the bottom of the lake, with the following results in \(\mathrm{ppm} \mathrm{Cl}\) : $$ \begin{array}{cc} \text { Top } & \text { Bottom } \\ \hline 26.30 & 26.22 \\ 26.43 & 26.32 \\ 26.28 & 26.20 \\ 26.19 & 26.11 \\ 26.49 & 26.42 \\ \hline \end{array} $$ (a) Apply the \(t\) test at the \(95 \%\) confidence level to determine if the chloride level from the top of the lake is different from that at the bottom. (b) Now use the paired \(t\) test and determine whether there is a significant difference between the top and bottom values at the \(95 \%\) confidence level. (c) Why is a different conclusion drawn from using the paired \(t\) test than from just pooling the data and using the normal \(t\) test for differences in means?

The level of a pollutant in a river adjacent to a chemical plant is regularly monitored. Over a period of years, the normal level of the pollutant has been established by chemical analyses. Recently, the company has made several changes to the plant that appear to have increased the level of the pollutant. The Environmental Protection Agency (EPA) wants conclusive proof that the pollutant level has not increased. State the relevant null and alternative hypotheses and describe the type I and type II errors that might occur in this situation.

An atomic absorption method for the determination of the amount of iron present in used jet engine oil was found from pooling 30 triplicate analyses to have a standard deviation \(s=3.6 \mu \mathrm{g} \mathrm{Fe} / \mathrm{mL}\). If \(s\) is a good estimate of \(\sigma\), calculate the 95 and \(99 \%\) confidence intervals for the result \(18.5 \mu \mathrm{g} \mathrm{Fe} / \mathrm{mL}\) if it was based on (a) a single analysis, (b) the mean of two analyses, and (c) the mean of four analyses.

Determination of phosphorous in blood serum gave results of \(4.40,4.42,4.60,4.48\), and \(4.50 \mathrm{ppm}\) P. Determine whether the \(4.60 \mathrm{ppm}\) result is an outlier or should be retained at the \(95 \%\) confidence level.

Two different analytical methods were used to determine residual chlorine in sewage effluents. Both methods were used on the same samples, but each sample came from various locations with differing amounts of contact time with the effluent. Two methods were used to determine the concentration of \(\mathrm{Cl}\) in \(\mathrm{mg} / \mathrm{L}\), and the results are shown in the following table: $$ \begin{array}{ccc} \text { Sample } & \text { Method A } & \text { Method B } \\ \hline 1 & 0.39 & 0.36 \\ 2 & 0.84 & 1.35 \\ 3 & 1.76 & 2.56 \\ 4 & 3.35 & 3.92 \\ 5 & 4.69 & 5.35 \\ 6 & 7.70 & 8.33 \\ 7 & 10.52 & 10.70 \\ 8 & 10.92 & 10.91 \\ \hline \end{array} $$ (a) What type of \(t\) test should be used to compare the two methods and why? (b) Do the two methods give different results? State and test the appropriate hypotheses. (c) Does the conclusion depend on whether the \(90 \%\), \(95 \%\), or \(99 \%\) confidence levels are used?

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