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Calculate the density of toluene vapor (molar mass \(92 \mathrm{g} /\) mol) at 1.00 atm pressure and \(227.0^{\circ} \mathrm{C}\).

Short Answer

Expert verified
The density of toluene vapor at 1.00 atm pressure and 227.0掳C is approximately \(2.239 \frac{g}{L}\).

Step by step solution

01

Write down the given information

Before starting, let's write down the given information: Molar mass of toluene (M) = \(92 \frac{g}{mol}\), Pressure (P) = \(1.00 \ atm\), Temperature (T) = \(227.0^{\circ}C\). We're required to find the density (蟻) of toluene vapor.
02

Convert the temperature from Celsius to Kelvin

To apply the Ideal Gas Law, we need temperature in Kelvin. Convert the given temperature from Celsius to Kelvin using the following formula: \(T_{K} = T^{\circ}C + 273.15\) \(T_{K} = 227.0 + 273.15\) \(T_{K} = 500.15 \ K\)
03

Use the Ideal Gas Law and find the volume

The Ideal Gas Law is: \(PV = nRT\) Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (\(0.0821 \frac{L \cdot atm}{mol \cdot K}\)), and T is the temperature in Kelvin. First, let's solve for the volume per mole of toluene (V/n): \(\frac{V}{n} = \frac{RT}{P}\) Substitute the known values: \(\frac{V}{n} = \frac{0.0821 \frac{L \cdot atm}{mol \cdot K} \cdot 500.15 \ K}{1.00 \ atm}\) \(\frac{V}{n} = 41.06155 \frac{L}{mol}\)
04

Calculate the mass of 1 mole of toluene

The mass of 1 mole of toluene (m) can be found using the given molar mass: \(m = n \times M\) \(m = 1 \ mol \times 92 \frac{g}{mol}\) \(m = 92 \ g\)
05

Calculate the density

Finally, we can determine the density of toluene vapor by dividing the mass of 1 mole of toluene by the volume per mole: \(density (\rho) = \frac{m}{\frac{V}{n}}\) \(\rho = \frac{92 \ g}{41.06155 \frac{L}{mol}}\) \(\rho = 2.239 \frac{g}{L}\) The density of toluene vapor at 1.00 atm pressure and 227.0掳C is approximately \(2.239 \frac{g}{L}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The Ideal Gas Law is an equation that allows us to describe the behavior of ideal gases. It is represented by the formula:

\[\[\begin{align*}\(PV = nRT\)
\end{align*}\]\]

where \(P\) signifies the pressure of the gas, \(V\) denotes the volume it occupies, \(n\) represents the number of moles of gas, \(R\) is the universal gas constant, and \(T\) is the absolute temperature in Kelvin. In the context of density calculations, the Ideal Gas Law helps us find the volume occupied by a gas under specified conditions, which is integral to determining the gas density.
For our exercise involving toluene vapor, we use this law to calculate the volume per mole, which serves as a foundational step in finding the gas density. Understanding each element of the equation and its units is crucial for properly applying the Ideal Gas Law to real-world problems.
Molar Mass
Molar mass is a fundamental concept in chemistry, referring to the mass of one mole of a substance, measured in grams per mole (\(g/mol\)). It is significant because it serves as a bridge between the microscopic particles in atoms and molecules and the measurable quantities we can observe.
To calculate the density of a gas, knowing the molar mass allows us to determine the mass of a given number of moles. For instance, in our problem, the molar mass of toluene is an essential element of the calculation. With the molar mass of \(92 \frac{g}{mol}\) and the ideal gas law, one can calculate the mass of toluene involved in the reaction, which is integral for finding the gas density.
Temperature Conversion
Temperature conversion is a critical step in many chemistry calculations, particularly those involving gas laws. The Ideal Gas Law requires the use of absolute temperature, meaning temperatures must be expressed in Kelvin (K) rather than Celsius (掳C) or Fahrenheit (掳F).
To convert from Celsius to Kelvin, the formula used is:
\[\[\begin{align*}\(T_K = T_掳C + 273.15\)
\end{align*}\]\]
The addition of 273.15 to the Celsius temperature accounts for the difference in starting points: 0掳C is equivalent to 273.15K. In our exercise, the given temperature of toluene vapor at \(227.0^掳C\) converts to \(500.15 K\). Properly converting temperature ensures accurate calculations when applying the Ideal Gas Law.
Gas Density
Gas density is the mass of a gas divided by its volume, typically expressed in grams per liter (\(g/L\)). To find the density of a gas using the Ideal Gas Law, you can rearrange the formula to solve for the volume occupied by a known mass of gas.
This is how we approached our toluene vapor problem, determining the volume per mole using the Ideal Gas Law and then calculating the density by dividing the mass of one mole of toluene by that volume. The result gives us the gas density, which in our case was \(2.239 \frac{g}{L}\). Understanding gas density is key in many applications, including material science, environmental monitoring, and industrial processes, as it affects how gases behave under different conditions.

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