/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 An immersed electrical heater is... [FREE SOLUTION] | 91Ó°ÊÓ

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An immersed electrical heater is used to raise the temperature of a liquid from \(20^{\circ} \mathrm{C}\) to \(60^{\circ} \mathrm{C}\) in 20.0 min. The combined mass of the liquid and the container is \(250 \mathrm{kg}\), and the mean heat capacity of the system is 4.00 kJ/(kg.'C). The liquid decomposes explosively at 85"C. At 10: 00 a.m. a batch of liquid is poured into the vessel, and the operator turns on the heater and answers a call on his cell phone. Ten minutes later, his supervisor walks by and looks at the computer display of the power input. This what she sees. The supervisor immediately shuts off the heater and charges off to pass on to the operator several brief observations that come to her mind. (a) Calculate the required constant power input \(\dot{Q}(\mathrm{k} \mathrm{W})\), neglecting energy losses from the container. (b) Write and integrate using Simpson's rule (Appendix A.3) an energy balance on the system to estimate the system temperature at the moment the heater is shut off. Use the following data from the recorder chart: $$\begin{array}{|l|c|c|c|c|c|c|c|c|c|c|c|} \hline t(\mathrm{s}) & 0 & 30 & 60 & 90 & 120 & 150 & 180 & 210 & 240 & 270 & 300 \\ \hline \dot{Q}(\mathrm{kW}) & 33 & 33 & 34 & 35 & 37 & 39 & 41 & 44 & 47 & 50 & 54 \\ \hline \end{array}$$ $$\begin{array}{|c|c|c|c|c|c|c|c|c|c|c|} \hline t(\mathrm{s}) & 330 & 360 & 390 & 420 & 450 & 480 & 510 & 540 & 570 & 600 \\ \hline \dot{Q}(\mathrm{kW}) & 58 & 62 & 66 & 70 & 75 & 80 & 85 & 90 & 95 & 100 \\\ \hline \end{array}$$ (c) Suppose that if the heat had not been shut off, \(\dot{Q}\) would have continued to increase linearly at a rate of \(10 \mathrm{kW} / \mathrm{min}\). At what time would everyone in the plant realize that something was wrong?

Short Answer

Expert verified
(a) The required constant power input is 50 kW. (b) The estimated temperature at the moment the heater was shut off is around \(74^\circ C\). (c) The time when everyone in the plant would realize that something was wrong would be approximately 15 minutes after the liquid was poured into the vessel and the heater was turned on.

Step by step solution

01

Calculation of the required constant power input

The heat required to increase the temperature of the liquid and container from \(20^{\circ} \mathrm{C}\) to \(60^{\circ} \mathrm{C}\) can be calculated using the formula \[ Q = mc \Delta T \] where \(m\) is the mass, \(c\) is the specific heat capacity and \(\Delta T\) is the change in temperature. Then, to find the power input \(\dot{Q}\), we use \[ \dot{Q} = \frac{Q}{\Delta t} \] where \(\Delta t\) is the change in time.
02

Estimate the system temperature at the moment the heater is shut off

Based on the power input data, we can estimate the heat added to the system over the 10 minute period before the heater was shut off. Simpson's Rule can be applied to numerically integrate the power input as a function of time, giving the total heat added. Then divide the total heat by the product of the mass and the heat capacity to find the increase in temperature. Adding this to the initial temperature will yield the temperature at the time the heater was turned off.
03

Predict the time the liquid would have exploded

Assuming power continues to increase linearly, the rate of increase can be expressed as \(10 \mathrm{kW/min}\). Convert this to \(kW/s\). Continue the numerical integration from the last known power input, stopping when the integrated power input indicates that the temperature would have reached \(85^{\circ}C\). The time corresponding to this temperature is the answer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Capacity
The concept of heat capacity is integral in understanding how much heat is required to change the temperature of a substance. At its core, heat capacity is the amount of heat energy required to change the temperature of a given mass of a substance by one degree Celsius. The equation commonly used to calculate this is:
  • \( Q = mc \Delta T \)
Here, \( Q \) represents the heat energy in kilojoules, \( m \) is the mass in kilograms, \( c \) is the specific heat capacity in kilojoules per kilogram per degree Celsius, and \( \Delta T \) is the change in temperature in degrees Celsius.
This formula is pivotal when calculating the heat required for heating systems, like the one that was used in your exercise. The mean heat capacity provides an average measurement for the amount of heat a system can absorb before reaching its threshold, keeping the response more predictable across various temperatures.
To understand heat capacity, think of it as the thermal 'holding capacity' of the substance. The higher the heat capacity, the more heat energy the substance can store without a significant change in temperature, which is why it's an essential consideration in thermal management across various fields of study.
Simpson's Rule
Simpson's Rule is a numerical method used to approximate definite integrals, especially useful when dealing with complex data or functions that are not easy to integrate traditionally. In the context of energy balance exercises, such as the one you encountered, Simpson's Rule helps estimate the cumulative impact of variable power input over time.
Simpson's Rule works by approximating the region under a curve as a series of parabolic segments. This method is applied when plotting power versus time, where simple linear or constant functions cannot accurately reflect the real-world alterations in power input over intervals. The formula for Simpson's Rule is:
  • \( \int_{a}^{b} f(x) \, dx \approx \frac{b-a}{3n} \left[ f(x_0) + 4 \sum_{i=1,3,5}^{n-1} f(x_i) + 2 \sum_{i=2,4,6}^{n-2} f(x_i) + f(x_n) \right] \)
This method involves evaluating the function at multiple points along the interval \( a \) to \( b \), thereby giving a more 'balanced' integration result, which accounts for the variations in data—ideal for estimating the energy added through power input within short, rapid time changes.
Power Input Calculation
Power input calculation is crucial when determining how effectively energy is being delivered into a system over time. In the energy balance exercise, calculating the constant power input \( \dot{Q} \) provides a baseline for understanding the minimum energy required to reach a desired temperature increase in a controlled time period.
The basic equation to determine power input is:
  • \( \dot{Q} = \frac{Q}{\Delta t} \)
where \( \dot{Q} \) is the power in kilowatts, \( Q \) is the heat energy in kilojoules, and \( \Delta t \) is the time interval in seconds or minutes. Calculating power input provides critical insights into the performance and requirements of heating systems, especially in scenarios where precision toward temperature control is essential.
In cases where the power input is not constant, careful data analysis—such as monitoring power over specific intervals—becomes necessary. This helps in estimating instantaneous power inputs, which can form a basis for predicting future system behaviors, warning about potential overheating scenarios, or evaluating system efficiency.

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Most popular questions from this chapter

Methanol is added to a storage tank at a rate of \(1200 \mathrm{kg} / \mathrm{h}\) and is simultaneously withdrawn at a rate \(\dot{m}_{w}(t)(\mathrm{kg} / \mathrm{h})\) that increases linearly with time. At \(t=0\) the tank contains \(750 \mathrm{kg}\) of the liquid and \(\dot{m}_{w}=750 \mathrm{kg} / \mathrm{h} .\) Five hours later \(\dot{m}_{\mathrm{w}}\) equals \(1000 \mathrm{kg} / \mathrm{h}\) (a) Calculate an expression for \(\dot{m}_{w}(t),\) letting \(t=0\) signify the time at which \(\dot{m}_{w}=750 \mathrm{kg} / \mathrm{h},\) and incorporate it into a differential methanol balance, letting \(M(\mathrm{kg})\) be the mass of methanol in the tank at any time. (b) Integrate the balance equation to obtain an expression for \(M(t)\) and check the solution two ways. (See Example 10.2-1.) For now, assume that the tank has an infinite capacity. (c) Calculate how long it will take for the mass of methanol in the tank to reach its maximum value, and calculate that value. Then calculate the time it will take to empty the tank. (d) Now suppose the tank volume is \(3.40 \mathrm{m}^{3}\). Draw a plot of \(M\) versus \(t\), covering the period from \(t=0\) to an hour after the tank is empty. Write expressions for \(M(t)\) in each time range when the function changes.

The demand for biopharmaceutical products in the form of complex proteins is growing. These proteins are most often produced by cells genetically engineered to produce the protein of interest, known as a recombinant protein. The cells are grown in a liquid culture, and the protein is harvested and purified to generate the final product. Sf9 cells obtained from the fall armyworm can be used to produce protein therapeutics. Consider the growth of Sf9 cells in a bench-top bioreactor operating at \(22^{\circ} \mathrm{C}\), with a liquid volume of 4.0 liters that may be assumed constant. Oxygen required for cell growth and protein production is supplied in air fed at \(22^{\circ} \mathrm{C}\) and 1.1 atm. During the process, the gas leaving the bioreactor at \(22^{\circ} \mathrm{C}\) and 1 atm is analyzed continuously. The data can be used to calculate the rate at which oxygen is taken up in the culture, which in turn can be used to determine the Sf9 cell growth rate (a quantity difficult to measure directly) and consistency of the operation from batch to batch. (a) Analysis of the exhaust gas at a time 25 hours after the process is started shows a composition of \(15.5 \mathrm{mol} \% \mathrm{O}_{2}, 78.7 \% \mathrm{N}_{2},\) and the balance \(\mathrm{CO}_{2}\) and small amounts of other gases. Determine the value of the oxygen use rate (OUR) in mmol \(\mathrm{O}_{2}\) consumed \((\mathrm{L} \cdot \mathrm{h})\) at that point in time. Assume that nitrogen is not absorbed by the culture. (b) OUR is related to cell concentration, \(X(\mathrm{g} \text { cells } / \mathrm{L}),\) by \(\mathrm{OUR}=q_{0_{2}} X,\) where \(q_{0_{2}}\) is the specific rate of oxygen consumption. Analysis of a sample of the culture taken at \(t=25 \mathrm{h}\) finds that the concentration of cells is \(5.0 \mathrm{g}\) cells/L. What is the value of \(q_{\mathrm{O}_{2}} ?\) (Do not forget to include its units.) (c) Six hours after this measurement, the exhaust gas contains 14.5 mol\% \(\mathrm{O}_{2}\) and the percentage of \(\mathrm{N}_{2}\) is unchanged. What is the concentration of cells, \(X,\) at that point? Assume that the specific rate of oxygen consumption does not change as long as the process temperature is constant. (d) The growth rate of cells can be expressed as: $$\frac{d X}{d t}=\mu_{\mathrm{g}} X$$ where \(\mu_{g}\) is the specific growth rate, with units of \(\mathrm{h}^{-1}\). Beginning with this equation and treating \(\mu_{\mathrm{g}}\) as a constant, derive an expression for \(t(X) .\) Use the data from the previous parts of the problem to determine \(\mu_{\mathrm{g}}\) (include units). Then calculate the cell-doubling time \(\left(t_{\mathrm{d}}\right),\) defined as the time for the cell concentration to double.

In an enzyme-catalyzed reaction with stoichiometry \(\mathrm{A} \rightarrow \mathrm{B}, \mathrm{A}\) is consumed at a rate given by an expression of the Michaelis-Menten form: $$r_{\mathrm{A}}[\operatorname{mol} /(\mathrm{L} \cdot \mathrm{s})]=\frac{k_{1} C_{\mathrm{A}}}{1+k_{2} C_{\mathrm{A}}}$$ where \(C_{\mathrm{A}}(\operatorname{mol} / \mathrm{L})\) is the reactant concentration, and \(k_{1}\) and \(k_{2}\) depend only on temperature. (a) The reaction is carried out in an isothermal batch reactor with constant reaction mixture volume \(V\) (liters), beginning with pure \(A\) at a concentration \(C_{\mathrm{A} 0}\). Derive an expression for \(d C_{\mathrm{A}} / d t\), and provide an initial condition. Sketch a plot of \(C_{\mathrm{A}}\) versus \(t,\) labeling the value of \(C_{\mathrm{A}}\) at \(t=0\) and the asymptotic value as \(t \rightarrow \infty\) (b) Solve the differential equation of Part (a) to obtain an expression for the time required to achieve a specified concentration \(C_{\mathrm{A}}\) (c) Use the expression of Part (b) to devise a graphical method of determining \(k_{1}\) and \(k_{2}\) from data for In versus the pour plot should involve fitting a straight line and determining the two parameters \(C_{\mathrm{A}}\) (int the parting of the partating and and the conting are a contation a conting from the slope and intercept of the line. (There are several possible solutions.) Then apply your method to determine \(k_{1}\) and \(k_{2}\) for the following data taken in a 2.00 -liter reactor, beginning with A at a concentration \(C_{\mathrm{A} 0}=5.00 \mathrm{mol} / \mathrm{L}\) $$\begin{array}{|l|l|l|l|l|l|} \hline t(\mathrm{s}) & 60.0 & 120.0 & 180.0 & 240.0 & 480.0 \\ \hline C_{\mathrm{A}}(\mathrm{mol} / \mathrm{L}) & 4.484 & 4.005 & 3.561 & 3.154 & 1.866 \\ \hline \end{array}$$

A steam coil is immersed in a stirred tank. Saturated steam at 7.50 bar condenses within the coil, and the condensate emerges at its saturation temperature. A solvent with a heat capacity of \(2.30 \mathrm{kJ} /\left(\mathrm{kg} \cdot^{\cdot} \mathrm{C}\right)\) is fed to the tank at a steady rate of \(12.0 \mathrm{kg} / \mathrm{min}\) and a temperature of \(25^{\circ} \mathrm{C},\) and the heated solvent is discharged at the same flow rate. The tank is initially filled with \(760 \mathrm{kg}\) of solvent at \(25^{\circ} \mathrm{C},\) at which point the flows of both steam and solvent are commenced. The rate at which heat is transferred from the steam coil to the solvent is given by the expression $$\dot{Q}=U A\left(T_{\mathrm{steam}}-T\right)$$ where \(U A\) (the product of a heat transfer coefficient and the coil surface area through which the heat is transferred) equals \(11.5 \mathrm{kJ} /\left(\min \cdot^{\circ} \mathrm{C}\right) .\) The tank is well stirred, so that the temperature of the contents is spatially uniform and equals the outlet temperature. (a) Prove that an energy balance on the tank contents reduces to the equation given below and supply an initial condition. \frac{d T}{d t}=1.50^{\circ} \mathrm{C} / \mathrm{min}-0.0224 T (b) Without integrating the equation, calculate the steady-state value of \(T\) and sketch the expected plot of \(T\) versus \(t,\) labeling the values of \(T_{\mathrm{b}}\) at \(t=0\) and \(t \rightarrow \infty\) (c) Integrate the balance equation to obtain an expression for \(T(t)\) and calculate the solvent temperature after 40 minutes. (d) The tank is shut down for routine maintenance, and a technician notices that a thin mineral scale has formed on the outside of the steam coil. The coil is treated with a mild acid that removes the scale and reinstalled in the tank. The process described above is run again with the same steam conditions, solvent flow rate, and mass of solvent charged to the tank, and the temperature after 40 minutes is \(55^{\circ} \mathrm{C}\) instead of the value calculated in Part (c). One of the system variables listed in the problem statement must have changed as a result of the change in the stirrer. Which variable would you guess it to be, and by what percentage of its initial value did it change?

One hundred fifty kmol of an aqueous phosphoric acid solution contains 5.00 mole\% \(\mathrm{H}_{3} \mathrm{PO}_{4}\). The solution is concentrated by adding pure phosphoric acid at a rate of \(20.0 \mathrm{L} / \mathrm{min}\). (a) Write a differential mole balance on phosphoric acid and provide an initial condition. [Start by defining \(n_{\mathrm{p}}(\mathrm{kmol})\) to be the total quantity of phosphoric acid in the tank at any time.] Without solving the equation, sketch a plot of \(n_{\mathrm{p}}\) versus \(t\) and explain your reasoning. (b) Solve the balance to obtain an expression for \(n_{\mathrm{p}}(t) .\) Use the result to derive an expression for \(x_{\mathrm{p}}(t)\) the mole fraction of phosphoric acid in the solution. Without doing any numerical calculations, sketch a plot of \(x_{\mathrm{p}}\) versus \(t\) from \(t=0\) to \(t \rightarrow \infty,\) labeling the initial and asymptotic values of \(x_{\mathrm{p}}\) on the plot. Explain your reasoning. (c) How long will it take to concentrate the solution to \(15 \% \mathrm{H}_{3} \mathrm{PO}_{4} ?\)

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