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Which of the following pairs of elements is most likely to create an interstitial alloy? (A) Titanium and copper (B) Aluminum and lead (C) Silver and tin (D) Magnesium and calcium

Short Answer

Expert verified
The most likely pair of elements to create an interstitial alloy is (D) Magnesium and Calcium, due to the significant difference in their atomic radii.

Step by step solution

01

Understand interstitial alloys

Interstitial alloys are a type of alloy where smaller atoms fill the gaps between larger metal atoms. These alloys have different properties than their base metals, including increased hardness and strength.
02

Compare the atomic radii of the elements in option A

The atomic radius of Titanium is approximately \(147pm\) and that of Copper is \(128pm\). The difference in size is small, making it less likely for an interstitial alloy to be formed.
03

Compare the atomic radii of the elements in option B

The atomic radius of Aluminum is approximately \(143pm\) and that of Lead is \(175pm\). Although Lead has a larger atomic radius, the difference is not significant enough for an interstitial alloy to be formed.
04

Compare the atomic radii of the elements in option C

The atomic radius of Silver is approximately \(160pm\) and that of Tin is \(140pm\). The difference in size is small, making it less likely for an interstitial alloy to be formed.
05

Compare the atomic radii of the elements in option D

The atomic radius of Magnesium is approximately \(150pm\) and that of Calcium is \(197pm\). The difference in size is significant, making it possible for an interstitial alloy to be formed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Radius
The atomic radius of an element is the distance from the nucleus of an atom to the outermost boundary of its electron cloud. This measurement is crucial when considering the formation of alloys. The size of different atoms plays a significant role in determining whether an interstitial alloy can form.

For interstitial alloys, smaller atoms need to fit into the gaps between larger metal atoms, which requires a considerable size difference. When two elements have a similar atomic radius, they are less likely to form interstitial alloys because there isn't enough space for the smaller atoms to fit between the larger ones.

In the context of the problem, we observe that Magnesium and Calcium, with atomic radii of 150 pm and 197 pm respectively, have a more pronounced size difference compared to other pairs, like Silver and Tin. This greater size differential facilitates the interstitial inclusion of smaller atoms and distinguishes interstitial alloys from substitutional ones, where atomic size similarity is more favorable.
Alloy Properties
Alloys are combinations of metals that aim to improve upon the properties of the base metals. Interstitial alloys, specifically, have unique characteristics because of their structure.

When smaller atoms lodge themselves between the larger metal atoms without replacing them, they affect the physical properties of the alloy. The insertion of these small atoms in between the larger ones can lead to:
  • Increased hardness: The tight packing of atoms restricts movement, making the material harder.
  • Enhanced strength: The randomness and density of atom placement confer additional strength to the material.

In practical applications, the changes in properties make interstitial alloys valuable in industries requiring durable materials, such as construction and manufacturing tools. Understanding alloy properties helps chemists design materials with specific traits.
Metal Atoms
Metal atoms are central to the formation of all types of alloys. They are usually organized in crystalline structures that allow them to combine with other metal or non-metal atoms. When forming interstitial alloys, these metal atoms serve as the base structure into which smaller atoms can fit.

In crystalline metals, the spaces between atoms are called interstitial sites. It's these vacant spaces that smaller atoms occupy to form interstitial alloys. The choice of metal atoms is crucial since it determines how well the smaller atoms can fit and stabilize within the metal's structure.

Considering the exercise, Magnesium's and Calcium's differing atomic sizes and properties can be ideal for forming an interstitial alloy. Their crystal structure is conducive to integrating smaller atoms into this interstitial space, leading to an alloy with altered properties beneficial for specific applications.

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Most popular questions from this chapter

Directions: Questions 1-3 are long free-response questions that require about 23 minutes each to answer and are worth 10 points each. Write your response in the space provided following each question. Examples and equations may be included in your responses where appropriate. For calculations, clearly show the method used and the steps involved in arriving at your answers. You must show your work to receive credit for your answer. Pay attention to significant figures. The unbalanced reaction between potassium permanganate and acidified iron (II) sulfate is a redox reaction that proceeds as follows: $$\mathrm{H}^{+}(a q)+\mathrm{Fe}^{2+}(a q)+\mathrm{MnO}_{4}^{-(a q)} \rightarrow \mathrm{Mn}^{2+}(a q)+\mathrm{Fe}^{3+}(a q)+\mathrm{H}_{2} \mathrm{O}(l)$$ (a) Provide the equations for both half-reactions that occur below: (i) Oxidation half-reaction (ii) Reduction half-reaction (b) What is the balanced net ionic equation? A solution of 0.150 M potassium permanganate is placed in a buret before being titrated into a flask containing 50.00 mL of iron (II) sulfate solution of unknown concentration. The following data describes the colors of the various ions in solution: $$\begin{array}{|c|c|}\hline \text { Ion } & {\text { Color in solution }} \\\ \hline \mathrm{H^{+ }} & {\text { Colorless }} \\ \hline \mathrm{Fe}^{2+} & {\text { Pale Green }} \\ \hline \mathrm{MnO}_{4^{-}} & {\text {Dark Purple }} \\ \hline \mathrm{Mn}^{2+} & {\text { Colorless }} \\ \hline \mathrm{Fe}^{3+} & {\text { Yellow }} \\ \hline \mathrm{K}^{+} & {\text {Colorless }} \\ \hline \mathrm{SO}_{4}^{2-} & {\text { Colorless }} \\\ \hline\end{array}$$ (c) Describe the color of the solution in the flask at the following points: (i) Before titration begins (ii) During titration prior to the endpoint (iii) At the endpoint of the titration (d) (i) If 15.55 mL of permanganate are added to reach the endpoint, what is the initial concentration of the iron (II) sulfate? (ii) The actual concentration of the \(\mathrm{FeSO}_{4}\), is 0.250 \(M\) . Calculate the percent error. (e) Could the following errors have led to the experimental result deviating in the direction that it did? You must justify your answers quantitatively. (i) 55.0 \(\mathrm{mL}\) of \(\mathrm{FeSO}_{4}\) was added to the flask prior to titration instead of 50.0 mL . (ii) The concentration of the potassium permanganate was actually 0.160 \(M\) instead of 0.150 \(M\) .

If solutions containing equal amounts of \(\mathrm{AgNO}_{3}\) and \(\mathrm{KCl}\) are mixed, what is the identity of the spectator ions? (A) \(\mathrm{Ag}^{+}, \mathrm{NO}_{3}^{-}, \mathrm{K}^{+},\) and \(\mathrm{Cl}^{-}\) (B) \(\mathrm{Ag}^{+}\) and \(\mathrm{Cl}^{-}\) (C) \(\mathrm{K}^{+}\) and \(\mathrm{Ag}^{+}\) (D) \(\mathrm{K}^{+}\) and \(\mathrm{NO}_{3}^{-}\)

Questions 54-56 refer to the following. GRAPH CAN'T COPY Between propane and ethene, which will likely have the higher boiling point and why? (A) Propane, because it has a greater molar mass (B) Propane, because it has a more polarizable electron cloud (C) Ethene, because of the double bond (D) Ethene, because it is smaller in size

Identical amounts of the four gases listed below are present in four separate balloons. At STP, which balloon size experiences the greatest deviation from the volume calculated using the Ideal Gas Law? \(\begin{array}{ll}{\text { (A) }} & {\mathrm{H}_{2}} \\ {\text { (B) }} & {\mathrm{O}_{2}} \\ {\text { (C) }} & {\mathrm{N}_{2}} \\ {\text { (D) }} & {\mathrm{F}_{2}}\end{array}\)

An electron from which peak would have the greatest velocity after ejection? (A) The peak at 104 \(\mathrm{MJ} / \mathrm{mol}\) (B) The peak at 6.84 \(\mathrm{MJ} / \mathrm{mol}\) (C) The peak at 4.98 \(\mathrm{MJ} / \mathrm{mol}\) (D) The peak at 1.76 \(\mathrm{MJ} / \mathrm{mol}\)

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