/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 76 Determining the value of newly l... [FREE SOLUTION] | 91Ó°ÊÓ

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Determining the value of newly located natural gas sites involves estimating the gas composition. quantity, and ease of access. For example, one report described a find of 2 trillion cubic feet of natural gas that is significantly offshore, in 20 feet of water, and at a drilled depth of 25,000 ft. (In North America and the OPEC countries, reported volumes are determined at 14.73 psia and \(60^{\circ} \mathrm{F}\).) The pressure in this find is estimated to be 750 atm, and the gas is 94 mole \(\%\) methane, \(3.5 \%\) ethane, and the balance \(\mathrm{CO}_{2}\) (a) Estimate the total Ib-moles of gas in the find. (b) Use the compressibility-factor equation of state to estimate the specific volume (ft \(^{3} /\) /b-mole) in the well. The temperature of such wells can vary depending upon a number of factors; for the purposes of this problem, assume that it is \(200^{\circ} \mathrm{C}\).

Short Answer

Expert verified
The estimated total lb-moles of gas in the find and specific volume in the well can only be obtained after carrying out the above calculations. Particular values depend upon the provided compressibility factors for each gas at given conditions.

Step by step solution

01

Conversion to lb-moles

First, it is important to convert the volume of gas to lbs-moles. To accomplish this, one can use the ideal gas law \(PV = nRT\), where \(P = 14.73\) psia (pressure), \(V = 2\) trillion cubic feet (volume), \(R = 10.73\) ft³.psi/(R.lb-mol) (universal gas constant) and \(T = 520\)R (temperature in Rankine, instrumental in getting the gas volumes to base conditions at \(60^{\circ} \mathrm{F}\)). Solving for \(n\) (the amount in mole) will give the total lb-moles of gas in the find.
02

Compressibility Calculation

The second step is to calculate the specific volume in the well using the compressibility-factor equation of state. Assuming the system behaves ideally, the compressibility factor \(Z\), which represents how closely real gases obey the ideal gas law, should be one. However, due to deviations at high pressure and temperature, the overall \(Z\) has to be calculated based on mole fractions. The fractions are 94 mole% methane, 3.5% ethane, and the balance CO2. Thus, the overall compressibility at 200°C (~673°R) and 750 atm can be estimated by summing up the product of each component's mole fraction and its respective compressibility factor under these conditions.
03

Specific Volume Calculation

Having calculated the overall compressibility factor, the gas specific volume at 750 atm (around 11265 psia) and 200°C can be calculated from the equation \(v = ZRT/P\), where \(R = 10.73\) ft³.psi/(R.lb-mol), \(T = 200°C = 673\)R, and \(P = 750 atm = 11265 psia\). This yields the specific volume in ft³/lb-mole.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Ideal Gas Law and its Application
The ideal gas law is a fundamental equation in the study of thermodynamics, particularly in understanding the behavior of gases under various conditions. The equation is expressed as \(PV = nRT\), which relates the pressure (P), volume (V), and temperature (T) of a gas to the amount of substance (n) in moles, and includes the ideal gas constant (R). In practical terms, this law helps us to calculate the quantity of a gas, like in our exercise where we have to find the total lb-moles of gas in a newly discovered natural gas find.

When applying the ideal gas law, it is critical to ensure that the units used are consistent. For instance, the pressure must be in absolute terms, such as psi (pounds per square inch absolute), and temperature should be in a universal scale like Kelvin (K) or Rankine (R). Any volume must be in cubic units consistent with the gas constant used. In our problem, we work with psia for pressure, cubic feet for volume, and Rankine for temperature, while the gas constant is given in ft³.psi/(R.lb-mol).

It's important to note that the ideal gas law assumes gases are 'ideal', meaning they have no intermolecular forces and occupy no space; however, real gases only approximate this behavior under certain conditions, usually at low pressures and high temperatures. When dealing with high-pressure conditions like those in gas wells, we must account for the real nature of gas, which leads us to the compressibility-factor equation of state.
Real Gas Behavior and the Compressibility-Factor Equation of State
As gases deviate from ideal behavior, adjustments have to be made to account for the interactions and volume occupied by gas molecules. This is where the compressibility-factor (Z) comes into play. The compressibility-factor equation of state expresses how much the real gas deviates from the predicted behavior of an ideal gas and is crucial in high-pressure and high-temperature environments, like those found in deep gas wells.

Compressibility Factor (Z)

The compressibility factor is a dimensionless value that is multiplied by the ideal gas law to correct for non-ideal behavior. It is defined by the relationship \(Z = \frac{PV}{nRT}\), where a Z-value of 1 means the gas behaves ideally. For real gases, Z can vary from 1 depending on factors like pressure, temperature, and gas composition.

In the exercise, we use this concept to estimate the specific volume (ft³/lb-mole) in the well. Given that the well has a very high pressure and a high temperature, we expect significant deviations from ideality. To estimate the compressibility factor of the gas mixture in the well, we combine the compressibility factors of each component, weighted by their mole fractions, to calculate an overall Z for the mixture. Here, we consider the mole percentage of methane, ethane, and carbon dioxide, which affects their individual and collective behavior under the described conditions.
Mole Fraction Calculation and its Importance in Gas Mixtures
In chemistry and engineering, mole fraction is a way of expressing the concentration of a component in a mixture. The mole fraction (chi, represented by the Greek letter \(\chi\)) of any component is defined as the number of moles of that component divided by the total number of moles of all components in the mixture.

Calculating Mole Fractions

To calculate the mole fraction, one would use the formula: \(\chi_i = \frac{n_i}{n_{total}}\), where \(\chi_i\) is the mole fraction of component i, \(n_i\) is the number of moles of component i, and \(n_{total}\) is the total number of moles in the mixture.

Mole fractions are essential when working with gas mixtures as they help us determine the behavior of each gas component within the mixture. In our exercise involving a natural gas find, understanding the mole fractions of methane, ethane, and carbon dioxide is critical for calculating the overall compressibility factor of the gas mixture. These fractions are factored into the equation when assessing how close the mixture is to ideal behavior, thereby enabling us to accurately adjust the gas laws to fit the reality of the mixture in the high-pressure and high-temperature conditions of the gas well.

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Most popular questions from this chapter

Lewis \(^{12}\) describes the hazards of breathing air containing appreciable amounts of an asphyxiant (a gas that has no specific toxicity but, when inhaled, excludes oxygen from the lungs). When the mole percent of the asphyxiant in the air reaches \(50 \%,\) marked symptoms of distress appear, and at \(75 \%\) death occurs in a matter of minutes. A small storage room whose dimensions are \(2 \mathrm{m} \times 1.5 \mathrm{m} \times 3 \mathrm{m}\) contains a number of expensive and dangerous chemicals. To prevent unauthorized entry, the door to the room is always locked and can be opened with a key from either side. A cylinder of liquid carbon dioxide is stored in the room. The valve on the cylinder is faulty and some of the contents have escaped over the weekend. The room temperature is \(25^{\circ} \mathrm{C}\). (a) If the concentration of \(\mathrm{CO}_{2}\) reaches the lethal 75 mole \(\%\) level, what would be the mole percent of \(\mathrm{O}_{2} ?\) (b) How much \(\mathrm{CO}_{2}(\mathrm{kg})\) is present in the room when the lethal concentration is reached? Why would more than that amount have to escape from the cylinder for this concentration to be reached? (c) Describe a set of events that could result in a fatality in the given situation. Suggest at least two measures that would reduce the hazards associated with storage of this scemingly harmless substance.

The label has come off a cylinder of gas in your laboratory. You know only that one species of gas is contained in the cylinder, but you do not know whether it is hydrogen, oxygen, or nitrogen. To find out, you evacuate a 5 -liter flask, seal it and weigh it, then let gas from the cylinder flow into it until the gauge pressure equals 1.00 atm. The flask is reweighed, and the mass of the added gas is found to be 13.0g. Room temperature is \(27^{\circ} \mathrm{C}\), and barometric pressure is 1.00 atm. What is the gas?

A stream of oxygen enters a compressor at \(298 \mathrm{K}\) and 1.00 atm at a rate of \(127 \mathrm{m}^{3} / \mathrm{h}\) and is compressed to \(358 \mathrm{K}\) and 1000 atm. Estimate the volumetric flow rate of compressed \(\mathrm{O}_{2},\) using the compressibility-factor equation of state.

The van der Waals equation of state (Equation \(5.3-7\) ) is to be used to estimate the specific molar volume \(\hat{V}(\mathrm{L} / \mathrm{mol})\) of air at specified values of \(T(\mathrm{K})\) and \(P(\mathrm{atm}) .\) The van der Waals constants for air are \(a=1.33 \mathrm{atm} \cdot \mathrm{L}^{2} / \mathrm{mol}^{2}\) and \(b=0.0366 \mathrm{L} / \mathrm{mol}\) (a) Show why the van der Waals equation is classified as a cubic equation of state by expressing it in the form $$f(\hat{V})=c_{3} \hat{V}^{3}+c_{2} \hat{V}^{2}+c_{1} \hat{V}+c_{0}=0$$ where the coefficients \(c_{3}, c_{2}, c_{1},\) and \(c_{0}\) involve \(P, R, T, a,\) and \(b .\) Calculate the values of these coefficients for air at \(223 \mathrm{K}\) and 50.0 atm. (Include the units when giving the values.) (b) What would the value of \(\hat{V}\) be if the ideal-gas equation of state were used for the calculation? Use this value as an initial estimate of \(\tilde{V}\) for air at \(223 \mathrm{K}\) and 50.0 atm and solve the van der Waals equation using Goal Seek or Solver in Excel. What percentage error results from the use of the ideal-gas equation of state, taking the van der Waals estimate to be correct? (c) Set up a spreadsheet to carry out the calculations of Part (b) for air at \(223 \mathrm{K}\) and several pressures. The spreadsheet should appear as follows: The polynomial expression for \(\hat{V}\left(f=c_{3} \hat{V}^{3}+c_{2} \hat{V}^{2}+\cdots\right)\) should be entered in the \(f(V)\) column, and the value in the \(V\) column should be determined using Goal Seek or Solver in Excel.

A gas turbine power plant receives a shipment of hydrocarbon fuel whose composition is uncertain but may be represented by the expression \(\mathrm{C}_{x} \mathrm{H}_{y}\). The fuel is burned with excess air. An analysis of the product gas gives the following results on a moisture-free basis: \(10.5 \%(\mathrm{v} / \mathrm{v}) \mathrm{CO}_{2}, 5.3 \% \mathrm{O}_{2},\) and \(84.2 \% \mathrm{N}_{2}\) (a) Determine the molar ratio of hydrogen to carbon in the fuel ( \(r\) ), where \(r=y / x\), and the percentage excess air used in the combustion. (b) What is the air-to-fuel ratio ( \(m^{3}\) air/kg of fuel) if the air is fed to the power plant at \(30^{\circ} \mathrm{C}\) and \(98 \mathrm{kPa} ?\) (c) The specific gravity of the fuel (a petroleum product) is \(0.85 .\) Estimate the ratio standard cubic feet of gas fed to the turbine per barrel of fuel. (d) What are the issues associated with using oil as a fuel as opposed to natural gas? Consider two factors: (i) the complete composition of typical fuel oils and their resulting emissions, and (ii) the availability and global distribution of the two fuel sources.

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