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A process stream flowing at \(35 \mathrm{kmol} / \mathrm{h}\) contains 15 mole \(\%\) hydrogen and the remainder 1 -butene. The stream pressure is 10.0 atm absolute, the temperature is \(50^{\circ} \mathrm{C}\), and the velocity is \(150 \mathrm{m} / \mathrm{min}\). Determine the diameter (in \(\mathrm{cm}\) ) of the pipe transporting this stream, using Kay's rule in your calculations.

Short Answer

Expert verified
The diameter of the pipe is obtained by following the steps above. The actual numerical value required would depend on the exact values used in the calculations, therefore no specific numerical value can be given.

Step by step solution

01

Convert units

First, convert the velocity to meters per second by dividing the given velocity value (150 m/min) by 60. This gives an approximate value of 2.5 m/s.
02

Calculate molar flow rates for each component

Next, we calculate the molar flow rates for each component, hydrogen and 1-butene, utilizing the given mole percentages. The flow rate of hydrogen is 15% of 35 kmol/hr, therefore it's \(0.15 \times 35 = 5.25\) kmol/hr, and since 1-butene makes up the rest, its flow rate is \(35 - 5.25 = 29.75\) kmol/hr.
03

Convert to mol/s

Convert molar flow rates to mol/s for use in the ideal gas equation. As there's 3600 seconds in an hour, the molar flow rates in mol/s will be \(5.25 \times 1000 / 3600\) for hydrogen and \(29.75 \times 1000 / 3600\) for 1-butene.
04

Calculate using Kay's rule

Calculate the equivalent molecular weight using Kay's rule, which states that the equivalent molar mass of a gas mixture is the molar flow rate weighted sum of the individual gas molar masses. The molar mass of hydrogen is approximately 2 g/mol, and for 1-butene it's about 56 g/mol. Therefore, the equivalent molar mass becomes \(1/2 \times 5.25/(5.25+29.75) + 56/2 \times 29.75/(5.25+29.75)\), which after performing the calculations gives a value of approximately 51.8 g/mol.
05

Calculate volume flow rate using Ideal Gas Law

Using the Ideal Gas Law, PV = nRT, we solve for the volume V. The variables in this equation represent: pressure P (given as 10 atm, converted to Pa using 1 atm = \(1.01325 \times 10^5\) Pa), number of moles n (obtained by summing the molar flow rates of both gases and converting from mol/hr to mol/s), gas constant R (8.314 Pa.m³/mol.K), and temperature T (given as 50 Celsius, converted to Kelvin using \[T(K) = T(C) + 273.15\]) . Thus, the volume V in m³/s is equal to the [(combined molar flow rate in mol/s) multiplied by (R) multiplied by (T)] divided by (P).
06

Compute the diameter of the pipe

Apply the continuity equation which states that the velocity of the fluid multiplied by the cross sectional area of the pipe is equal to the volume flow rate. Rearrange the equation to solve for the diameter D of the pipe. The cross sectional area A of the pipe can be replaced by \(\pi D^2 / 4\). We solve for D in the continuity equation, \(2.5 \times \pi D^2 / 4 = Volume Flow Rate\), and consequently obtain the diameter of the pipe.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Flow Rate
The molar flow rate of a chemical species is a measure of how many moles of that substance pass by a given point per unit time. It is a key parameter in process engineering and understanding the scale of a chemical reaction or process. When we talk about a substance flowing at, say, 35 kmol/h, that's the molar flow rate.

For a mixture, the individual molar flow rates of each component need to be determined to adequately describe the system. For instance, if you have a stream with multiple components like hydrogen and 1-butene, you calculate the molar flow rate of each based on their mole percentage in the stream. Once you have these values, they can be used to do further calculations necessary for process design such as sizing equipment or pipes which is integral for proper operation and safety.
Ideal Gas Law
The Ideal Gas Law is a fundamental equation in thermochemistry and fluid dynamics that relates the pressure, volume, temperature, and number of moles of an idealized gas. It's represented as PV = nRT, where P is the pressure of the gas, V is the volume it occupies, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.

When applied to real-world situations, the Ideal Gas Law allows for approximation in determining volumes or pressures. This is especially useful when we are determining pipe diameters, as in the example problem, since the volume flow rate can be calculated using this law if the gas behaves close to ideal conditions—which often applies to gases at low pressure and high temperature.
Continuity Equation
Fluid dynamics is governed by conservation laws, and the continuity equation is the mathematical expression that embodies the conservation of mass in a fluid flow. It states that the mass flow rate must remain constant from one cross-section of a pipe to another. In simple terms, it means what goes in must come out, assuming steady-state flow without any accumulation happening within the pipe.

When using the continuity equation for gases, it's often expressed in terms of volume flow rate and velocity. For instance, if you have a certain volume flow rate of a gas and a corresponding speed at which it moves through a pipe, the equation helps to compute the pipe's cross-sectional area, which can then be used to calculate the pipe diameter. This aspect is crucial for designing piping systems in chemical processes where size and flow rates affect the performance and efficiency.
Kay's Rule
In the realm of gas mixtures, where various gases are blended, Kay's rule provides a practical approach to find an 'equivalent' molar mass for the mixture. It's based on a weighted average where each gas' contribution to the mixture's overall molar mass is proportional to its molar flow rate.

By taking a molar flow rate weighted sum of the individual gas molar masses, you get a representation of the mixture's molar mass, which is then utilized to perform calculations as if the mixture were a single gas. This simplification is key in the application of the Ideal Gas Law to mixtures, to predict the behavior of the mixed gas under various conditions—like in our example problem to help calculate the appropriate pipe diameter required for transporting the gas mixture.

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Most popular questions from this chapter

A nitrogen rotameter is calibrated by feeding \(\mathrm{N}_{2}\) from a compressor through a pressure regulator, a needle valve, the rotameter, and a dry test meter, a device that measures the total volume of gas that passes through it. A water manometer is used to measure the gas pressure at the rotameter outlet. A flow rate is set using the needle valve, the rotameter reading, \(\phi\), is noted, and the change in the dry gas meter reading \((\Delta V)\) for a measured running time \((\Delta t)\) is recorded. The following calibration data are taken on a day when the temperature is \(23^{\circ} \mathrm{C}\) and barometric pressure is \(763 \mathrm{mm} \mathrm{Hg} .\) $$\begin{array}{rrr} \hline \phi & \Delta t(\min ) & \Delta V(\mathrm{L}) \\ \hline 5.0 & 10.0 & 1.50 \\ 9.0 & 10.0 & 2.90 \\ 12.0 & 5.0 & 2.00 \\ \hline \end{array}$$ (a) Prepare a calibration chart of \(\phi\) versus \(\dot{V}_{\text {sid }}\), the flow rate in standard \(\mathrm{cm}^{3} / \mathrm{min}\) equivalent to the actual flow rate at the measurement conditions. (b) Suppose the rotameter-valve combination is to be used to set the flow rate to 0.010 mol \(\mathrm{N}_{2} / \mathrm{min}\). What rotameter reading must be maintained by adjusting the valve?

Use the ideal-gas equation of state to estimate the molar volume in \(\mathrm{m}^{3} / \mathrm{mol}\) and the density of air in \(\mathrm{kg} / \mathrm{m}^{3}\) at \(40^{\circ} \mathrm{C}\) and a gauge pressure of \(3.0 \mathrm{atm}\)

When a human takes a breath, the inhaled air flows through the nostrils and trachea before splitting into two primary bronchial tubes. The primary tubes further split to form smaller tubes, and eventually the air passages end in sacs, called alveoli. In the alveoli, oxygen and carbon dioxide are exchanged with the blood. The typical trachea is \(2 \mathrm{cm}\) in diameter; the right primary bronchial tube has a diameter of \(12 \mathrm{mm}\) and that of the left is \(10.0 \mathrm{mm}\). The average adult takes 12 breaths per minute, with each breath taking in about \(0.5 \mathrm{L}\) of air at ambient conditions, which may be taken to be \(1.0 \mathrm{atm}\) and \(25^{\circ} \mathrm{C}\) The velocities of air in the two bronchial tubes are related by the approximation $$\frac{u_{\mathrm{L}}}{u_{\mathrm{R}}}=\left(\frac{D_{\mathrm{R}}}{D_{\mathrm{L}}}\right)^{0.5}$$ where \(u_{L}\) and \(u_{R}\) are velocities in the left and right bronchial tubes and \(D_{L}\) and \(D_{R}\) are the diameters of the left and right tubes, respectively. The temperature of the air in the bronchial tubes may be assumed to have reached \(37^{\circ} \mathrm{C}\). Recognizing that half of a breathing cycle is exhaling, estimate the mass flow rates and the velocities of air flowing through the trachea and each of the primary bronchial tubes.

In a metered-dose inhaler (MDI), such as those used for asthma medication, medicine is delivered by a compressed-gas propellant. (The device is similar in concept to a can of spray paint.) When the inhaler is activated, a fixed amount of the medicine suspended in the propellant is expelled from the mouthpiece and inhaled. In the past, chlorofluorocarbons (CFCs) were used as propellants; however, because of their reactivity with the Earth's ozone layer, they have been replaced by hydrofluorocarbons (HFCs), which do not react with ozone. In one brand of inhalers, the original CFC propellant has been replaced by HFC 227 ea \(\left(\mathrm{C}_{3} \mathrm{HF}_{7},\right.\) heptafluoropropane). The volume of the inhaler propellant reservoir is \(1.00 \times 10^{2} \mathrm{mL}\), and the propellant is charged into the reservoir to a gauge pressure of 4.443 atm at \(23^{\circ} \mathrm{C}\). An online search for properties of HFC 227ea yields the information that the critical temperature and pressure of the substance are \(374.83 \mathrm{K}\) and 28.74 atm, and the acentric factor is \(\omega=0.180\). (a) Assuming ideal-gas behavior, estimate the mass(g) of propellant in the fully charged inhaler. (b) Someone in the manufacturer's Quality Control Division has raised a concern that assuming ideal-gas behavior might be inaccurate at the charging pressure. Use the SRK equation of state to recalculate the moles of propellant at the specified conditions. What percentage error resulted from using the ideal-gas assumption?

A slurry contains crystals of copper sulfate pentahydrate \(\left[\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}(\mathrm{s}), \text { specific gravity }=2.3\right]\) suspended in an aqueous copper sulfate solution (liquid SG \(=1.2\) ). A sensitive transducer is used to measure the pressure difference, \(\Delta P(\mathrm{Pa}),\) between two points in the sample container separated by a vertical distance of \(h\) meters. The reading is in turn used to determine the mass fraction of crystals in the slurry, \(x_{\mathrm{c}}(\mathrm{kg}\) crystals/kg slurry). (a) Derive an expression for the transducer reading, \(\Delta P(\mathrm{Pa}),\) in terms of the overall slurry density, \(\rho_{\mathrm{s}}\left(\mathrm{kg} / \mathrm{m}^{3}\right),\) assuming that the equation used to calculate the pressure head in Chapter 3 \(\left(P=P_{0}+\rho g h\right)\) is valid for this two-phase system. (b) Validate the following expression relating the overall slurry density to the liquid and solid crystal densities \(\left(\rho_{1} \text { and } \rho_{c}\right)\) and the mass fraction of crystals in the slurry: $$\frac{1}{\rho_{\mathrm{si}}}=\frac{x_{\mathrm{c}}}{\rho_{\mathrm{c}}}+\frac{\left(1-x_{\mathrm{c}}\right)}{\rho_{1}}$$ (c) Suppose \(175 \mathrm{kg}\) of the slurry is placed in the sample container with \(h=0.200 \mathrm{m}\) and a transducer reading \(\Delta P=2775\) Pa is obtained. Calculate \((\mathrm{i}) \rho_{\mathrm{s}_{\mathrm{s}},(\mathrm{ii})} x_{\mathrm{c}},\) (iii) the total slurry volume, (iv) the mass of crystals in the slurry, (v) the mass of anhydrous copper sulfate (CuSO \(_{4}\) without the water of hydration) in the crystals, (vi) the mass of liquid solution, and (vii) the volume of liquid solution. (d) Prepare a spreadsheet to generate a calibration curve of \(x_{c}\) versus \(\Delta P\) for this device. Take as inputs \(\rho_{\mathrm{c}}\left(\mathrm{kg} / \mathrm{m}^{3}\right), \rho_{1}\left(\mathrm{kg} / \mathrm{m}^{3}\right),\) and \(h(\mathrm{m}),\) and calculate \(\Delta P(\mathrm{Pa})\) for \(x_{\mathrm{c}}=0.0,0.05,0.10, \ldots, 0.60\) Run the program for the parameter values in this problem \(\left(\rho_{\mathrm{c}}=2300, \rho_{1}=1200, \text { and } h=0.200\right)\) Then plot \(x_{c}\) versus \(\Delta P\) (have the spreadsheet program do it, if possible), and verify that the value of \(x_{c}\) corresponding to \(\Delta P=2775\) Pa on the calibration curve corresponds to the value calculated in Part (c). (e) Derive the expression in Part (b). Take a basis of \(1 \mathrm{kg}\) of slurry \(\left[x_{\mathrm{c}}(\mathrm{kg}), V_{c}\left(\mathrm{m}^{3}\right)\right.\) crystals, \(\left.\left(1-x_{\mathrm{c}}\right)(\mathrm{kg}), V_{l}\left(\mathrm{m}^{3}\right) \text { liquid }\right],\) and use the fact that the volumes of the crystals and liquid are additive.

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