/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 A sample of \(\mathrm{H}_{2} \ma... [FREE SOLUTION] | 91Ó°ÊÓ

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A sample of \(\mathrm{H}_{2} \mathrm{S}\) gas is placed in an evacuated, sealed container and heated until the following decomposition reaction occurs at \(1000 \mathrm{K} :\) \(2 \mathrm{H}_{2} \mathrm{S}(g) \rightarrow 2 \mathrm{H}_{2}(g)+\mathrm{S}_{2}(g) \qquad K_{\mathrm{c}}=1.0 \times 10^{-6}\) (A) \(K_{\mathrm{c}}=\frac{\left[\mathrm{H}_{2}\right]^{2}\left[\mathrm{S}_{2}\right]}{\left[\mathrm{H}_{2} \mathrm{S}\right]^{2}}\) (B) \(K_{\mathrm{c}}=\frac{\left[\mathrm{H}_{2} \mathrm{S}\right]^{2}}{\left[\mathrm{H}_{2}\right]^{2}\left[\mathrm{S}_{2}\right]}\) (C) \(K_{\mathrm{c}}=\frac{2\left[\mathrm{H}_{2}\right]\left[\mathrm{S}_{2}\right]}{2\left[\mathrm{H}_{2} \mathrm{S}\right]}\) (D) \(K_{\mathrm{c}}=\frac{2\left[\mathrm{H}_{2} \mathrm{S}\right]}{2\left[\mathrm{H}_{2}\right]\left[\mathrm{S}_{2}\right]}\)

Short Answer

Expert verified
The correct expression for the equilibrium constant is (A) \(K_{\mathrm{c}}=\frac{\left[\mathrm{H}_{2}\right]^{2}\left[\mathrm{S}_{2}\right]}{\left[\mathrm{H}_{2} \mathrm{S}\right]^{2}}\).

Step by step solution

01

Understand the law of mass action for the reaction

The law of mass action stipulates that for a reaction of the form \(aA + bB \rightarrow cC + dD\), the equilibrium constant expression can be defined as \[K_c = \frac{[C]^c [D]^d}{[A]^a [B]^b}\], where the brackets represent the molar concentrations of the respective substances at equilibrium and a, b, c, d are the stoichiometric coefficients. In this case, the reaction is \(2 \mathrm{H}_{2} \mathrm{S}(g) \rightarrow 2 \mathrm{H}_{2}(g)+\mathrm{S}_{2}(g)\). Therefore, a and b should be 2, whereas c and d should also be 2.
02

Identify the given options for \(K_{c}\) expressions

Here, the alternatives for the \(K_c\) expression are (A) \(\frac{\left[\mathrm{H}_{2}\right]^{2}\left[\mathrm{S}_{2}\right]}{\left[\mathrm{H}_{2} \mathrm{S}\right]^{2}}\), (B) \(\frac{\left[\mathrm{H}_{2} \mathrm{S}\right]^{2}}{\left[\mathrm{H}_{2}\right]^{2}\left[\mathrm{S}_{2}\right]}\), (C) \(\frac{2\left[\mathrm{H}_{2}\right]\left[\mathrm{S}_{2}\right]}{2\left[\mathrm{H}_{2} \mathrm{S}\right]}\), and (D) \(\frac{2\left[\mathrm{H}_{2} \mathrm{S}\right]}{2\left[\mathrm{H}_{2}\right]\left[\mathrm{S}_{2}\right]}\)
03

Choose the correct expression for \(K_{c}\)

By analyzing the four options given, it can be found that only Option (A) is consistent with the law of mass action. The expression \(K_{c} = \frac{\left[\mathrm{H}_{2}\right]^{2}\left[\mathrm{S}_{2}\right]}{\left[\mathrm{H}_{2} \mathrm{S}\right]^{2}}\) includes the correct stoichiometric coefficients in the reaction and correctly represents the molar concentration ratios at equilibrium. Therefore, the correct option is (A).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Law of Mass Action
The law of mass action is a fundamental principle in chemistry that helps us understand how concentrations of substances influence the behavior of chemical reactions at equilibrium. According to this law, the equilibrium constant expression for a chemical reaction can be determined by the formula:
  • \[K_c = \frac{[C]^c [D]^d}{[A]^a [B]^b}\]
Here,
  • \([A]\), \([B]\), \([C]\), and \([D]\) are the molar concentrations of the reactants and products at equilibrium.
  • The letters \(a\), \(b\), \(c\), and \(d\) serve as stoichiometric coefficients, representing the number of moles of each substance involved in the reaction.

By using this expression, we can relate the concentrations of different substances in a reversible reaction and predict the composition of the mixture at equilibrium.
Understanding the law of mass action is crucial when analyzing any reaction, and particularly when solving equilibrium problems like the decomposition of hydrogen sulfide (\(\mathrm{H}_2\mathrm{S}\)).This helps in constructing the correct equilibrium expressions necessary for calculating equilibrium constants.
Decomposition Reaction
A decomposition reaction is a type of chemical reaction where one compound breaks down into two or more simpler substances.
In the given problem, the decomposition of hydrogen sulfide, \(\mathrm{H}_2\mathrm{S}\), occurs:
  • \[2 \mathrm{H}_{2} \mathrm{S}(g) \rightarrow 2 \mathrm{H}_{2}(g)+\mathrm{S}_{2}(g)\]
This reaction shows that each molecule of hydrogen sulfide decomposes to produce hydrogen gas and sulfur gas.
This process of breaking down can often be initiated by heat, which provides the energy needed to overcome the energy barrier of the decomposition.

Important Features of Decomposition Reactions:

- **Energy Requirement**: Often require an external energy source like heat or light.
- **Simplicity**: A single reactant gives multiple products.
- **Unidirectional**: Generally proceed in one direction, leading to simpler components.Understanding decomposition reactions helps in predicting the products and determining the stoichiometric coefficients used in chemical equilibrium expressions.
Stoichiometric Coefficients
Stoichiometric coefficients are the numbers used to balance chemical equations. These numbers indicate the ratio in which substances react or form in a given chemical reaction.
In the decomposition of \(\mathrm{H}_{2}\mathrm{S}\), the balanced equation is:
  • \[2 \mathrm{H}_{2} \mathrm{S}(g) \rightarrow 2 \mathrm{H}_{2}(g)+\mathrm{S}_{2}(g)\]

Key Points About Stoichiometric Coefficients:

- **Quantitative Measure**: They tell us the exact amount of reactants needed and products formed.
- **Determining Factors**: Help in establishing the correct proportions of substances involved.
- **Connected with Mole Concept**: Directly associated with the number of molecules, often corresponding to moles.Understanding stoichiometric coefficients allows us to write the correct equilibrium expression. This assures that the relationships between reactants and products are balanced, consistent with the law of mass action, which uses these coefficients to formulate accurate predictions of equilibrium constants.
Chemical Equilibrium Expressions
Chemical equilibrium expressions provide a snapshot of the chemical system at the point where the rates of the forward and reverse reactions are equal.
At equilibrium, the actual amounts of substances in the reaction mixture remain constant over time.
In the case of \(\mathrm{H}_{2}\mathrm{S}\)'s decomposition, the chemical equilibrium expression is derived from the law of mass action, using the balanced equation:
  • \[ K_c = \frac{[\mathrm{H}_2]^2 [\mathrm{S}_2]}{[\mathrm{H}_2\mathrm{S}]^2}\]
The equilibrium constant \(K_c\) helps us predict the concentrations of products and reactants at equilibrium.

Significance of Chemical Equilibrium Expressions:

- **Predictive Measure**: Indicates how far the reaction proceeds toward the products.
- **Reaction Direction**: A larger \(K_c\) means more product is formed; a smaller \(K_c\) implies more reactants remain.
- **Equilibrium Position**: Helps in assessing if the equilibrium lies to the left (favoring reactants) or right (favoring products).Crafting accurate chemical equilibrium expressions ensures a comprehensive understanding of the dynamic balance in chemical reactions, such as the one presented in this exercise.

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Most popular questions from this chapter

An unknown substance is found to have a high melting point. In addition, it is a poor conductor of electricity and does not dissolve in water. The substance most likely contains (A) ionic bonding (B) nonpolar covalent bonding (C) covalent network bonding (D) metallic bonding

$$\begin{array}{|c|c|c|}\hline & {\text { Initial pH }} & {\text { PH after NaOH }} \\ \hline \text { Acid 1 } & {3.0} & {3.5} \\ \hline \text { Acid 2 } & {3.0} & {5.0} \\ \hline\end{array}$$ Two different acids with identical pH are placed in separate beakers. Identical portions of NaOH are added to each beaker, and the resulting pH is indicated in the table above. What can be determined about the strength of each acid? (A) Acid 1 is a strong acid and acid 2 is a weak acid because acid 1 resists change in pH more effectively. (B) Acid 1 is a strong acid and acid 2 is a weak acid because the NaOH is more effective at neutralizing acid 2. (C) Acid 1 is a weak acid and acid 2 is a strong acid because the concentration of the weak acid must be significantly greater to have the same pH as the strong acid. (D) Acid 1 is a weak acid and acid 2 is a strong acid because the concentration of the hydrogen ions will be greater in acid 2 after the NaOH addition.

Atoms of four elements are examined: carbon, nitrogen, neon, and sulfur. Atoms of which element are most likely to form a structure with the formula \(\mathrm{XF}_{6}\) (where \(\mathrm{X}\) is one of the four atoms)? (A) Carbon (B) Nitrogen (C) Neon (D) Sulfur

Hydrogen fluoride, HF, is a liquid at \(15^{\circ} \mathrm{C}\) . All other hydrogen halides (represented by HX, where \(\mathrm{X}\) is any other halogen) are gases at the same temperature. Why? (A) Fluorine has a very high electronegativity; therefore, the H–F bond is stronger than any other H–X bond. (B) HF is smaller than any other H–X molecule; therefore, it exhibits stronger London dispersion forces. (C) The dipoles in a HF molecule exhibit a particularly strong attraction force to the dipoles in other HF molecules. (D) The H–F bond is the most ionic in character compared to all other hydrogen halides.

A rigid, sealed 12.00 \(\mathrm{L}\) container is filled with 10.00 \(\mathrm{g}\) each of three different gases: \(\mathrm{CO}_{2}, \mathrm{NO},\) and \(\mathrm{NH}_{3}\) . The temperature of the gases is held constant \(35.0^{\circ} \mathrm{C} .\) Assume ideal behavior for all gases. (a) (i) What is the mole fraction of each gas? (ii) What is the partial pressure of each gas? (b) Out of the three gases, molecules of which gas will have the highest velocity? Why? (c) Name one circumstance in which the gases might deviate from ideal behavior, and clearly explain the reason for the deviation.

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