/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Sulfur dioxide is oxidized to su... [FREE SOLUTION] | 91Ó°ÊÓ

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Sulfur dioxide is oxidized to sulfur trioxide in a small pilot-plant reactor. SO \(_{2}\) and \(100 \%\) excess air are fed to the reactor at \(450^{\circ} \mathrm{C}\). The reaction proceeds to a \(65 \% \mathrm{SO}_{2}\) conversion, and the products emerge from the reactor at \(550^{\circ} \mathrm{C}\). The production rate of \(\mathrm{SO}_{3}\) is \(1.00 \times 10^{2} \mathrm{kg} / \mathrm{min}\). The reactor is surrounded by a water jacket into which water at \(25^{\circ} \mathrm{C}\) is fed. (a) Calculate the feed rates (standard cubic meters per second) of the \(\mathrm{SO}_{2}\) and air feed streams and the extent of reaction, \(\xi\) (b) Calculate the standard heat of the SO_ oxidation reaction, \(\Delta H_{\mathrm{t}}^{\mathrm{r}}(\mathrm{kJ}) .\) Then, taking molecular species at \(25^{\circ} \mathrm{C}\) as references, prepare and fill in an inlet-outlet enthalpy table and write an energy balance to calculate the necessary rate of heat transfer ( \(\mathrm{kW}\) ) from the reactor to the cooling water. (c) Calculate the minimum flow rate of the cooling water if its temperature rise is to be kept below \(15^{\circ} \mathrm{C}\) (d) Briefly state what would have been different in your calculations and results if you had taken elemental species as references in Part (b).

Short Answer

Expert verified
The feed rates of \(SO_2\) and air are \(153.85 kmol/min\) and \(307.7 kmol/min\) respectively. The standard heat of reaction, amount of heat transfer and minimum water cooling rate would be determined based on the given feed rate, conversion, and reaction data. The results would have been different if elemental species are considered as reference in the calculation.

Step by step solution

01

Determine the feed rates

Given production rate of \(SO_3\) is \(1.00 \times 10^2 kmol/min\) which means in each minute, \(1.00 \times 10^2 kmol\) of \(SO_2\) are getting converted to \(SO_3\). Since the feed contains 100% excess air, conversion of \(SO_2\) is less than expected. Since conversion rate is 65%, actual feed rate of \(SO_2\) is \(1.00 \times 10^2 kmol/min / 0.65 = 153.85 kmol/min\). Therefore, the feed rates of \(SO_2\) and air are \(153.85 kmol/min\) and \(307.7 kmol/min\) respectively.
02

Calculate the heat of reaction

Heat of reaction \(\Delta H_{t}^r\) for the reaction \(SO_2 + 0.5O_2 → SO_3\) can be obtained from the standard heat of formation of the reactants and products. \(\Delta H_{t}^ {r} = Heat of formation of products – Heat of formation of reactants\). The standard heat of reaction is now used to determine the energy flow from the reactor to the cooling water by setting up an enthalpy table for the inlet and outlet streams and writing the energy balance around the reactor.
03

Calculate cooling water flow rate

The rate of heat transfer from the reactor to the cooling system can be calculated using \(q=mc\Delta t\), where \(m\) is the cooling water flow rate, \(c\) is the specific heat of water, and \(\Delta t\) is the temperature difference. This equation gives the minimum flow rate of cooling water needed to keep the temperature rise below \(15^{\circ}C\).
04

Analyses of different reference states

If the calculation was using elemental species as reference, the energy of heat transfer would have been calculated based on the heat of formation values which are zero for the elements in their standard states at the reference temperature. This modification would have changed the energy balance equation and therefore the calculated rate of heat transfer. The conversion rate and feed rates would still be same, but the heat of reaction, and therefore the rate of heat transfer and the cooling water flow rate would have been different.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sulfur Dioxide Oxidation
Sulfur dioxide oxidation is a crucial reaction in chemical engineering, particularly in the production of sulfuric acid. This reaction involves the conversion of sulfur dioxide (SO\(_2\)) to sulfur trioxide (SO\(_3\)) using oxygen available in excess air. In the described pilot-plant reactor, the conversion efficiency of SO\(_2\) is 65%. This means that 65% of the sulfur dioxide introduced to the reactor is transformed into sulfur trioxide. Oxidation reactions like this one are significant because they determine the effectiveness and efficiency of industrial processes.
One important aspect of this reaction to notice is the excess use of air. This implies that there is more oxygen available than what is necessary to react with the sulfur dioxide. This ensures the reaction goes to completion as much as possible, minimizing leftover reactants.
Conversion percentage is a key parameter that affects the design and operation of chemical reactors, determining the required feed rates and the overall economic feasibility of the process. Thus, understanding and optimizing this aspect is fundamental to chemical reaction engineering.
Heat of Reaction
The heat of reaction is the heat energy absorbed or released during a chemical reaction. For the sulfur dioxide oxidation reaction, it is important to determine this energy change as it directly affects the reactor operation and its thermal management.
To calculate the heat of reaction (\(\Delta H_{rxn}\),for the oxidation of SO\(_2\) to SO\(_3\), start by considering the standard heat of formation for the reactants and products. These values are typically obtained from thermodynamic tables. The formula used is:\[\Delta H_{rxn} = \text{heat of formation of products} - \text{heat of formation of reactants}\]Due to its impact on energy balance calculations, understanding the heat of reaction is crucial. It dictates whether the process is exothermic (releasing heat) or endothermic (absorbing heat). This energy change helps in designing systems to manage the thermal effects generated during the reaction, often requiring the implementation of cooling systems.
Energy Balance
Energy balance is a fundamental concept in chemical reaction engineering, ensuring that all energy inputs and outputs within a process are accounted for. In this context, it deals with achieving a balance between the energy supplied to the system and the energy absorbed or released during the chemical reaction.
Creating an enthalpy table for the inlet and outlet streams is the first step to writing an energy balance for the reactor. This table lists all the thermal energies of each component entering and leaving the system, based on their specific heat capacities and temperatures.
From there, the energy balance equation can be formulated. This includes the sum of all energies entering the system equated to the sum of the energies leaving the system, along with the energy either absorbed or released by the reaction. This helps in calculating the necessary rate of heat transfer to manage the reactor temperature, which is vital for safe and efficient operation.
Cooling Water Flow Rate
The cooling water flow rate is a key operational parameter in chemical reactors, especially those involving exothermic reactions like sulfur dioxide oxidation. The primary function of cooling water is to remove excess heat from the reactor, preventing overheating and ensuring optimal reaction conditions.
This involves applying the principle of heat transfer, where the equation is expressed as:\[q = mc\Delta T\]Here, \(q\) represents the heat removal rate, \(m\) is the flow rate of the cooling water, \(c\) is the specific heat capacity of water, and \(\Delta T\) is the permissible temperature rise of the water.
In this scenario, the goal is to keep the cooling water's temperature change below 15°C. By substituting known values into the equation, one can solve for the minimum cooling water flow rate necessary. Proper adjustment of this flow rate is essential in maintaining the reactor's stability and preventing any negative impacts on the reaction performance or safety.

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Most popular questions from this chapter

Methane is burned completely with 40\% excess air. The methane enters the combustion chamber at \(25^{\circ} \mathrm{C},\) the combustion air enters at \(150^{\circ} \mathrm{C},\) and the stack gas \(\left[\mathrm{CO}_{2}, \mathrm{H}_{2} \mathrm{O}(\mathrm{v}), \mathrm{O}_{2}, \mathrm{N}_{2}\right]\) exits at \(450^{\circ} \mathrm{C} .\) The chamber functions as a preheater for an air stream flowing in a pipe through the chamber to a spray dryer. The air enters the chamber at \(25^{\circ} \mathrm{C}\) at a rate of \(1.57 \times 10^{4} \mathrm{m}^{3}(\mathrm{STP}) / \mathrm{h}\) and is heated to \(181^{\circ} \mathrm{C}\). All of the heat generated by combustion is used to heat the combustion products and the air going to the spray dryer (i.e., the combustion chamber may be considered adiabatic). (a) Draw and completely label the process flow diagram and perform a degree- of-freedom analysis. (b) Calculate the required molar flow rates of methane and combustion air (kmol/h) and the volumetric flow rates \(\left(\mathrm{m}^{3} / \mathrm{h}\right)\) of the two effluent streams. State all assumptions you make. (c) When the system goes on line for the first time, environmental monitoring of the stack gas reveals a considerable quantity of CO, suggesting a problem with either the design or the operation of the combustion chamber. What changes from your calculated values would you expect to see in the temperatures and volumetric flow rates of the effluent streams [increase, decrease, cannot tell without doing the calculations]?

An ultimate analysis of a coal is a series of operations that yields the percentages by mass of carbon, hydrogen, nitrogen, oxygen, and sulfur in the coal. The heating value of a coal is best determined in a calorimeter, but it may be estimated with reasonable accuracy from the ultimate analysis using the Dulong formula: $$H H V(\mathrm{k} J / \mathrm{kg})=33,801(\mathrm{C})+144,158[(\mathrm{H})-0.125(\mathrm{O})]+9413(\mathrm{S})$$ where (C), (H), (O), and (S) are the mass fractions of the corresponding elements. The 0.125(O) term accounts for the hydrogen bound in the water contained in the coal. (a) Derive an expression for the higher heating value ( \(H H V\) ) of a coal in terms of \(\mathrm{C}, \mathrm{H}, \mathrm{O},\) and \(\mathrm{S},\) and compare your result with the Dulong formula. Suggest a reason for the difference. (b) A coal with an ultimate analysis of \(75.8 \mathrm{wt} \% \mathrm{C}, 5.1 \% \mathrm{H}, 8.2 \% \mathrm{O}, 1.5 \% \mathrm{N}, 1.6 \% \mathrm{S},\) and \(7.8 \%\) ash (noncombustible) is burned in a power-plant boiler fumace. All of the sulfur in the coal forms \(\mathrm{SO}_{2}\) The gas leaving the furnace is fed through a tall stack and discharged to the atmosphere. The ratio \(\phi\) (\(\mathrm{kg} \mathrm{SO}_{2}\) in the stack gas/kJ heating value of the fuel) must be below a specified value for the power plant to be in compliance with Environmental Protection Agency regulations regarding sulfur emissions. Estimate \(\phi\), using the Dulong formula for the heating value of the coal. (c) An earlier version of the EPA regulation specified that the mole fraction of \(\mathrm{SO}_{2}\) in the stack gas must be less than a specified amount to avoid a costly fine and the required installation of an expensive stack gas scrubbing unit. When this regulation was in force, a few unethical plant operators blew clear air into the base of the stack while the furnace was operating. Briefly explain why they did so and why they stopped this practice when the new regulation was introduced.

Calcium chloride is a salt used in a number of food and medicinal applications and in brine for refrigeration systems. Its most distinctive property is its affinity for water. in its anhydrous form it efficiently absorbs water vapor from gases, and from aqueous liquid solutions it can form (at different conditions) calcium chloride hydrate \(\left(\mathrm{CaCl}_{2} \cdot \mathrm{H}_{2} \mathrm{O}\right)\) dihydrate \(\left(\mathrm{CaCl}_{2} \cdot 2 \mathrm{H}_{2} \mathrm{O}\right)\) tetrahydrate \(\left(\mathrm{CaCl}_{2} \cdot 4 \mathrm{H}_{2} \mathrm{O}\right),\) and hexahydrate \(\left(\mathrm{CaCl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O}\right)\) You have been given the task of determining the standard heat of the reaction in which calcium chloride hexahydrate is formed from anhydrous calcium chloride: $$\mathrm{CaCl}_{2}(\mathrm{s})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{CaCl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O}(\mathrm{s}): \quad \Delta H_{\mathrm{r}}^{\circ}(\mathrm{k} \mathrm{J})=?$$ By definition, the desired quantity is the heat of hydration of calcium chloride hexahydrate. You cannot carry out the hydration reaction directly, so you resort to an indirect method. You first dissolve 1.00 mol of anhydrous \(\mathrm{CaCl}_{2}\) in \(10.0 \mathrm{mol}\) of water in a calorimeter and determine that \(64.85 \mathrm{kJ}\) of heat must be transferred away from the calorimeter to keep the solution temperature at \(25^{\circ} \mathrm{C}\). You next dissolve 1.00 mol of the hexahydrate salt in 4.00 mol of water and find that 32.1 kJ of heat must be transferred to the calorimeter to keep the temperature at \(25^{\circ} \mathrm{C}\). (a) Use these results to calculate the desired heat of reaction. (Suggestion: Begin by writing out the stoichiometric equations for the two dissolution processes.) (b) Calculate the standard heat of reaction in \(\mathrm{kJ}\) for \(\mathrm{Ca}(\mathrm{s}), \mathrm{Cl}_{2}(\mathrm{g})\) and \(\mathrm{H}_{2} \mathrm{O}\) reacting to form \(\mathrm{CaCl}_{2}\) (aq, \(r=10\) ). (c) Speculate about why the standard heat of reaction in forming calcium chloride hexahydrate cannot be measured directly by reacting the anhydrous salt with water in a calorimeter.

Synthetically produced ethanol is an important industrial commodity used for various purposes, including as a solvent (especially for substances intended for human contact or consumption); in coatings, inks, and personal-care products; for sterilization; and as a fuel. Industrial cthanol is a petrochemical synthesized by the hydrolysis of ethylene: $$\mathrm{C}_{2} \mathrm{H}_{4}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{v}) \rightleftharpoons \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(\mathrm{v})$$ Some of the product is converted to diethyl ether in the undesired side reaction $$2 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(\mathrm{v}) \rightleftharpoons\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{O}(\mathrm{v})+\mathrm{H}_{2} \mathrm{O}(\mathrm{v}) $$The combined feed to the reactor contains 53.7 mole \(\% \mathrm{C}_{2} \mathrm{H}_{4}, 36.7 \% \mathrm{H}_{2} \mathrm{O}\) and the balance nitrogen, and enters the reactor at \(310^{\circ} \mathrm{C}\). The reactor operates isothermally at \(310^{\circ} \mathrm{C}\). An ethylene conversion of \(5 \%\) is achieved, and the yield of ethanol (moles cthanol produced/mole cthylene consumed) is 0.900 . Data for Diethyl Ether $$\begin{aligned}&\Delta \hat{H}_{f}^{\circ}=-271.2 \mathrm{kJ} / \mathrm{mol} \text { for the liquid }\\\ &\left.\Delta \hat{H}_{v}=26.05 \mathrm{kJ} / \mathrm{mol} \quad \text { (assume independent of } T\right)\end{aligned}$$ $$C_{p}\left[\mathrm{kJ} /\left(\mathrm{mol} \cdot^{\circ} \mathrm{C}\right)\right]=0.08945+40.33 \times 10^{-5} T\left(^{\circ} \mathrm{C}\right)-2.244 \times 10^{-7} T^{2}$$ (a) Calculate the reactor heating or cooling requirement in \(\mathrm{kJ} / \mathrm{mol}\) feed. (b) Why would the reactor be designed to yield such a low conversion of ethylene? What processing step (or steps) would probably follow the reactor in a commercial implementation of this process?

A methanol-synthesis reactor is fed with a gas stream at \(220^{\circ} \mathrm{C}\) consisting of 5.0 mole\% methane, \(25.0 \%\) CO, \(5.0 \% \mathrm{CO}_{2},\) and the remainder hydrogen. The reactor and feed stream are at \(7.5 \mathrm{MPa}\). The primary reaction occurring in the reactor and its associated equilibrium constant are $$\begin{array}{l}\mathrm{CO}+2 \mathrm{H}_{2} \rightleftharpoons \mathrm{CH}_{3} \mathrm{OH} \\\K=\frac{y_{\mathrm{CH}, \mathrm{OH}} y_{\mathrm{H}_{2}}}{y_{\mathrm{CO}} y_{H_{2}}^{2} P^{2}}=\exp \left(\begin{array}{c}21.225+\frac{9143.6}{T}-7.492 \ln T \\ +4.076 \times 10^{-3} T-7.161 \times 10^{-8} T^{2}\end{array}\right)\end{array}$$ where \(T\) is in kelvins. The product stream may be assumed to reach equilibrium at \(250^{\circ} \mathrm{C}\). (a) Determine the composition (mole fractions) of the product stream and the percentage conversions of CO and \(\mathrm{H}_{2}\). (b) Neglecting the effect of pressure on enthalpies, estimate the amount of heat (kJ/mol feed gas) that must be added to or removed from (state which) the reactor. (c) Calculate the extent of reaction and heat removal rate (kJ/mol feed) for reactor temperatures between \(200^{\circ} \mathrm{C}\) and \(400^{\circ} \mathrm{C}\) in \(50^{\circ} \mathrm{C}\) increments. Use these results to obtain an estimate of the adiabatic reaction temperature. (d) Determine the effect of pressure on the reaction by evaluating extent of conversion and rate of heat transfer at \(1 \mathrm{MPa}\) and \(15 \mathrm{MPa}\). (e) Considering the results of your calculations in Parts (c) and (d), propose an explanation for selection of the initial reaction conditions of \(250^{\circ} \mathrm{C}\) and \(7.5 \mathrm{MPa}\).

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