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The specific heat of solid copper is \(0.385 \mathrm{J} / \mathrm{g} \cdot^{\circ} \mathrm{C}\) ). What thermal energy change occurs when a \(35.3 \mathrm{g}\) sample of copper is cooled from \(35.0^{\circ} \mathrm{C}\) to \(15.0^{\circ} \mathrm{C} ?\) Be sure to give your answer the proper sign. This amount of energy is used to melt solid ice at \(0.0^{\circ} \mathrm{C} .\) The molar enthalpy of fusion of ice is \(6.01 \mathrm{kJ} / \mathrm{mol} .\) How many moles of ice are melted?

Short Answer

Expert verified
Answer: 0.04514 mol of ice are melted.

Step by step solution

01

Identify the given variables and the formula

Given: Specific heat of solid copper: \(0.385 \mathrm{J/g \cdot ^\circ C}\) Mass of copper: \(35.3 \mathrm{g}\) Initial temperature: \(35.0^{\circ} \mathrm{C}\) Final temperature: \(15.0^{\circ} \mathrm{C}\) We need to calculate the thermal energy change, which can be found using the formula: \( q = m \times c \times \Delta T \) where \(q\) is the heat transfer, \(m\) is the mass, \(c\) is the specific heat, and \(\Delta T\) is the change in temperature.
02

Calculate the change in temperature

To calculate the change in temperature, subtract the initial temperature from the final temperature: \(\Delta T = T_{final} - T_{initial} = 15.0^{\circ} \mathrm{C} - 35.0^{\circ} \mathrm{C} = -20.0^{\circ} \mathrm{C}\)
03

Calculate the heat transfer

Now, plug in the given values into the heat transfer formula: \(q = m \times c \times \Delta T = 35.3\, \mathrm{g} \times 0.385\, \mathrm{J/g\cdot ^\circ C} \times -20.0\, ^{\circ} \mathrm{C} = -271.37\, \mathrm{J}\) The negative sign indicates that the heat was released from the copper while cooling. Thus, the thermal energy change when the copper is cooled is \(-271.37\ \mathrm{J}\).
04

Use the molar enthalpy of fusion to find the moles of ice melted

Given: Molar enthalpy of fusion for ice: \(6.01 \mathrm{kJ/mol}\) First, convert \(-271.37\, \mathrm{J}\) to kJ: \(-271.37\, \mathrm{J} = -0.27137\, \mathrm{kJ}\) Now, we can use the formula for heat transfer in phase change: \(q = n \times \Delta H\) Where \(n\) is the number of moles of ice, and \(\Delta H\) is the molar enthalpy of fusion. Rearrange the formula to find the number of moles: \(n = \frac{q}{\Delta H} = \frac{-0.27137\, \mathrm{kJ}}{6.01\ \mathrm{kJ/mol}} = -0.04514\ \mathrm{mol}\) The negative sign indicates that heat is being released. Therefore, \(0.04514\ \mathrm{mol}\) of ice are melted by the energy released when the copper is cooled.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Specific Heat
Specific heat is a term used to describe the amount of heat required to change the temperature of a given amount of a substance. In chemistry and physics, specific heat is crucial because it helps us understand how different materials react to heat. The specific heat of a material is defined as the amount of heat per unit mass required to raise the temperature by one degree Celsius.

For instance, in our example, the specific heat of copper is given as \(0.385 \mathrm{J/g \, ^\circ C}\). This means that it takes 0.385 joules of thermal energy to raise the temperature of 1 gram of copper by 1 degree Celsius. Knowing the specific heat allows us to calculate the amount of energy exchanged during temperature changes.
Thermal Energy Change
Thermal energy change is a concept closely related to specific heat. It measures the total energy change when a substance is heated or cooled. In the example problem, the copper undergoes cooling, which results in a negative thermal energy change.

The formula to calculate thermal energy change is:
  • \( q = m \times c \times \Delta T \)
Here, \(q\) is the heat transfer (thermal energy change), \(m\) is the mass, \(c\) is the specific heat, and \(\Delta T\) is the change in temperature.

In the exercise, copper cools from \(35.0^{\circ}\mathrm{C}\) to \(15.0^{\circ}\mathrm{C}\), with a change in temperature (\(\Delta T\)) of \(-20.0^{\circ}\mathrm{C}\). By plugging these numbers into the formula, we get a thermal energy change of \(-271.37\, \mathrm{J}\), indicating the heat released during cooling.
Molar Enthalpy of Fusion
The molar enthalpy of fusion refers to the amount of energy required to change a mole of a solid to a liquid at a constant temperature, which is also known as the melting point. This property is crucial for phase change calculations.

In the exercise, the molar enthalpy of fusion for ice is provided as \(6.01 \mathrm{kJ/mol}\). This means \(6.01\) kilojoules of energy are needed to melt one mole of ice. The example problem uses the thermal energy change resulting from cooling copper to calculate how much ice can be melted with that absorbed energy.
Phase Change Calculation
Phase change calculations involve determining the amount of substance that changes state due to heat transfer. In our example, the energy released when copper cools is used to melt ice.

To find the number of moles of ice melted, we use:
  • \( q = n \times \Delta H \)
Where \(n\) is the number of moles, and \(\Delta H\) is the molar enthalpy of fusion. After converting the released energy to kilojoules (\(-0.27137 \mathrm{kJ}\)), we use the enthalpy of fusion of ice to find the number of moles.

Rearranging gives:
  • \( n = \frac{q}{\Delta H} = \frac{-0.27137 \mathrm{kJ}}{6.01 \mathrm{kJ/mol}} = -0.04514 \mathrm{mol} \)
The negative sign here reaffirms that the energy released cools the metal, resulting in \(0.04514 \mathrm{mol}\) of ice melting.

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Most popular questions from this chapter

Calculate the standard enthalpy of formation of \(\mathrm{SO}_{2}(g)\) from the standard enthalpy changes of the following reactions: $$\begin{aligned} 2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \rightarrow 2 \mathrm{SO}_{3}(g) & & \Delta H_{\mathrm{rxn}}^{\circ}=-196 \mathrm{kJ} \\ \frac{1}{4} \mathrm{S}_{8}(s)+3 \mathrm{O}_{2}(g) \rightarrow 2 \mathrm{SO}_{3}(g) & & \Delta H_{\operatorname{man}}^{\circ}=-790 \mathrm{kJ} \\\ \frac{1}{8} \mathrm{S}_{8}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{SO}_{2}(g) & \Delta H_{5}^{\circ} &=? \end{aligned}$$

Use the following standard heats of formation to calculate the molar enthalpy of vaporization of liquid hydrogen peroxide: \(\Delta H_{\mathrm{f}}^{\circ}\) of \(\mathrm{H}_{2} \mathrm{O}_{2}(\ell)\) is \(-188 \mathrm{kJ} / / \mathrm{mol}\) and \(\Delta H_{\mathrm{f}}^{\circ}\) of \(\mathrm{H}_{2} \mathrm{O}_{2}(g)\) is \(-136 \mathrm{kJ} / \mathrm{mol}\)

Acetylene, \(\mathrm{C}_{2} \mathrm{H}_{2}\left(\Delta H_{\mathrm{f}}^{\circ}=226.7 \mathrm{kJ} / \mathrm{mol}\right),\) and benzene, \(\mathrm{C}_{6} \mathrm{H}_{6}\left(\Delta H_{\mathrm{f}}^{\circ}=49.0 \mathrm{kJ} / \mathrm{mol}\right),\) are sometimes referred to as endothermic compounds. a. Why are \(\mathrm{C}_{2} \mathrm{H}_{2}\) and \(\mathrm{C}_{6} \mathrm{H}_{6}\) called endothermic compounds? b. Calculate the standard molar enthalpy of combustion of acetylene and benzene.

If we replace the water in a bomb calorimeter with another liquid, why do we need to redetermine the heat capacity of the calorimeter?

Automobile air bags produce nitrogen gas from the reaction: $$2 \mathrm{NaN}_{3}(s) \rightarrow 2 \mathrm{Na}(s)+3 \mathrm{N}_{2}(g)$$ a. If \(2.25 \mathrm{g}\) of \(\mathrm{NaN}_{3}\) reacts to fill an air bag, how much \(P-V\) work will the \(\mathrm{N}_{2}\) do against an external pressure of 1.00 atm given that the density of nitrogen is \(1.165 \mathrm{g} / \mathrm{L}\) at \(20^{\circ} \mathrm{C} ?\) b. If the process releases \(2.34 \mathrm{kJ}\) of heat, what is \(\Delta E\) for the system?

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