/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 The label has come off a cylinde... [FREE SOLUTION] | 91Ó°ÊÓ

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The label has come off a cylinder of gas in your laboratory. You know only that one species of gas is contained in the cylinder, but you do not know whether it is hydrogen, oxygen, or nitrogen. To find out, you evacuate a 5 -liter flask, seal it and weigh it, then let gas from the cylinder flow into it until the gauge pressure equals 1.00 atm. The flask is reweighed, and the mass of the added gas is found to be 13.0g. Room temperature is \(27^{\circ} \mathrm{C}\), and barometric pressure is 1.00 atm. What is the gas?

Short Answer

Expert verified
The gas in the cylinder is oxygen.

Step by step solution

01

Convert the temperature from Celsius to Kelvin

To conduct any gas law calculations, the temperature must be expressed in Kelvin (K). The conversion from Celsius to Kelvin is done by adding 273 to the Celsius temperature. Thus, \(27^\circ C = 300 K\).
02

Calculate the moles of the gas

Use the Ideal Gas Law \(PV = nRT\) where P = 1 atm, V = 5 L, R = 0.0821 L·atm/K·mol (ideal gas constant), and T = 300 K to calculate the number of moles (n). It is rearranged to \( n = PV/RT \) to find that \( n = (1 atm · 5 L)/(0.0821 L·atm/K·mol · 300K) = 0.203 mol \)
03

Calculate the molar mass of the gas

The molar mass (MW) of a substance is its mass (g) divided by the amount (mol). Therefore the molar mass of the gas (g/mol) = mass of the gas (g) ÷ amount of the gas (mol). This gives \( MW = 13.0 g / 0.203 mol = 64.0 g/mol \)
04

Identify the gas

The calculated molar mass (64.0 g/mol) is compared to the molar masses of hydrogen (~1 g/mol), oxygen (~32 g/mol), and nitrogen (~28 g/mol). The molar mass closest to the calculated one is oxygen, so the gas in the cylinder is most likely oxygen.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gas Identification
Identifying an unknown gas in a laboratory setting can be accomplished using the Ideal Gas Law and information about the gas' properties. In the given exercise, we are presented with three possible gases: hydrogen, oxygen, and nitrogen. Each of these gases has a unique molar mass. By comparing the molar mass calculated from the experiment with the known molar masses of potential gases, we can make an educated guess about the gas' identity. In this context, the molar mass acts as a 'fingerprint' for chemical substances, allowing for accurate identification when measured precisely.

Understanding how to calculate and compare molar masses is essential in chemistry, not only for identification but also for stoichiometry and reaction prediction. The process involves a careful balance of measurement, calculation, and comparison against established data.
Molar Mass Calculation
Molar mass is defined as the mass of one mole of a substance and is expressed in grams per mole (g/mol). To calculate the molar mass of a gas from experimental data, you need to know the mass of a known volume of the gas at a specified temperature and pressure - precisely the information provided in the exercise. After determining the amount of gas (in moles) using the Ideal Gas Law, the next step is to divide the measured gas mass by the number of moles to find the molar mass.

This calculated molar mass can be utilized as a crucial parameter in various chemical calculations, such as determining the formula of a compound, finding the percent composition, or converting between mass and moles in a chemical reaction.
Gas Law Calculations
Gas Law calculations involve equations that relate the pressure, volume, temperature, and number of moles of a gas. In the exercise, we used the Ideal Gas Law, which is the cornerstone of gas law calculations. The flexibility of this equation allows us to solve for any one of the variables if the other three are known. This versatile formula is essential for various applications in both chemistry and physics, from calculating the behavior of gases in different environmental conditions to understanding the thermodynamics of gaseous systems.

By mastering gas law calculations, students can confidently approach a variety of real-world problems that involve gases and their interactions. The key is to ensure all units match the Ideal Gas Law's requirements, especially with temperature in Kelvin and pressure in atmospheres, for consistency and accuracy.
PV=nRT
The equation PV=nRT, known as the Ideal Gas Law, provides a mathematical relationship between the pressure (P), volume (V), number of moles (n), gas constant (R), and temperature (T) of an ideal gas. This law is the culmination of Boyle's Law, Charles's Law, Avogadro's Law, and Gay-Lussac's Law, and it assumes that the particles of an ideal gas do not attract or repel each other and take up no space. Though no gas is perfectly ideal, the Ideal Gas Law gives a close approximation for many gases under standard conditions.

By comprehending how to manipulate the Ideal Gas Law and solve for any of its individual components, students can explore varied gas-related scenarios, from the expansion of a balloon to the kinetics of a chemical reaction involving gases. The gas constant (R) used must match the units of pressure, volume, and temperature within the context of the problem.
Temperature Conversion
Temperature conversion in gas law calculations is critical because the laws on which these calculations are based—such as Charles's Law and Gay-Lussac's Law—are derived from experiments where temperature is measured on an absolute scale (Kelvin scale). To ensure accuracy in gas law problems, it's essential always to convert temperature from Celsius or Fahrenheit to Kelvin.

The conversion from Celsius to Kelvin is straightforward: simply add 273.15 to the Celsius temperature. For Fahrenheit, the conversion involves subtracting 32, then multiplying by 5/9, and finally adding 273.15. These conversions are critical because the volume and pressure of gases are directly related to their temperature in Kelvin, which means accurate temperature data is necessary for reliable gas behaviors predictions.

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Most popular questions from this chapter

A gas cylinder filled with nitrogen at standard temperature and pressure has a mass of \(37.289 \mathrm{g}\). The same container filled with carbon dioxide at STP has a mass of 37.440 g. When filled with an unknown gas at STP, the container mass is \(37.062 \mathrm{g}\). Calculate the molecular weight of the unknown gas, and then state its probable identity.

Magnesium sulfate has a number of uses, some of which are related to the ability of the anhydrate form to remove water from air and others based on the high solubility of the heptahydrate \(\left(\mathrm{MgSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}\right)\) form, also known as Epsom salt. The densities of the anhydrate and heptahydrate crystalline forms are 2.66 and \(1.68 \mathrm{g} / \mathrm{mL},\) respectively. Suppose you wish to form a 20.0 wt\% \(\mathrm{MgSO}_{4}\) aqueous solution by simply pouring crystals of one of the forms into a tank of water while the temperature is held constant at \(30^{\circ} \mathrm{C}\). The specific gravity of the 20.0 wt\% solution at \(30^{\circ} \mathrm{C}\) is \(1.22 .\) Answer the following questions for both forms of the \(\mathrm{MgSO}_{4}\) crystals: (a) What volume of water should be in the tank before crystals are added if the final product is to be 1000 kg of the 20 wt\% solution? (b) Suppose the tank diameter is \(0.30 \mathrm{m}\). What is the height of liquid in the tank before the crystals are added? (c) What is the height of the water in the tank after addition of the crystals but before they begin to dissolve? (d) What is the height of liquid in the tank after all the MgSO \(_{4}\) has dissolved?

Air in industrial plants is subject to contamination by many different chemicals, and companies must monitor ambient levels of hazardous species to be sure they are below limits specified by the National Institute for Occupational Safety and Health (NIOSH). In personal breathing-zone sampling (as opposed to area sampling), workers wear devices that periodically collect air samples less than 10 inches away from their noses. Breathing-zone sampling and analysis methods for hundreds of species are set forth in the NIOSH Manual of Analytical Methods. \(^{13}\) For benzene, NIOSH specifies a recommended exposure limit (REL) of 0.1 ppm time-weighted average exposure (TWA), and the Occupational Safety and Health Administration (OSHA) permissible exposure limit (PEL) is 1.0ppm TWA. A worker in a petrolcum refinery has a personal breathing-zone sampler for benzenc clipped to her shirt collar. Following the NIOSH prescription, air is pumped through the sampler at a rate of \(0.200 \mathrm{L} / \mathrm{min}\) by a small battery-operated pump attached to the worker's belt. The sampler contains an adsorbent that removes essentially all of the benzene from the air passing through it. After several hours, the sampler is removed and sent to a lab for analysis, and the worker puts on a fresh sampler. On a particular day when the temperature is \(21^{\circ} \mathrm{C}\) and barometric pressure is \(730 \mathrm{mm}\) Hg, samples are collected during a 4-h period before lunch and a 3.5-h period after lunch. The analytical laboratory reports \(0.17 \mathrm{mg}\) of benzene in the first sample and \(0.23 \mathrm{mg}\) in the second. (a) Calculate the average benzene concentration, \(C_{\mathrm{B}}(\mathrm{ppm}),\) in the worker's breathing zone during each sampling period, where 1 ppm = 1 mol C \(_{6} \mathrm{H}_{6} / 10^{6}\) mol air. (b) The worker's TWA is the average concentration of benzene in her breathing zone during the eight hours of her shift. It is calculated by multiplying \(C_{\mathrm{B}}\) in each sampling period by the time of that period, summing the products over all periods during the shift, and dividing by the total time of the shift. Assume that the worker's exposure during the unsampled 30 minutes was zero, and calculate her TWA. (c) If the worker's exposure is above the recommended limits, what actions might the company take?

Propylene is hydrogenated in a batch reactor: $$\mathrm{C}_{3} \mathrm{H}_{6}(\mathrm{g})+\mathrm{H}_{2}(\mathrm{g}) \rightarrow \mathrm{C}_{3} \mathrm{H}_{8}(\mathrm{g})$$ Equimolar amounts of propylene and hydrogen are fed into the reactor at \(25^{\circ} \mathrm{C}\) and a total absolute pressure of 32.0 atm. The reactor temperature is raised to \(235^{\circ} \mathrm{C}\) and held constant thereafter until the reaction is complete. The propylene conversion at the beginning of the isothermal period is \(53.2 \%\) You may assume ideal-gas behavior for this problem, although at the high pressures involved this assumption constitutes an approximation at best. (a) What is the final reactor pressure? (b) What is the percentage conversion of propylene when \(P=35.1\) atm? (c) Construct a graph of pressure versus fractional conversion of propylene covering the isothermal period of operation. Use the graph to confirm the results in Parts (a) and (b). (Suggestion: Use a spreadsheet.)

A distillation column is being used to separate methanol and water at atmospheric pressure. The column temperature varies from approximately \(65^{\circ} \mathrm{C}\) at the top to \(100^{\circ} \mathrm{C}\) at the bottom. Liquid enters the top of the column and flows down to the bottom; vapor is generated in a reboiler at the bottom of the column, flows upward, and leaves at the top. The molar flow rate of vapor up the column may be assumed to be constant from top to bottom. The vapor velocity is kept below \(5.0 \mathrm{ft} / \mathrm{s}\) to keep the vapor from entraining liquid (suspending and carrying away liquid droplets). (a) Where in the column is the greatest risk of liquid entrainment? Explain your answer. (b) Assuming that the liquid flowing down the column and the column internals (equipment inside the column) occupy a negligible fraction of the column cross-sectional area, estimate the minimum column diameter if the vapor flow rate is 25.0 lb-mole/min. (c) Suppose the column is constructed with a diameter \(10 \%\) greater than that determined in Part (b). What are the vapor velocities at the top and bottom of the column if the vapor molar flow rate in both locations is 25.0 ib-mole/min? How much can the vapor molar flow rate be increased without causing liquid entrainment? (d) There is a need to increase process throughput, which would require the vapor molar flow rate to be doubled. It has been suggested that increasing the pressure in the column would allow that to be done without risking excessive liquid entrainment. Again applying a vapor velocity limit of \(5 \mathrm{ft} / \mathrm{s}\) what would the new pressure be?

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