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\(\mathrm{H}_{2}(g)+\mathrm{F}_{2}(g) \rightarrow 2 \mathrm{HF}(g)\) Gaseous hydrogen and fluorine combine in the reaction above to form hydrogen fluride with an enthalpy change of \(-540 \mathrm{kJ}\) . What is the value of the heat of formation of \(\mathrm{HF}(g) ?\) (A) \(-1,080 \mathrm{kJ} / \mathrm{mol}\) (B) \(-270 \mathrm{kJ} / \mathrm{mol}\) (C) 270 \(\mathrm{kJ} / \mathrm{mol}\) (D) 540 \(\mathrm{kJ} / \mathrm{mol}\)

Short Answer

Expert verified
The heat of formation for HF(g) is -270 kJ/mol, so the correct answer is (B) -270 kJ/mole.

Step by step solution

01

Determine the reaction stoichiometry

The reaction shows that 1 mole of H2(g) reacts with 1 mole of F2(g) to produce 2 moles of HF(g). Therefore, the amount of energy (-540 kJ) associated with this reaction is for the formation of 2 moles of HF(g).
02

Calculate the heat of formation for one mole of HF

The heat of formation is the energy associated with forming one mole of a substance. Since the given reaction forms 2 moles of HF(g), we divide the total energy by 2 to find the heat of formation for one mole of HF(g). Doing this gives us -540 kJ / 2 = -270 kJ/mole.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry is a fascinating area of chemistry that involves understanding the quantitative relationships in chemical reactions. It allows us to predict the amounts of substances consumed and produced in a reaction. In the context of our exercise, stoichiometry helps us determine that one mole of hydrogen gas (\( \mathrm{H}_2 \) ) combines with one mole of fluorine gas (\( \mathrm{F}_2 \) ) to produce two moles of hydrogen fluoride (\( \mathrm{HF} \) ). This stoichiometric relationship is vital because it provides the framework for calculating the enthalpy change for reactions.
Understanding stoichiometry needs attention to three key points:
  • Identify and use mole ratios from balanced chemical equations.
  • Understand that coefficients in a chemical equation represent moles, which are the base unit for stoichiometric calculations.
  • Use mole ratios to transition between moles of different reactants and products.
By mastering stoichiometry, one can seamlessly navigate various parts of a chemical reaction, including determining how much of each substance you'll need or produce.
Heat of Formation
The heat of formation is an important thermodynamic concept. It refers to the energy change when one mole of a compound is formed from its elements under standard state conditions. In simpler terms, it tells us how much energy is absorbed or released when a particular compound is made.
In the exercise provided, the heat of formation is calculated for hydrogen fluoride (\( \mathrm{HF} \) ). Essentially, the given reaction produces 2 moles of \( \mathrm{HF} \) with an enthalpy change of \(-540 \text{kJ}\). To find the heat of formation per mole of \( \mathrm{HF} \) , the total energy change is divided by the number of moles: \(-540 \text{kJ} / 2 = -270 \text{kJ/mol}\).
Key takeaways about the heat of formation include:
  • It is a specific type of enthalpy change for forming a compound from elements.
  • Units are typically expressed in \(\text{kJ/mol}\).
  • Negative values show exothermic reactions, indicating energy release during formation.
Recognizing how to calculate and interpret the heat of formation is essential for predicting the energy profiles of chemical reactions.
Moles of Substance
The concept of moles is fundamental in chemistry, serving as the bridge between the microscale behavior of molecules and macroscale measurements we can see and measure. A mole represents \(6.022 \times 10^{23}\) entities, often atoms or molecules, allowing us to express massive numbers found in chemical reactions in manageable terms.
Within the given problem, calculating the moles of a substance—whether a reactant or product—gave insight into the enthalpy change for specific reactions. For instance, knowing the reaction produced 2 moles of \( \mathrm{HF} \) was pivotal in determining the per-mole energy change.
Key points about moles of substance:
  • A mole is a counting unit like a dozen but for tiny particles.
  • Moles help convert between grams of a substance and atoms or molecules.
  • Stoichiometry employs mole ratios to relate amounts of reactants and products.
Understanding how to use and calculate moles brings precision to chemistry, making sense of chemical formulas, equations, and reaction magnitudes.

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Most popular questions from this chapter

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