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Which of the following pairs of elements is most likely to create an interstitial alloy? (A) Titanium and copper (B) Aluminum and lead (C) Silver and tin (D) Magnesium and calcium

Short Answer

Expert verified
The most likely pair of elements to create an interstitial alloy is (D) Magnesium and Calcium, due to the significant difference in their atomic radii.

Step by step solution

01

Understand interstitial alloys

Interstitial alloys are a type of alloy where smaller atoms fill the gaps between larger metal atoms. These alloys have different properties than their base metals, including increased hardness and strength.
02

Compare the atomic radii of the elements in option A

The atomic radius of Titanium is approximately \(147pm\) and that of Copper is \(128pm\). The difference in size is small, making it less likely for an interstitial alloy to be formed.
03

Compare the atomic radii of the elements in option B

The atomic radius of Aluminum is approximately \(143pm\) and that of Lead is \(175pm\). Although Lead has a larger atomic radius, the difference is not significant enough for an interstitial alloy to be formed.
04

Compare the atomic radii of the elements in option C

The atomic radius of Silver is approximately \(160pm\) and that of Tin is \(140pm\). The difference in size is small, making it less likely for an interstitial alloy to be formed.
05

Compare the atomic radii of the elements in option D

The atomic radius of Magnesium is approximately \(150pm\) and that of Calcium is \(197pm\). The difference in size is significant, making it possible for an interstitial alloy to be formed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Radius
The atomic radius of an element is the distance from the nucleus of an atom to the outermost boundary of its electron cloud. This measurement is crucial when considering the formation of alloys. The size of different atoms plays a significant role in determining whether an interstitial alloy can form.

For interstitial alloys, smaller atoms need to fit into the gaps between larger metal atoms, which requires a considerable size difference. When two elements have a similar atomic radius, they are less likely to form interstitial alloys because there isn't enough space for the smaller atoms to fit between the larger ones.

In the context of the problem, we observe that Magnesium and Calcium, with atomic radii of 150 pm and 197 pm respectively, have a more pronounced size difference compared to other pairs, like Silver and Tin. This greater size differential facilitates the interstitial inclusion of smaller atoms and distinguishes interstitial alloys from substitutional ones, where atomic size similarity is more favorable.
Alloy Properties
Alloys are combinations of metals that aim to improve upon the properties of the base metals. Interstitial alloys, specifically, have unique characteristics because of their structure.

When smaller atoms lodge themselves between the larger metal atoms without replacing them, they affect the physical properties of the alloy. The insertion of these small atoms in between the larger ones can lead to:
  • Increased hardness: The tight packing of atoms restricts movement, making the material harder.
  • Enhanced strength: The randomness and density of atom placement confer additional strength to the material.

In practical applications, the changes in properties make interstitial alloys valuable in industries requiring durable materials, such as construction and manufacturing tools. Understanding alloy properties helps chemists design materials with specific traits.
Metal Atoms
Metal atoms are central to the formation of all types of alloys. They are usually organized in crystalline structures that allow them to combine with other metal or non-metal atoms. When forming interstitial alloys, these metal atoms serve as the base structure into which smaller atoms can fit.

In crystalline metals, the spaces between atoms are called interstitial sites. It's these vacant spaces that smaller atoms occupy to form interstitial alloys. The choice of metal atoms is crucial since it determines how well the smaller atoms can fit and stabilize within the metal's structure.

Considering the exercise, Magnesium's and Calcium's differing atomic sizes and properties can be ideal for forming an interstitial alloy. Their crystal structure is conducive to integrating smaller atoms into this interstitial space, leading to an alloy with altered properties beneficial for specific applications.

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Most popular questions from this chapter

Nitrogen’s electronegativity value is between those of phosphorus and oxygen. Which of the following correctly describes the relationship between the three values? (A) The value for nitrogen is less than that of phosphorus because nitrogen is larger, but greater than that of oxygen because nitrogen has a greater effective nuclear charge. (B) The value for nitrogen is less than that of phosphorus because nitrogen has fewer protons, but greater than that of oxygen because nitrogen has fewer valence electrons. (C) The value for nitrogen is greater than that of phosphorus because nitrogen has fewer electrons, but less than that of oxygen because nitrogen is smaller. (D) The value for nitrogen is greater than that of phosphorus because nitrogen is smaller, but less than that of oxygen because nitrogen has a smaller effective nuclear charge.

The first ionization energy for a neutral atom of chlorine is 1.25 \(\mathrm{MJ} / \mathrm{mol}\) and the first ionization energy for a neutral atom of argon is 1.52 \(\mathrm{MJ} / \mathrm{mol}\) How would the first ionization energy value for a neutral atom of potassium compare to those values? (A) It would be greater than both because potassium carries a greater nuclear charge then either chlorine or argon. (B) It would be greater than both because the size of a potassium atom is smaller than an atom of either chlorine or argon. (C) It would be less than both because there are more electrons in potassium, meaning they repel each other more effectively and less energy is needed to remove one. (D) It would be less than both because a valence electron of potassium is farther from the nucleus than one of either chlorine or argon.

Use the following information to answer questions 25-28. A voltaic cell is created using the following half-cells: \(\begin{array}{ll}{\mathrm{Cr}^{3+}+3 e \rightarrow \mathrm{Cr}(s)} & {E^{\circ}=-0.41 \mathrm{V}} \\ {\mathrm{Pb}^{2+}+2 e \rightarrow \mathrm{Pb}(s)} & {E^{\circ}=-0.12 \mathrm{V}}\end{array}\) The concentrations of the solutions in each half-cell are 1.0 M. Which net ionic equation below represents a possible reaction that takes place when a strip of magnesium metal is oxidized by a solution of chromium (III) nitrate? (A) \(\operatorname{Mg}(s)+\operatorname{Cr}\left(\mathrm{NO}_{3}\right)_{3}(a q) \rightarrow \mathrm{Mg}^{2+}(a q)+\mathrm{Cr}^{3+}(a q)+3 \mathrm{NO}_{3}^{-}(a q)\) (B) \(3 \mathrm{Mg}(s)+2 \mathrm{Cr}^{3+} \rightarrow 3 \mathrm{Mg}^{2+}+2 \mathrm{Cr}(s)\) (C) \(\mathrm{Mg}(s)+\mathrm{Cr}^{3+} \rightarrow \mathrm{Mg}^{2+}+\mathrm{Cr}(s)\) (D) \(3 \mathrm{Mg}(s)+2 \mathrm{Cr}\left(\mathrm{NO}_{3}\right)_{3}(a q) \rightarrow 3 \mathrm{Mg}^{2+}(a q)+2 \mathrm{Cr}(s)+\mathrm{NO}_{3}^{-}(a q)\)

An atom of silicon in its ground state is subjected to a frequency of light that is high enough to cause electron ejection. An electron from which subshell of silicon would have the highest kinetic energy after ejection? (A) 1 \(\mathrm{s}\) (B) 2\(p\) (C) 3\(p\) (D) 4\(s\)

A sealed, rigid container contains three gases: 28.0 \(\mathrm{g}\) of nitrogen, 40.0 \(\mathrm{g}\) of argon, and 36.0 g of water vapor. If the total pressure exerted by the gases is \(2.0 \mathrm{atm},\) what is the partial pressure of the nitrogen? (A) 0.33 atm (B) 0.40 atm (C) 0.50 \(\mathrm{atm}\) (D) 2.0 \(\mathrm{atm}\)

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