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Polyvinylpyrrolidone (PVP) is a polymer product used as a binding agent in pharmaceutical applications as well as in personal-care items such as hairspray. In the manufacture of \(\mathrm{PVP}\), a spray-drying process is used to collect solid PVP from an aqueous suspension, as shown in the flowchart on the next page. A liquid solution containing 65 wt\% \(\mathrm{PVP}\) and the balance water at \(25^{\circ} \mathrm{C}\) is pumped through an atomizing nozzle at a rate of \(1500 \mathrm{kg} / \mathrm{h}\) into a stream of preheated air flowing at a rate of \(1.57 \times 10^{4}\) SCMH. The water evaporates into the stream of hot air and the solid PVP particles are suspended in the humidified air. Downstream, the particles are separated from the air with a filter and collected. The process is designed so that the exiting solid product and humid air are in thermal equilibrium with each other at \(110^{\circ} \mathrm{C}\). For convenience, the spray-drying and solid- separation processes are shown as one unit that may be considered adiabatic. (a) Draw and completely label the process flow diagram and perform a degree- of-freedom analysis. (b) Calculate the required temperature of the inlet air, \(T_{0}\), and the volumetric flow rate \(\left(\mathrm{m}^{3} / \mathrm{h}\right)\) and relative humidity of the exiting air. Assume that the polymer has a heat capacity per unit mass one third that of liquid water, and only use the first two terms of the polynomial heat-capacity formula for air in Table B.2. (c) Why do you think the polymer solution is put through an atomizing nozzle, which converts it to a mist of tiny droplets, rather than being sprayed through a much less costly nozzle of the type commonly found in showers? (d) Due to a design flaw, the polymer solution does not remain in the dryer long enough for all the water to evaporate, so the solid product emerging from the separator is a wet powder. How will this change the values of the outlet temperatures of the emerging gas and powder and the volumetric flow rate and relative humidity of the emerging gas (increase, decrease, can't tell without doing the calculations)? Explain your answers.

Short Answer

Expert verified
The atomizing nozzle is used to create tiny droplets, thereby increasing the surface area available for evaporation leading to effective drying. Incomplete drying could alter the outlet temperatures, volumetric flow rate, and relative humidity of the emerging gas due to changes in heat and mass balance equations. Exact values would depend on the specific amount of water not evaporated.

Step by step solution

01

Process flowchart and Degree of Freedom Analysis

Start by sketching a flowchart for the entire process as described in the problem statement. The system is adiabatic, which essentially means there is no energy exchange with the environment, hence no heat loss. For degree of freedom analysis, count the number of process variables against the number of available independent equations.
02

Calculation of inlet air Temperature

Use the heat capacity formula and heat balance equation to compute the inlet temperature of air. Since the process is in thermal equilibrium, incoming heat (from hot air and the solution) equals outcoming heat (from dry PVP and exiting air).
03

Exit Air’s Volumetric Flow Rate and Relative Humidity

Apply the ideal gas law to calculate the volumetric flow rate. Use the water balance to calculate the mass fraction of water in the exit air, and from this, the relative humidity can be determined.
04

Necessity of Atomizing Nozzle

The atomizing nozzle helps to create small droplets, thereby increasing the surface area to enhance the evaporation rate. The atomizing nozzle is crucial to achieve fast and efficient drying.
05

Effect of Incomplete Drying on Process Parameters

If not all the water is evaporated, it means the heat provided was spent on heating the exit air and PVP as well as evaporating some water. This would change the outlet temperatures, volumetric flow rate, and relative humidity of the emerging gas. The exact change would depend upon the amount of water remaining to be evaporated and needs to be derived from calculations using modified versions of the heat and mass balance equations used earlier.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degree of Freedom Analysis
In chemical process engineering, performing a degree of freedom analysis is essential to understand the complexity and solvability of any given system. It involves comparing the number of unknown variables in a system against the number of independent equations that can be formulated. Each degree of freedom is essentially an independent variable that can be adjusted without violating the physical laws governing the system.
  • If the degree of freedom is zero, the system can be completely determined using the given equations and parameters.
  • A positive degree of freedom indicates extra variables for which data or parameters should be specified.
  • A negative degree of freedom shows that there are more equations than variables, suggesting an over-specified or inconsistent system.
In the PVP manufacturing process described, the system includes inputs like mass flow rates and temperatures, while relying on mass and energy balance equations. With an adiabatic assumption, the system simplifies, focusing primarily on mass transfer between the liquid and gaseous phases without heat exchange with the environment.
Heat Capacity
Heat capacity is a fundamental concept that defines the amount of heat required to change a substance's temperature by a certain amount. In the context of the PVP manufacturing process, understanding the heat capacity of different components like liquid polymer and air is key to calculating the system's thermal dynamics.
Various substances have different heat capacities which reflect their ability to absorb heat energy. In this scenario, the heat capacity of air and PVP are calculated to ensure temperature regulation throughout the process. The inputs for temperature adjustments rely on initial heat capacities:
  • Heat capacity per unit mass for air is considered from available data charts.
  • The PVP's heat capacity is approximately one-third of that of liquid water, indicating its lower capacity to hold heat.
This differentiation is crucial for performing thermal calculations needed to analyze how much heat will be absorbed by the water, PVP, and air – determining the inlet and outlet air temperatures.
Relative Humidity
Relative humidity is the measure of the amount of water vapor present in air relative to the amount it could hold at maximum capacity. It's expressed as a percentage and is crucial for processes involving drying and evaporation.
In the spray-drying of PVP, relative humidity helps in understanding the air's moisture absorption capacity as it exits the system with humidified hot air.
  • A drop in relative humidity could mean that air is capable of holding more water vapor, making it dry again.
  • An increase signifies saturated air, indicating efficient evaporation of moisture.
The calculations involve using the moist air properties and mass balances to find out how saturated the leaving air is compared to its maximum capacity. The relative humidity influences how effectively the spray-drying process dehydrates the polymer solution, crucial for ensuring quality in PVP production.
Spray Drying
Spray drying is a method of producing a dry powder from a liquid by rapidly drying with a hot gas. It’s a preferred technique in industries for thermal-sensitive materials where ideal temperature and humidity play a crucial role. The principle is simple yet efficient; the solution is atomized into a mist, which significantly increases surface area and improves heat and mass transfer rates.
Major advantages of spray drying include:
  • Fast drying rates due to high surface area.
  • Controlled particle size for specific end-use requirements.
  • Preservation of material due to minimal thermal degradation.
This technique is vital for PVP production, ensuring that the polymer remains intact while the required amount of water is evaporated to form a precise powder consistency.
Polyvinylpyrrolidone (PVP) Manufacturing
Polyvinylpyrrolidone, or PVP, is an important polymer used widely in pharmaceuticals and personal care products. The production process often involves spray drying, capturing solid PVP from solutions while maintaining its stability and quality.
The PVP manufacturing process entails several critical steps including correct formulation of the polymer-water solution, meticulous temperature control, and efficient particle separation methods. Such precision enhances the product's strength as a binding and film-forming agent.
  • Using an atomizing nozzle instead of a simpler spray system optimizes droplet size for consistent drying.
  • Ensuring proper thermal balance prevents thermal degradation and preserves PVP's benefit.
These considerations are crucial for achieving the desired product characteristics, which include solubility, adhesive capacity, and minimal impurities for pharmaceutical standards.

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Most popular questions from this chapter

Fish and wildlife managers have determined that a sudden temperature increase greater than \(5^{\circ} \mathrm{C}\) would be harmful to the marine ecosystem of a river. Warmer waters contain less dissolved oxygen and cause organisms in a river to increase their metabolism; if the temperature increase is sudden, the organisms do not have time to adapt to the new environment and likely will die. (Changes in river temperatures of five degrees and more due to seasonal temperature variations are common, but those temperature changes are gradual.) A proposed chemical plant plans to use river water for process cooling. The river flows at a rate of \(15.0 \mathrm{m}^{3} / \mathrm{s}\) at a temperature of \(15^{\circ} \mathrm{C}\), and a fraction of it will be diverted to the plant. Preliminary calculations reveal that the cooling water will remove \(5.00 \times 10^{5} \mathrm{kJ} / \mathrm{s}\) of heat from the plant. A portion of the extracted water will evaporate from the plant into the atmosphere, and the remainder will be returned to the river at a temperature of \(35^{\circ} \mathrm{C}\). (a) Draw and completely label a flowchart of the process and prove that there is enough information available to calculate all of the unknown stream flow rates on the chart. (b) Estimate the fraction of the river flow that must be diverted to the plant and the percentage of the cooling water that evaporates. Assume that water has a constant heat capacity of \(4.19 \mathrm{kJ} /\left(\mathrm{kg} \cdot^{\circ} \mathrm{C}\right)\) and a heat of vaporization roughly that of water at the normal boiling point, and also assume that the specific enthalpy of the water vapor relative to liquid water at \(15^{\circ} \mathrm{C}\) equals the heat of vaporization. (c) Write (but don't evaluate) an expression for the enthalpy change neglected by the assumption about the specific enthalpy of the steam.

The flow of groundwater often plagues construction of tunnels and other underground systems. Dne way of preventing it is with an ice seal-freezing the water in the soil so that the ice formed is a barrier to water movement. Such a structure was planned for the Fukushima TEPCO nuclear power plant, which was severely damaged by a 2011 tsunami that created a tremendous environmental challenge. A major concern was potential contamination with radioactive isotopes of groundwater flowing under the plant and into the ocean. A proposal under consideration was to channel the flow around the plant by forming an ice dam with a 1,400 -meter perimeter, a depth of \(30 \mathrm{m},\) and a thickness of approximately \(2 \mathrm{m}\). This was to be done by pumping a brine solution at a temperature of \(-40^{\circ} \mathrm{C}\) though vertical pipes spaced at \(1-\mathrm{m}\) intervals. The brine would exit at a temperature no greater than \(-25^{\circ} \mathrm{C}\). To keep ambient temperature fluctuations from causing occasional melting, the dam was to have a mean temperature of about \(-20^{\circ} \mathrm{C}\). (a) Estimate the average cooling rate (kW) and associated flow rate of brine (L/min) required to complete formation of the dam within 60 days of starting the refrigeration system. State and give your rationale for each of the assumptions and/or approximations necessary to obtain your result. (b) From a suitable reference, for which you must provide a citation, find an estimate of the ratio of the heat removed to the work done by a refrigeration system. Use the value to estimate the power usage during the time the dam is being created. (c) It is expected that substantially less power will be used once the dam has been formed. Explain. (d) Identify the primary radioactive species that were of greatest concern regarding contamination of the groundwater. (e) Explosions of hydrogen occurred in the power plants after the cooling water system was shut down upon being flooded by the tsunami. What was the source of the hydrogen? Describe the scenario that led to hydrogen formation.

The heat required to raise the temperature of \(m\) (kg) of a liquid from \(T_{1}\) to \(T_{2}\) at constant pressure is $$ Q=\Delta H=m \int_{T_{1}}^{T_{2}} C_{p}(T) d T $$ In high school and in first-year college physics courses, the formula is usually given as $$ Q=m C_{p} \Delta T=m C_{p}\left(T_{2}-T_{1}\right) $$ (a) What assumption about \(C_{p}\) is required to go from Equation 1 to Equation \(2 ?\) (b) The heat capacity \(\left(C_{p}\right)\) of liquid \(n\) -hexane is measured in a bomb calorimeter. A small reaction flask (the bomb) is placed in a well- insulated vessel containing \(2.00 \mathrm{L}\) of liquid \(n-\mathrm{C}_{6} \mathrm{H}_{14}\) at \(T=300 \mathrm{K} .\) A combustion reaction known to release \(16.73 \mathrm{kJ}\) of heat takes place in the bomb, and the subsequent temperature rise of the system contents is measured and found to be \(3.10 \mathrm{K}\). In a separate experiment, it is found that \(6.14 \mathrm{kJ}\) of heat is required to raise the temperature of everything in the system except the hexane by \(3.10 \mathrm{K}\). Use these data to estimate \(C_{p}[\mathrm{kJ} /(\mathrm{mol} \cdot \mathrm{K})]\) for liquid \(n\) -hexane at \(T \approx 300 \mathrm{K},\) assuming that the condition required for the validity of Equation 2 is satisfied. Compare your result with a tabulated value.

Estimate the heat of vaporization of diethyl ether at its normal boiling point using Trouton's rule and Chen's rule and compare the results with a tabulated value of this quantity. Calculate the percentage error that results from using each estimation. Then estimate \(\Delta \hat{H}_{\mathrm{v}}\) at \(100^{\circ} \mathrm{C}\) using Watson's correlation.

A sheet of cellulose acetate film containing 5.00 wt\% liquid acetone enters an adiabatic dryer where \(90 \%\) of the acetone evaporates into a stream of dry air flowing over the film. The film enters the dryer at \(T_{\mathrm{f} 1}=35^{\circ} \mathrm{C}\) and leaves at \(T_{\mathrm{f} 2}\left(^{\circ} \mathrm{C}\right) .\) The air enters the dryer at \(T_{\mathrm{al}}\left(^{\circ} \mathrm{C}\right)\) and 1.01 atm and exits the dryer at \(T_{\mathrm{a} 2}=49^{\circ} \mathrm{C}\) and 1 atm with a relative saturation of \(40 \% . C_{p}\) may be taken to be \(1.33 \mathrm{kJ} /\left(\mathrm{kg} \cdot^{\circ} \mathrm{C}\right)\) for dry film and \(0.129 \mathrm{kJ} /\left(\mathrm{mol} \cdot^{\circ} \mathrm{C}\right)\) for liquid acetone. Make a reasonable assumption regarding the heat capacity of dry air. The heat of vaporization of acetone may be considered independent of temperature. Take a basis of \(100 \mathrm{kg}\) film fed to the dryer for the requested calculations. (a) Estimate the feed ratio [liters dry air (STP)/kg dry film]. (b) Derive an expression for \(T_{\mathrm{al}}\) in terms of the film temperature change, \(\left(T_{\mathrm{f} 2}-35\right),\) and use it to answer Parts (c) and (d). (c) Calculate the film temperature change if the inlet air temperature is \(120^{\circ} \mathrm{C}\). (d) Calculate the required value of \(T_{\mathrm{al}}\) if the film temperature falls to \(34^{\circ} \mathrm{C},\) and the value if it rises to \(36^{\circ} \mathrm{C}.\) (e) If you solved Parts (c) and (d) correctly, you found that even though the air temperature is consistently higher than the film temperature in the dryer, so that heat is always transferred from the air to the film, the film temperature can drop from the inlet to the outlet. How is this possible?

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