/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 A gas leak has led to the presen... [FREE SOLUTION] | 91Ó°ÊÓ

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A gas leak has led to the presence of 1.00 mole \(\%\) carbon monoxide in a \(350-\mathrm{m}^{3}\) laboratory. \(^{4}\) The leak was discovered and sealed, and the laboratory is to be purged with clean air to a point at which the air contains less than the OSHA (Occupational Safety and Health Administration) specified Permissible Exposure Level (PEL) of 35 ppm (molar basis). Assume that the clean air and the air in the laboratory are atthe same temperature and pressure and that the laboratory air is perfectly mixed throughout the purging process. (a) Let \(t_{\mathrm{r}}(\mathrm{h})\) be the time required for the specified reduction in the carbon monoxide concentration. Write a differential CO mole balance, letting \(N\) equal the total moles of gas in the room (assume constant), the mole fraction of CO in the room air, and \(\dot{V}_{\mathrm{p}}\left(\mathrm{m}^{3} / \mathrm{h}\right)\) the flow rate of purge air entering the room (and also the flow rate of laboratory air leaving the room). Convert the balance into an equation for \(d x / d t\) and provide an initial condition. Sketch a plot of \(x\) versus \(t,\) labeling the value of \(x\) at \(t=0\) and the asymptotic value at \(t \rightarrow \infty\) (b) Integrate the balance to derive an equation for \(t_{r}\) in terms of \(\dot{V}_{\mathrm{p}}\) (c) If the volumetric flow rate is \(700 \mathrm{m}^{3} / \mathrm{h}\) (representing a tumover of two room volumes per hour), how long will the purge take? What would the volumetric flow rate have to be to cut the purge time in half? (d) Give several reasons why it might not be safe to resume work in the laboratory after the calculated purge time has elapsed. What precautionary steps would you advise taking at this point?

Short Answer

Expert verified
The calculated time to reduce the carbon monoxide concentration to the permissible level under the described conditions is approximately 3.99 hours. The required purge rate to halve this time is 1400 m^3/h. However, the actual time may be longer due to non-ideal conditions, and proper precautions should be taken.

Step by step solution

01

Derive a Differential Mole Balance

The required mole balance is derived by taking into account that the change in the number of moles of CO in the room over time is equal to the rate of CO entering minus the rate of CO leaving. This can be written as \(\frac{dN_{CO}}{dt} = \dot{V}_{p}x_{0} - \dot{V}_{p}x\), where\(N_{CO}\) are the moles of CO in the room at time t, \(x_{0}\) is the initial mole fraction of CO, and \(x\) is the mole fraction of CO at time t. Since the total moles of gas in the room is constant, we can write\(N_{CO}= Nx\) with N the total moles of gas, leading to \(N\frac{dx}{dt} = \dot{V}_{p}(x_{0}-x)\). The initial condition is \(x(0) = x_{0}\). For the plot, \(x\) will decrease gradually from \(x_{0}\) at \(t=0\) to an asymptotic value of 0 as \(t \rightarrow \infty\).
02

Integration of the Balance Equation

To find the time needed to reduce CO to acceptable limits, integrate the differential equation. Separation of variables and subsequent integration results in \(N\int_{x_{0}}^{x}\frac{dx}{x_{0}-x}= \dot{V}_{p}\int_{0}^{t}dt\), which simplifies to \(-N\log\frac{x}{x_{0}}= \dot{V}_{p} t\). Solving for \(t\) provides an expression for the necessary time for the CO concentration to be reduced from \(x_{0}\) to \(x\), namely \(t=-\frac{N}{ \dot{V}_{p}}\log\frac{x}{x_{0}}\).
03

Time for Purification and Required Flow Rate

The permissible exposure level is 35 ppm or 35x10^-6 in mole fraction. Substituting this for \(x\), the initial \(x_{0}\) of 1 mole%, or 0.01 in mole fraction, the total moles of gas \(N\) as volume/22.4 since 1 mole occupies 22.4 m^3 at standard conditions, and \(\dot{V}_{p}\) of 700 m^3/h, we find \(t=-\frac{350/22.4}{700}\log\frac{35x10^-6}{0.01} \approx 3.99\) hours. To cut the purge time in half, we need to double the purge rate to 1400 m^3/h.
04

Safety Precautions

Resuming work in the lab immediately after the calculated purge time might not be safe because the calculation assumes perfect mixing of the gases, which may not be the case. It also assumes that the CO source has been completely stopped, but there may still be residual CO. As a precaution, the CO level should be monitored before resuming operations, the area should be properly ventilated, and an inspection of the lab should be performed to identify any potential sources of residual CO.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gas Purging
Gas purging is a vital safety procedure that ensures harmful gases, such as carbon monoxide, are removed from an enclosed space. The process involves flushing the enclosed area with a clean, inert gas—often air—to reduce the concentration of unwanted gases to a safe level. In the context of industrial settings or laboratories, achieving a low concentration is crucial to prevent health hazards.
When conducting gas purging, it is important to:
  • Calculate the volume of the space accurately to determine the right flow rate for the purging gas.
  • Use an appropriate flow rate to ensure that the gas mixture is effectively diluted and replaced over time.
  • Maintain uniform conditions such as temperature and pressure to enhance mixing throughout the area.
Effective gas purging requires a proper understanding of gas dynamics and the specific characteristics of the space being purged. Continuous monitoring of gas levels ensures that the process is successful and that the air quality is restored to a safe standard.
Carbon Monoxide Exposure
Carbon monoxide (CO) is a colorless, odorless, and toxic gas that poses significant health risks upon exposure. Even at low concentrations, CO can lead to serious health effects, which makes understanding its exposure levels critical, especially in occupational environments. The Occupational Safety and Health Administration (OSHA) has established a permissible exposure limit (PEL) for workplaces, which is 35 parts per million (ppm). Exceeding this limit can result in symptoms ranging from headaches and dizziness to much more severe health complications, like impaired cognitive function, or even death in extreme cases.
To protect against CO exposure:
  • Regular monitoring of air quality is important, to quickly identify any rise in CO levels above safe limits.
  • Install CO detectors in strategic locations, especially in areas prone to gas accumulation.
  • Ensure adequate ventilation and continue to educate workers about recognizing potential symptoms of CO exposure.
Understanding the properties of CO and maintaining vigilant safety measures creates a safer and healthier environment.
Differential Equations
Differential equations are mathematical equations that describe how quantities change over time, often used in modeling dynamic systems in various fields including engineering and physics. In the case of gas purging, they help describe how the concentration of a gas changes as clean air is introduced.
To model the reduction of carbon monoxide concentration, a differential equation balances the input and output rates of the gases involved. For example, the rate of CO leaving the laboratory is balanced against the mole fraction of CO present and the volumetric flow rate of the incoming clean air:\[\frac{dx}{dt} = -\frac{\dot{V}_{p}}{N}(x - x_{0})\]This equation simplifies understanding the relationship between different variables involved in gas purging. Solving this differential equation helps to determine the time required to achieve a desired concentration level, ensuring that safety standards are met. Understanding and correctly applying differential equations is essential for accurate modeling and decision-making in engineering contexts.
Occupational Safety
Occupational safety is crucial in any workplace to protect workers from health hazards that may occur due to exposure to harmful substances or unsafe practices. In scenarios involving gas leaks, such as the carbon monoxide instance in the exercise, it is paramount to have effective safety protocols in place.
Key considerations for occupational safety in such situations include:
  • Thoroughly checking that leaks are sealed before attempting to purify the air.
  • Ensuring that the purging process is complete and has achieved concentrations below the acceptable limits before resuming work.
  • Performing regular safety audits and training sessions to keep workers informed and ready to act during emergencies.
Resuming activities without ensuring the safe completion of these steps might still leave workers exposed to potential health risks. Investing in preventive measures, ongoing monitoring, and upkeep of equipment reduces risks and creates a safer working environment. Understanding and implementing occupational safety standards keeps both workers and businesses protected.

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Most popular questions from this chapter

A kettle containing 3.00 liters of water at a temperature of \(18^{\circ} \mathrm{C}\) is placed on an electric stove and begins to boil in three minutes. (a) Write an energy balance on the water and determine an expression for \(d T / d t,\) neglecting evaporation of water before the boiling point is reached, and provide an initial condition. Sketch a plot of \(T\) versus \(t\) from \(t=0\) to \(t=4\) minutes. (b) Calculate the average rate (W) at which heat is being added to the water. Then calculate the rate (g/s) at which water vaporizes once boiling begins. (c) The rate of heat output from the stove element differs significantly from the heating rate calculated in Part (b). In which direction, and why?

A steam radiator is used to heat a \(60-\mathrm{m}^{3}\) room. Saturated steam at 3.0 bar condenses in the radiator and emerges as a liquid at the saturation temperature. Heat is lost from the room to the outside at a rate $$\dot{Q}(\mathrm{kJ} / \mathrm{h})=30.0\left(T-T_{0}\right)$$ where \(T\left(^{\circ} \mathrm{C}\right)\) is the room temperature and \(T_{0}=0^{\circ} \mathrm{C}\) is the outside temperature. At the moment the radiator is turned on, the temperature in the room is \(10^{\circ} \mathrm{C}\). (a) Let \(\dot{m}_{\mathrm{s}}(\mathrm{kg} / \mathrm{h})\) denote the rate at which steam condenses in the radiator and \(n(\mathrm{kmol})\) the quantity of air in the room. Write a differential energy balance on the room air, assuming that \(n\) remains constant at its initial value, and evaluate all numerical coefficients. Take the heat capacity of air \(\left(C_{v}\right)\) to be constant at \(20.8 \mathrm{J} /\left(\mathrm{mol} \cdot^{\circ} \mathrm{C}\right)\) (b) Write the steady-state energy balance on the room air and use it to calculate the steam condensation rate required to maintain a constant room temperature of \(24^{\circ} \mathrm{C}\). Without integrating the transient balance, sketch a plot of \(T\) versus \(t,\) labeling both the initial and maximum values of \(T\) (c) Integrate the transient balance to calculate the time required for the room temperature to rise by \(99 \%\) of the interval from its initial value to its steady-state value, assuming that the steam condensation rate is that calculated in Part (b).

Water is added at varying rates to a 300 -liter holding tank. When a valve in a discharge line is opened, water flows out at a rate proportional to the height and hence to the volume \(V\) of water in the tank. The flow of water into the tank is slowly increased and the level rises in consequence, until at a steady input rate of \(60.0 \mathrm{L} / \mathrm{min}\) the level just reaches the top but does not spill over. The input rate is then abruptly decreased to \(40.0 \mathrm{L} / \mathrm{min}\). (a) Write the equation that relates the discharge rate, \(\dot{V}_{\text {out }}(\mathrm{L} / \mathrm{min}),\) to the volume of water in the tank, \(V(\mathrm{L}),\) and use it to calculate the steady-state volume when the input rate is \(40 \mathrm{L} / \mathrm{min}\). (b) Write a differential balance on the water in the tank for the period from the moment the input rate is decreased \((t=0)\) to the attainment of steady state \((t \rightarrow \infty),\) expressing it in the form \(d V / d t=\cdots \cdot\) Provide an initial condition. (c) Without integrating the equation, use it to confirm the steady-state value of \(V\) calculated in Part (a) and then to predict the shape you would anticipate for a plot of \(V\) versus \(t\). Explain your reasoning. (d) Separate variables and integrate the balance equation to derive an expression for \(V(t)\). Calculate the time in minutes required for the volume to decrease to within \(1 \%\) of its steady-state value.

A 10.0 -ft compressed-air tank is being filled. Before the filling begins, the tank is open to the atmosphere. The reading on a Bourdon gauge mounted on the tank increases linearly from an initial value of 0.0 to 100 psi after 15 seconds. The temperature is constant at \(72^{\circ} \mathrm{F}\), and atmospheric pressure is 1 atm. (a) Calculate the rate \(\dot{n}\) (lb-mole/s) at which air is being added to the tank, assuming ideal-gas behavior. (Suggestion: Start by calculating how much is in the tank at \(t=0 .)\) (b) Let \(N(t)\) equal the number of Ib-moles of air in the tank at any time. Write a differential balance on the air in the tank in terms of \(N\) and provide an initial condition. (c) Integrate the balance to obtain an expression for \(N(t)\). Check your solution two ways. (d) Estimate the Ib-moles of oxygen in the tank after two minutes. List reasons your answer might be inaccurate, assuming there are no mistakes in your calculation.

A gas that contains \(\mathrm{CO}_{2}\) is contacted with liquid water in an agitated batch absorber. The equilibrium solubility of \(\mathrm{CO}_{2}\) in water is given by Henry's law (Section \(6.4 \mathrm{b}\) ) $$C_{\mathrm{A}}=p_{\mathrm{A}} / H_{\mathrm{A}}$$ where \(C_{\mathrm{A}}\left(\mathrm{mol} / \mathrm{cm}^{3}\right)=\) concentration of \(\mathrm{CO}_{2}\) in solution, \(p_{\mathrm{A}}(\mathrm{atm})=\) partial pressure of \(\mathrm{CO}_{2}\) in the gas phase, and \(H_{\mathrm{A}}\left[\mathrm{atm} /\left(\mathrm{mol} / \mathrm{cm}^{3}\right)\right]=\) Henry's law constant. The rate of absorption of \(\mathrm{CO}_{2}\) (i.e., the rate of transfer of \(\mathrm{CO}_{2}\) from the gas to the liquid per unit area of gas-liquid interface) is given by the expression $$r_{\mathrm{A}}\left[\operatorname{mol} /\left(\mathrm{cm}^{2} \cdot \mathrm{s}\right)\right]=k\left(C_{\mathrm{A}}^{*}-C_{\mathrm{A}}\right)$$ where \(C_{A}=\) actual concentration of \(\mathrm{CO}_{2}\) in the liquid, \(C_{\mathrm{A}}^{*}=\) concentration of \(\mathrm{CO}_{2}\) in the liquid that would be in equilibrium with the \(\mathrm{CO}_{2}\) in the gas phase, and \(k(\mathrm{cm} / \mathrm{s})=\) a mass transfer coefficient. The gas phase is at a total pressure \(\mathrm{P}\left(\text { atm) and contains } y_{\mathrm{A}}\left(\mathrm{mol} \mathrm{CO}_{2} / \mathrm{mol}\text { gas), and the liquid }\right.\right.\) phase initially consists of \(V\left(\mathrm{cm}^{3}\right)\) of pure water. The agitation of the liquid phase is sufficient for the composition to be considered spatially uniform, and the amount of \(\mathrm{CO}_{2}\) absorbed is low enough for \(P, V,\) and \(y_{\mathrm{A}}\) to be considered constant throughout the process. (a) Derive an expression for \(d C_{\mathrm{A}} / d t\) and provide an initial condition. Without doing any calculations, sketch a plot of \(C_{\mathrm{A}}\) versus \(t,\) labeling the value of \(C_{\mathrm{A}}\) at \(t=0\) and the asymptotic value at \(t \rightarrow \infty\) Give a physical explanation for the asymptotic value of the concentration. (b) Prove that $$C_{\mathrm{A}}(t)=\frac{p_{\mathrm{A}}}{H_{\mathrm{A}}}[1-\exp (-k S t / V)]$$ where \(S\left(\mathrm{cm}^{2}\right)\) is the effective contact area between the gas and liquid phases. (c) Suppose the system pressure is 20.0 atm, the liquid volume is 5.00 liters, the tank diameter is \(10.0 \mathrm{cm},\) the gas contains 30.0 mole \(\% \mathrm{CO}_{2},\) the Henry's law constant is \(9230 \mathrm{atm} / \mathrm{mole} / \mathrm{cm}^{3}\) ), and the mass transfer coefficient is \(0.020 \mathrm{cm} / \mathrm{s}\). Calculate the time required for \(C_{\mathrm{A}}\) to reach \(0.620 \mathrm{mol} / \mathrm{L}\) if the gas-phase properties remain essentially constant. (d) If A were not \(\mathrm{CO}_{2}\) but instead a gas with a moderately high solubility in water, the expression for \(C_{\mathrm{A}}\) given in Part (b) would be incorrect. Explain where the derivation that led to it would break down.

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