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The enthalpy change for which of the following reactions would be equal to the enthalpy of formation for ethanol \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\right)\) ? (A) \(\mathrm{CH}_{3}+\mathrm{CH}_{2}+\mathrm{OH} \rightarrow \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) (B) \(2 \mathrm{C}+5 \mathrm{H}+\mathrm{O} \rightarrow \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) (C) \(4 \mathrm{C}+6 \mathrm{H}_{2}+\mathrm{O}_{2} \rightarrow 2 \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) (D) \(2 \mathrm{C}+3 \mathrm{H}_{2}+\frac{1}{2} \mathrm{O}_{2} \rightarrow \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\)

Short Answer

Expert verified
The enthalpy change for the reaction as defined in option (D) would be equal to the enthalpy of formation for ethanol.

Step by step solution

01

Understanding Enthalpy of Formation

The enthalpy of formation of a compound is the change in enthalpy that accompanies the formation of 1 mole of the compound from its elements, with all substances in their standard states at 1 atm. The substances in their standard states refers to the most stable form of the substances under normal conditions (1 atm pressure and room temperature).
02

Analyze Given Options

For each of the options, analyze the reactants to see if they are in their standard states: \[ (A) CH_{3} + CH_{2} + OH \] These are not the standard states of Carbon, Hydrogen, and Oxygen. \[ (B) 2C + 5H + O \] Hydrogen and Oxygen are not in their standard states here. Hydrogen in its standard state is H2 (hydrogen molecule) and Oxygen in its standard state is O2 (oxygen molecule). \[ (C) 4C + 6H2 + O2 \] Although the elements are in their standard states, the reaction gives 2 moles of ethanol. The enthalpy of formation should correspond to the formation of 1 mole of the compound. \[ (D) 2C + 3H2 + 0.5O2 \] This reaction involves the elements in their standard states and forms one mole of ethanol. Therefore, this is the correct answer.
03

Selection of Answer

After analyzing all the given options, it is clear that option (D) provides the correct stoichiometry for the enthalpy of formation for ethanol. The reaction contains all the elements required for the formation of ethanol in their standard states and forms one mole of ethanol, which is consistent with the definition of enthalpy of formation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard State
Understanding the concept of standard state is crucial when dealing with enthalpy of formation. The standard state of a substance is its most stable form at 1 atmosphere of pressure and a specified temperature, often 25°C (or 298 K). This standard state is used as a reference point for thermodynamic calculations. For example:
  • Carbon in its standard state is graphite, rather than diamond.
  • Hydrogen's standard state is the diatomic molecule \( ext{H}_2\), a gas at room temperature.
  • Similarly, oxygen's standard state is \( ext{O}_2\), also a diatomic gas.
When measuring enthalpy changes, like the enthalpy of formation, it's important that all reactants are in their standard states. This ensures consistency across reactions and calculations. In the context of forming ethanol, the reaction must start with carbon, hydrogen, and oxygen in their respective standard states. This is why understanding and identifying substances in their standard state is a fundamental skill in chemistry.
Stoichiometry
Stoichiometry involves the calculation of reactants and products in chemical reactions. Essentially, it's the math behind chemistry, ensuring that the amounts of substances in a chemical reaction are proportionally correct. This accuracy is vital when determining enthalpy changes, as it affects the energy measurements of forming a single mole of a compound. In our case, the formation of ethanol, \( ext{CH}_3 ext{CH}_2 ext{OH}\), from its elements requires the correct stoichiometry for the enthalpy of formation:
  • 2 moles of carbon (C), ideally in graphite form
  • 3 moles of \( ext{H}_2\) (hydrogen gas)
  • 0.5 moles of \( ext{O}_2\) (oxygen gas)
This balanced reaction ensures that one mole of ethanol is formed with all reactants in their standard states, matching the conditions needed for accurate enthalpy calculations. Proper stoichiometry is crucial for understanding and conducting chemical reactions. It provides a framework for predicting the amounts of products and reactants involved, as well as the energy changes that occur.
Ethanol Chemistry
Ethanol, chemically denoted as \( ext{CH}_3 ext{CH}_2 ext{OH}\), is a simple alcohol with a variety of applications ranging from being a fuel additive to a solvent in the pharmaceutical industry. Understanding how it is formed and its properties is essential in chemistry. Ethanol is often synthesized from ethylene due to its availability and efficiency, but its fundamental production from elemental carbon, hydrogen, and oxygen showcases basic chemical principles like stoichiometry and enthalpy of formation. For educational purposes, ethanol's enthalpy of formation provides a great context to apply these concepts. The reaction forming ethanol can also illustrate concepts such as:
  • The interaction of different elements to form specific compounds
  • The transformation of gaseous elements into a liquid compound
These interactions highlight how basic chemical principles interact to create compounds with unique characteristics and functions. In industry and laboratories, understanding the chemistry of ethanol ensures that its production is both efficient and environmentally sustainable, showcasing real-world applications of the chemical principles learners study.

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Most popular questions from this chapter

150 \(\mathrm{mL}\) of saturated \(\mathrm{SrF}_{2}\) solution is present in a 250 \(\mathrm{mL}\) beaker at room temperature. The molar solubility of \(\mathrm{SrF}_{2}\) at 298 \(\mathrm{K}\) is \(1.0 \times 10^{-3} \mathrm{M}\) . What are the concentrations of \(\mathrm{Sr}^{2+}\) and \(\mathrm{F}^{-}\) in the beaker? (A) \(\left[\mathrm{Sr}^{2+}\right]=1.0 \times 10^{-3} M\left[\mathrm{F}^{-}\right]=1.0 \times 10^{-3} M\) (B) \(\left[\mathrm{Sr}^{2+}\right]=1.0 \times 10^{-3} M\left[\mathrm{F}^{-}\right]=2.0 \times 10^{-3} M\) (C) \(\left[\mathrm{Sr}^{2+}\right]=2.0 \times 10^{-3} M\left[\mathrm{F}^{-}\right]=1.0 \times 10^{-3} M\) (D) \(\left[\mathrm{Sr}^{2+}\right]=2.0 \times 10^{-3} \mathrm{M}\left[\mathrm{F}^{-}\right]=2.0 \times 10^{-3} M\)

Nitrogen’s electronegativity value is between those of phosphorus and oxygen. Which of the following correctly describes the relationship between the three values? (A) The value for nitrogen is less than that of phosphorus because nitrogen is larger, but greater than that of oxygen because nitrogen has a greater effective nuclear charge. (B) The value for nitrogen is less than that of phosphorus because nitrogen has fewer protons, but greater than that of oxygen because nitrogen has fewer valence electrons. (C) The value for nitrogen is greater than that of phosphorus because nitrogen has fewer electrons, but less than that of oxygen because nitrogen is smaller. (D) The value for nitrogen is greater than that of phosphorus because nitrogen is smaller, but less than that of oxygen because nitrogen has a smaller effective nuclear charge.

150 \(\mathrm{mL}\) of saturated \(\mathrm{SrF}_{2}\) solution is present in a 250 \(\mathrm{mL}\) beaker at room temperature. The molar solubility of \(\mathrm{SrF}_{2}\) at 298 \(\mathrm{K}\) is \(1.0 \times 10^{-3} \mathrm{M}\) . How could the concentration of \(\mathrm{Sr}^{2+}\) ions in solution be decreased? (A) Adding some \(\operatorname{NaF}(s)\) to the beaker (B) Adding some \(\operatorname{Sr}\left(\mathrm{NO}_{3}\right)_{2}(s)\) to the beaker (C) By heating the solution in the beaker (D) By adding a small amount of water to the beaker, but not dissolving all the solid

Which of the following could be added to an aqueous solution of weak acid HF to increase the percent dissociation? (A) \(\operatorname{NaF}(s)\) (B) \(\mathrm{H}_{2} \mathrm{O}(l)\) (C) \(\mathrm{NaOH}(\mathrm{s})\) (D) \(\mathrm{NH}_{3}(a q)\)

\(\mathrm{Cu}^{2+}+2 e^{-} \rightarrow \mathrm{Cu} \quad E^{\circ}=+0.3 \mathrm{V}\) \(\mathrm{Fe}^{2+}+2 e^{-} \rightarrow \mathrm{Fe} \quad E^{\circ}=-0.4 \mathrm{V}\) Based on the reduction potentials given above, what is the reaction potential for the following reaction? \(\mathrm{Fe}^{2+}+\mathrm{Cu} \rightarrow \mathrm{Fe}+\mathrm{Cu}^{2+}\) (A) \(-0.7 \mathrm{V}\) (B) \(-0.1 \mathrm{V}\) (C) \(+0.1 \mathrm{V}\) (D) \(+0.7 \mathrm{V}\)

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