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Which gas exerts the greatest pressure? (A) He (B) Ne (C) NO (D) All gases exert the same amount of pressure.

Short Answer

Expert verified
(D) All gases exert the same amount of pressure, according to the ideal gas law.

Step by step solution

01

Understand the nature of gases

First, it's essential to remember that, according to the ideal gas law (\(PV=nRT\)), the pressure exerted by a gas depends on the temperature, volume, and number of gas molecules present and not the nature or type of the gas.
02

Apply the gas law to all the given options

Applying the ideal gas law to all the options, we find that regardless of whether the gas is He, Ne, or NO, under the same conditions (the same volume, temperature, and number of particles), they all exert the same pressure.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pressure of Gases
The pressure of a gas is a measure of how forcefully the gas particles are colliding with the walls of their container. This pressure is explained through the ideal gas law, represented as \(PV = nRT\). In this equation:
  • \(P\) stands for pressure.
  • \(V\) is the volume of the container.
  • \(n\) represents the number of moles of gas molecules.
  • \(R\) is the ideal gas constant.
  • \(T\) indicates the temperature in Kelvin.
The key takeaway here is that the pressure exerted by the gas depends on these variables rather than the specific type of gas. This means that different gases, like helium (He), neon (Ne), and nitrogen monoxide (NO), will exert the same pressure when kept under identical conditions of volume, temperature, and number of moles. This understanding is vital because it highlights the universal behavior of gas pressure across different types of gases when assessed in a standardized scenario.
Volume and Temperature
Volume and temperature play crucial roles in determining the behavior of gases. According to the ideal gas law, if a gas is contained in a flexible balloon, any increase in temperature will make the gas particles move faster, increasing the pressure and potentially expanding the balloon volume as a result.
It's essential to remember that:
  • A higher temperature results in more energetic collisions of gas particles, pushing against the walls with greater force, increasing the pressure.
  • Volume is the space the gas occupies. If the volume increases while the number of particles and temperature remain constant, the pressure will tend to decrease – this is described by Boyle's Law.
By understanding these relationships, you can predict how changing one variable can influence the others. For example, keeping the temperature constant while decreasing the volume forces the particles into a smaller space, increasing the pressure. Conversely, if you heat the gas while maintaining the volume constant, the pressure will rise as particles speed up.
Nature of Gases
Gases are unique in that they do not have a fixed shape or constant volume. Their nature is characterized by the ability to fill any container they are in completely. This behavior makes the pressure exerted by a gas on the container's walls depend more on the conditions (such as volume and temperature) than on the gas's chemical characteristics.
An important aspect of the nature of gases is their ability to mix completely and uniformly with other gases, often termed as 'ideal behavior.' This is effectively modeled through the ideal gas law, which provides a good approximation for many gases under various conditions.
This ideal nature of gases allows us to predict their behavior under different environmental conditions without concerning ourselves with the specific identities of the gas molecules involved. Hence, whether you are analyzing helium, neon, or nitrogen monoxide, if they are under the same conditions, their behaviors are expected to be the same in terms of pressure exertion.

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Most popular questions from this chapter

Questions 54-56 refer to the following. GRAPH CAN'T COPY Between propane and ethene, which will likely have the higher boiling point and why? (A) Propane, because it has a greater molar mass (B) Propane, because it has a more polarizable electron cloud (C) Ethene, because of the double bond (D) Ethene, because it is smaller in size

When calcium chloride \(\left(\mathrm{CaCl}_{2}\right)\) dissolves in water, the temperature of the water increases dramatically. During this reaction, heat transfers from (A) the reactants to the products (B) the reactants to the system (C) the system to the surroundings (D) the products to the surroundings

150 \(\mathrm{mL}\) of saturated \(\mathrm{SrF}_{2}\) solution is present in a 250 \(\mathrm{mL}\) beaker at room temperature. The molar solubility of \(\mathrm{SrF}_{2}\) at 298 \(\mathrm{K}\) is \(1.0 \times 10^{-3} \mathrm{M}\) . How could the concentration of \(\mathrm{Sr}^{2+}\) ions in solution be decreased? (A) Adding some \(\operatorname{NaF}(s)\) to the beaker (B) Adding some \(\operatorname{Sr}\left(\mathrm{NO}_{3}\right)_{2}(s)\) to the beaker (C) By heating the solution in the beaker (D) By adding a small amount of water to the beaker, but not dissolving all the solid

\(2 \mathrm{HI}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons 2 \mathrm{HCl}(g)+\mathrm{I}_{2}(g)+\) energy A gaseous reaction occurs and comes to equilibrium, as shown above. Which of the following changes to the system will serve to increase the number of moles of \(\mathrm{I}_{2}\) present at equilibrium? (A) Increasing the volume at constant temperature (B) Decreasing the volume at constant temperature (C) Increasing the temperature at constant volume (D) Decreasing the temperature at constant volume

A sample of a compound known to consist of only carbon, hydrogen, and oxygen is found to have a total mass of 29.05 g. If the mass of the carbon is 18.02 g and the mass of the hydrogen is 3.03 g, what is the empirical formula of the compound? (A) \(\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}\) (B) \(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}\) (C) \(\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}_{3}\) (D) \(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}_{2}\)

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