Chapter 7: Problem 34
Examine the following formulas. Which compound has the (a) lower percent by mass of chlorine: \(\mathrm{NaClO}_{3}\) or \(\mathrm{KClO}_{3}\) ? (b) higher percent by mass of sulfur: \(\mathrm{KHSO}_{4}\) or \(\mathrm{K}_{2} \mathrm{SO}_{4}\) ? (c) lower percent by mass of chromium: \(\mathrm{Na}_{2} \mathrm{CrO}_{4}\) or \(\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) ?
Short Answer
Step by step solution
Calculate Molar Mass - NaClO₃
Calculate Percent Mass of Chlorine in NaClO₃
Calculate Molar Mass - KClO₃
Calculate Percent Mass of Chlorine in KClO₃
Compare Percent Mass of Chlorine
Calculate Molar Mass - KHSOâ‚„
Calculate Percent Mass of Sulfur in KHSOâ‚„
Calculate Molar Mass - Kâ‚‚SOâ‚„
Calculate Percent Mass of Sulfur in Kâ‚‚SOâ‚„
Compare Percent Mass of Sulfur
Calculate Molar Mass - Naâ‚‚CrOâ‚„
Calculate Percent Mass of Chromium in Naâ‚‚CrOâ‚„
Calculate Molar Mass - Na₂Cr₂O₇
Calculate Percent Mass of Chromium in Na₂Cr₂O₇
Compare Percent Mass of Chromium
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
molar mass
For example, to calculate the molar mass of \(\text{NaClO}_3\), you have:
- Sodium (Na) = 22.99 g/mol
- Chlorine (Cl) = 35.45 g/mol
- Oxygen (O) = 16.00 g/mol (and there are 3 oxygens in the compound)
\text{22.99 + 35.45 + 3 \(\times 16.00\)} = 106.44 g/mol
Understanding molar mass helps in calculating other key properties, such as percent composition and stoichiometry.
chemical formulas
They are essential for determining the molar mass and percent composition of a compound. Each element in a formula has an associated atomic mass, which you sum to find the molar mass. In our example, for \(\text{KClO}_3\), the formula tells us there is:
- 1 Potassium (K)
- 1 Chlorine (Cl)
- 3 Oxygens (O)
Remember, the subscripts in the chemical formulas are vital as they indicate the ratio in which elements combine to form a compound.
percent by mass
\[ \text{Percent by mass of Element} = \frac{\text{Mass of Element in 1 mole of compound}}{\text{Molar Mass of compound}} \ \times 100 \] For example, to find the percent by mass of chlorine in \(\text{KClO}_3\):
- Calculate the molar mass: \text{122.55 g/mol}
- Mass of Cl in the compound: \text{35.45 g/mol}
\[ \text{Percent by mass of Cl} = \frac{\text{35.45}}{\text{122.55}} \ \times 100 = 28.9\text{%} \] This tells you that chlorine makes up 28.9% of the mass of \(\text{KClO}_3\). Understanding percent by mass is vital for characterizing the composition of compounds.