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A multi-step reaction takes place with the following elementary steps: \(\begin{array}{ll}{\text { Step I. }} & {A+B=C} \\ {\text { Step II. }} & {C+A \rightarrow D} \\ {\text { Step III. }} & {C+D \rightarrow B+E}\end{array}\) What is the overall balanced equation for this reaction? (A) 2A + B + 2C + D ? C + D + B + E (B) A + B ? B + E (C) A + 2C ? D + E (D) 2A + C ? E

Short Answer

Expert verified
The overall balanced equation for the reaction, after canceling out intermediates, is 2A + B ? B + E. Therefore, the correct answer is not provided in the given options.

Step by step solution

01

List and Categorize Reagents

Start by listing all reagents and products involved in the separate reactions, distinguishing which are reactants, intermediates, and products. Here, A and B are the initial reactants, C is a product and then a reactant, making it an intermediate, D also is an intermediate and E is final product. You have not been asked to balance the individual reactions, but the overall equation.
02

Form Overall Reaction

Next, gather all reactants and products from the initial reactants and final products list to form a theoretical overall reaction. Based on the individual reactions, the first theoretical reaction will be 2A + B + 2C + D ? C + D + B + E. This entails all the molecules in the reaction.
03

Cancel Out Intermediates

Now cancel out intermediates from both sides of the equation. Intermediates are those substances that are produced and then consumed in the reaction. From the formed equation, intermediates are C and D. After intermediates cancellation, the resultant equation becomes: 2A + B ? B + E

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Elementary Steps
Elementary steps are the foundation of understanding complex chemical reactions. Think of them as individual reactions that happen as part of a larger process in a multi-step reaction. Each step represents a fundamental action: breaking or forming bonds, rearranging atoms, or transferring electrons. In our given multi-step reaction, we see a sequence of three elementary steps. Each one shows how the molecules interact to form new substances:
  • Step I: Chemical species A and B react to form C.
  • Step II: C then reacts with another A to produce D.
  • Step III: Finally, C and D form B and E.
Understanding elementary steps helps us track the transformation at each stage before they combine into an overall balanced reaction. They reveal the intimate details about which molecules come together and the conditions they require to proceed to the next part of the overall reaction. This builds a comprehensive picture of complex reactions taking place over multiple stages.
Reaction Intermediates
Reaction intermediates are temporary substances that are formed and consumed during multi-step reactions. They play crucial roles in transitioning from one step to the next. In our featured reaction, C and D function as such intermediates. They both are formed in one step and used up in subsequent step(s), meaning they do not appear in the final overall balanced equation.
  • C is formed in Step I and consumed in Steps II and III.
  • D is created in Step II and consumed in Step III.
Because intermediates are only present briefly, they are not shown in the overall reaction. Their role, however, is significant in ensuring the reaction progresses and that all necessary transformations occur. This highlights their importance while ensuring clarity by excluding them from the final equation. Recognizing intermediates is essential to understanding the depth of multi-step reactions.
Overall Balanced Equation
The ultimate aim in analyzing chemical reactions is to derive the overall balanced equation. This represents the net transformation from reactants to products, excluding any intermediates that might have appeared and disappeared along the way. The balance ensures that we adhere to the law of conservation of mass; meaning the number of each type of atom entering the reaction equals the number exiting.
When we look at our multi-step reaction and apply these principles, we identify the true input and output:
  • Initial reactants: 2A and B (as given in the original equation process).
  • Final product: B and E (as intermediates C and D cancel out).
The overall balanced equation becomes simply: 2A + B = E. Notice that B appears on both sides, indicating it is regenerated; thus, the simplest equation reads A + E on the product side. This elegant solution showcases the beautiful simplicity nestled in complex processes, all thanks to thorough cancellation and balance.

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Most popular questions from this chapter

Use the following information to answer questions 14-16 The radius of atoms and ions is typically measured in Angstroms \((A),\) which is equivalent to \(1 * 10^{-10} \mathrm{m} .\) Below is a table of information for three different elements. TABLE NOT AVAILABLE The phosphorus ion is larger than a neutral phosphorus atom, yet a zinc ion is smaller than a neutral zinc atom. Which of the following statements best explains why? (A) The zinc atom has more protons than the phosphorus atom. (B) The phosphorus atom is paramagnetic, but the zinc atom is diamagnetic. (C) Phosphorus gains electrons when forming an ion, but zinc loses them. (D) The valence electrons in zinc are further from the nucleus than those in phosphorus.

Silver sulfate, \(\mathrm{Ag}_{2} \mathrm{SO}_{4}\) , has a solubility product constant of \(1.0 \times 10^{-5} .\) The below diagram shows the products of a precipitation reaction in which some silver sulfate was formed. (Diagram Can't Copy) Which ion concentrations below would have led the precipitate to form? (A) \(\left[\mathrm{Ag}^{+}\right]=0.01 M\left[\mathrm{SO}_{4}^{2-}\right]=0.01 M\) (B) \(\left[\mathrm{Ag}^{+}\right]=0.10 M\left[\mathrm{SO}_{4}^{2-}\right]=0.01 M\) (C) \(\left[\mathrm{Ag}^{+}\right]=0.01 M\left[\mathrm{SO}_{4}^{2-}\right]=0.10 M\) (D) This is impossible to determine without knowing the total volume of the solution.

Which compound, \(\mathrm{CaCl}_{2}\) or \(\mathrm{CaO}\) , would you expect to have a high melting point? Why? (A) \(\mathrm{CaCl}_{2}\) because there are more ions per lattice unit (B) \(\mathrm{CaCl}_{2}\) because a chlorine ion is smaller than an oxygen ion (C) Cao, because the charge of oxygen ion exceeds that of chlorine ion (D) CaO, because the common charges of calcium and oxygen ions are identical in magnitude

$$4 \mathrm{NH}_{3}(g)+5 \mathrm{O}_{2}(g) \rightarrow 4 \mathrm{NO}(g)+6 \mathrm{H}_{2} \mathrm{O}(g)$$ The above reaction will experience a rate increase by the addition of a catalyst such as platinum. Which of the following best explains why? (A) The catalyst causes the value for \(\Delta G\) to become more negative. (B) The catalyst increases the percentage of collisions that occur at the proper orientation in the reactant molecules. (C) The catalyst introduces a new reaction mechanism for the reaction. (D) The catalyst increases the activation energy for the reaction.

\(\mathrm{CaCO}_{3}(s)+2 \mathrm{H}^{+}(a q) \rightarrow \mathrm{Ca}^{2+}(a q)+\mathrm{H}_{2} \mathrm{O}(l)+\mathrm{CO}_{2}(g)\) If the reaction above took place at standard temperature and pressure and 150 grams of \(\mathrm{CaCO}_{3}(\mathrm{s})\) were consumed, what was the volume of \(\mathrm{CO}_{2}(g)\) produced at STP? (A) 11 L (B) 22 L (C) 34 L (D) 45 L

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