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Why are the lines from a hollow-cathode lamp generally narrower than the lines emitted by atoms in a flame?

Short Answer

Expert verified
Hollow-cathode lamps have narrower lines because they operate in low-pressure conditions that minimize broadening effects.

Step by step solution

01

Understand the Hollow-Cathode Lamp

A hollow-cathode lamp is a type of discharge lamp used in atomic absorption spectroscopy. It consists of a cathode made of the element being analyzed, which emits characteristic lines when electricity passes through the lamp.
02

Understand Atomic Emission in a Flame

Atoms in a flame are excited due to the energy provided by the flame's heat, causing them to emit photons. The broadening of lines in such emissions can occur due to various factors, such as Doppler broadening and pressure broadening from the high-temperature environment.
03

Compare the Environments

The hollow-cathode lamp provides a controlled, low-pressure environment where the emission lines are affected less by Doppler and pressure broadening compared to a flame. This maintains a narrow line width.
04

Consider Pressure and Doppler Effects

In a flame, the high temperature causes atoms to move rapidly, leading to Doppler broadening, and the higher pressure often causes pressure broadening. These effects cause the emission lines to broaden, unlike in a hollow-cathode lamp.
05

Conclusion

Thus, the controllable conditions within a hollow-cathode lamp—such as pressure and temperature—result in narrower lines compared to those emitted by atoms in a flame, where broadened effects from temperature and pressure are more significant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hollow-Cathode Lamp
A hollow-cathode lamp is an essential tool used in atomic absorption spectroscopy. This kind of lamp allows scientists to analyze specific elements within a sample through the light it emits. The lamp contains a cathode, which is made of the same element you wish to measure. Inside the lamp, low-pressure gas is introduced, and when electricity passes through, it excites the atoms of the element in the cathode. These excited atoms then emit light at very precise wavelengths specific to that element.
The key advantage of a hollow-cathode lamp lies in its ability to produce extremely narrow emission lines. This narrowness is crucial because it reduces overlap with other spectral lines, improving the accuracy of measurements. The low-pressure environment in the lamp minimizes broadening effects, which means the wavelengths emitted are very close to their true values, ensuring precise and reliable measurements.
Emission Line Broadening
Emission line broadening occurs when the spectral lines produced by excited atoms are wider than they theoretically would be if observed in perfect conditions. Understanding the causes of broadening is important for scientists to interpret the spectral lines accurately. Several environmental factors contribute to the broadening of emission lines including:
  • Temperature variations
  • Pressure changes
  • Motion of atoms
In any environment where atoms are excited, these factors play a role. For instance, in flames, atoms are at high temperatures, leading to a variety of broadening effects that distort the measurements if not properly accounted for.
Doppler Broadening
Doppler broadening is one of the effects that cause emission lines to widen. It is linked to the movement of atoms or molecules within the gas that emits light. When atoms move towards or away from the observer, the light emitted experiences a slight shift in wavelength, a phenomenon known as the Doppler shift.
Consider atoms in a flame; these atoms move very fast due to high temperatures. As a result, some of the light waves get compressed or stretched, depending on whether those atoms are moving towards or away from you. This adds a wider spread to the emission line. In controlled environments, like those in hollow-cathode lamps, Doppler broadening effects are minimized due to lower temperatures and controlled movement of atoms, maintaining the sharpness of lines.
Pressure Broadening
Pressure broadening, also known as collisional broadening, arises because of the interactions between atoms or molecules in a gas when they collide. This type of broadening is influenced by the pressure of the environment because increased pressure usually means more frequent collisions.
In a scenario like a flame, which is under relatively high pressure, these collisions are more common, contributing to a significant broadening of emission lines. Conversely, in a hollow-cathode lamp, the environment is kept at low pressure, which greatly reduces the number of collisions and, as a result, minimizes the broadening effect. This is why the emission lines in a hollow-cathode lamp are notably narrower, allowing for more precise analytical results. By understanding and controlling the conditions that affect pressure broadening, the accuracy of spectral analysis is greatly enhanced.

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Most popular questions from this chapter

Challenge Problem: Seawater samples were examined by ICP-atomic emission spectrometry (ICP-AES) in a multielement study. Vanadium was one of the clements determined. Standard solutions in a synthetic seawater matrix were prepared and determined by ICP-AES. The following results were obtained: \begin{tabular}{cc} Concentration, pg/mL. & Intensity, arbitrary units \\ \hline \(0.0\) & \(2.1\) \\ \(2.0\) & \(5.0\) \\ \(4.0\) & \(9.2\) \\ \(6.0\) & \(12.5\) \\ \(8.0\) & \(17.4\) \\ \(10.0\) & \(20.9\) \\ \(12.0\) & \(24.7\) \\ \hline \end{tabular} (a) Determine the least-squares regression line. (b) Determine the standard deviations of the slope and intercept. (c) Test the hypothesis that the slope is equal to \(2.00\). (d) Test the hypothesis that the intercept is equal to \(2.00\). (e) Three seawater solutions gave readings for vandadium of \(3.5,10.7\), and \(15.9\). Determine their concentrations and the standard deviation of their concentrations. (f) Determine the \(95 \%\) confidence limits for the three unknowns in part (e). (g) Estimate the limit of detection for determining vanadium in seawater from the data (see Section 8D-1). Use a \(\mathrm{k}\) value of 3 in your DL estimate. (h) The second seawater sample with a reading of \(10.7\) units was a certified reference standard with a known vanadium concentration of \(5.0 \mathrm{pg} / \mathrm{mL}\). What was the absolute and percent error in its determination? (i) Test the hypothesis that the value determined in part (e) for the second seawater sample (reading of \(10.7)\) is identical to the certified concentration of \(5.0 \mathrm{pg} / \mathrm{mL}\).

Why are ionization interferences usually not as severe in the ICP as they are in flames?

A 5.00-mL sample of blood was treated with trichloroacetic acid to precipitate proteins. After centrifugation, the resulting solution was brought to \(\mathrm{pH} 3\) and extracted with two 5-mL portions of methyl isobutyl ketone containing the lead-complexing agent APCD. The extract was aspirated directly into an air/acetylene flame and yielded an absorbance of \(0.502\) at \(283.3 \mathrm{~nm}\). Five-milliliter aliquots of standard solutions containing \(0.400\) and \(0.600 \mathrm{ppm}\) of lead were treated in the same way and yielded absorbances of \(0.396\) and \(0.599\). Find the concentration of lead in the sample in Ppm arsuming that Beer's law is followed.

Describe the basic differences among atomic emission, atomic absorption, and atomic fluorescence spectroscopy.

The copper in an aqueous sample was determined by atomic absorption flame spectrometry. First, \(10.0 \mathrm{~mL}\) of the unknown were pipetted into each of five \(50.0-\mathrm{mL}\). volumetric flasks. Various volumes of a standard containing \(12.2 \mathrm{Ppm} \mathrm{Cu}\) were added to the flasks, and the solutions were then diluted to volume. \begin{tabular}{ccc} Unknown, mL & Standard, mL & Abserbance \\ \hline \(10.0\) & \(0.0\) & \(0.201\) \\ \(10.0\) & \(10.0\) & \(0.292\) \\ \(10.0\) & \(20.0\) & \(0.378\) \\ \(10.0\) & \(30.0\) & \(0.467\) \\ \(10.0\) & \(40.0\) & \(0.554\) \\ \hline \end{tabular} (a) Plot absorbance as a function of volume of standard. *(b) Derive an expression relating absorbance to the concentrations of standard and unknown \(\left(c_{j}\right.\) and \(\left.c_{k}\right)\). and the volumes of the standards and unknown \(\left(V_{u}\right.\) and \(\left.V_{x}\right)\) as well as the volume to which the solutions were diluted \(\left(V_{k}\right)\). "(c) Derive expressions for the slope and the intercept of the straight line obtained in (a) in terms of the variables listed in (b). (d) Show that the concentration of the analyte is given by the relationship \(c_{x}=b c / m V_{x}\), where \(m\) and \(b\) are the slope and the intercept of the straight line in (a). *(e) Determine values for \(m\) and \(b\) by the method of least squares. (f) Calculate the standard deviation for the slope and the intercept in (e). * \((\mathrm{g})\) Calculate the copper concentration in Ppm Cu in the eample using the relationship given in (d).

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