/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 The reaction of \(\mathrm{SnCl}_... [FREE SOLUTION] | 91Ó°ÊÓ

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The reaction of \(\mathrm{SnCl}_{2}(a q)\) with \(\mathrm{Pt}^{4+}(a q)\) in aqueous \(\mathrm{HCl}\) yields a yellow-orange solution of a 1: 1 Pt-Sn compound with a molar absorptivity \((\varepsilon)\) of \(1.3 \times 10^{4} M^{-1} \mathrm{cm}^{-1} .\) What is the absorbance in a cell with a path length of \(1.00 \mathrm{cm}\) of a solution prepared by adding \(100 \mathrm{mL}\) of an aqueous solution of \(5.2 \mathrm{mg}\left(\mathrm{NH}_{4}\right)_{2} \mathrm{PtCl}_{6}\) to \(100 \mathrm{mL}\) of an aqueous solution of \(2.2 \mathrm{mg} \mathrm{SnCl}_{2} ?\)

Short Answer

Expert verified
Answer: The absorbance in a cell with a path length of 1.00 cm is 0.754.

Step by step solution

01

Calculate the moles of (NH4)2PtCl6 and SnCl2

First, we need to find the moles of (NH4)2PtCl6 and SnCl2 present in their respective solutions: - Convert the mass of (NH4)2PtCl6 into moles using its molar mass: \([(\mathrm{NH}_{4})_{2} \mathrm{PtCl}_{6}] = \frac{5.2\,\mathrm{mg}}{443.86\,\mathrm{g/mol}} \times \frac{1\,\mathrm{g}}{1000\,\mathrm{mg}} = 1.17 \times 10^{-5}\,\mathrm{mol}\) - Convert the mass of SnCl2 into moles using its molar mass: \(\mathrm{[SnCl}_{2}] = \frac{2.2\,\mathrm{mg}}{189.61\,\mathrm{g/mol}} \times \frac{1\,\mathrm{g}}{1000\,\mathrm{mg}} = 1.16 \times 10^{-5}\,\mathrm{mol}\) #Step 2: Calculate the initial concentrations of Pt4+ and Sn2+ ions#
02

Calculate the initial concentrations of Pt4+ and Sn2+ ions

Now, we need to find the initial concentrations of Pt4+ and Sn2+ ions in the mixed solution: - For Pt4+ ions, divide the moles of (NH4)2PtCl6 by the total volume of the mixed solution (200 mL) and convert to molarity: \(\mathrm{[Pt^{4+}]} = \frac{1.17 \times 10^{-5}\,\mathrm{mol}}{0.2\,\mathrm{L}} = 5.85 \times 10^{-5}\,\mathrm{M}\) - For Sn2+ ions, divide the moles of SnCl2 by the total volume of the mixed solution (200 mL) and convert to molarity: \(\mathrm{[Sn^{2+}]} = \frac{1.16 \times 10^{-5}\,\mathrm{mol}}{0.2\,\mathrm{L}} = 5.80 \times 10^{-5}\,\mathrm{M}\) #Step 3: Calculate the final concentration of the Pt-Sn compound#
03

Calculate the final concentration of the Pt-Sn compound

Since the reaction stoichiometry is 1:1, the minimum concentration of the two ions will react completely. In this case, the minimum concentration is the Sn2+ ions: \(\mathrm{[Pt-Sn]} = 5.80 \times 10^{-5}\,\mathrm{M}\) #Step 4: Calculate the absorbance using the Beer-Lambert law#
04

Calculate the absorbance using the Beer-Lambert law

Now we can use the Beer-Lambert law, A = ε * c * l, to find the absorbance: \(A = (1.3 \times 10^{4}\,\mathrm{M}^{-1}\mathrm{cm}^{-1} )\times (5.80 \times 10^{-5}\,\mathrm{M} )\times (1.00\,\mathrm{cm}) = 0.754\) The absorbance in a cell with a path length of 1.00 cm is 0.754.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Absorptivity
Molar absorptivity, represented by the Greek letter \( \varepsilon \), is a measure of how well a chemical species absorbs light at a particular wavelength. Imagine it as a factor that tells us how much light a solution will absorb, considering its concentration and the length of the path the light travels through it. This concept is essential in spectrophotometry because it links the absorption of light to the concentration of the absorbing species in solution.

When talking bout molar absorptivity, it's key to remember that units matter. It's typically expressed in units of \( M^{-1} cm^{-1} \), where \( M \) stands for molarity, or moles per liter, and \( cm \) indicates the path length of the cell containing the solution. In the sample exercise provided, the molar absorptivity of the Pt-Sn compound is \( 1.3 \times 10^{4} M^{-1} cm^{-1} \). This high value suggests that even a low concentration of the compound would result in significant light absorption, making it ideal for spectrophotometric analysis.
Chemical Stoichiometry
Chemical stoichiometry involves the relationship between the amounts of reactants and products in a chemical reaction. It's the big 'recipe' of chemistry. Just like following a recipe to make a cake, you need the right amounts of ingredients for the perfect outcome. Stoichiometry tells us how much of each substance is needed to react completely without any leftovers.

In the exercise, stoichiometry assumes a perfect 1:1 ratio between \( \mathrm{SnCl}_{2} \) and \( \mathrm{Pt}^{4+} \) ions, which simply means one ion of \( \mathrm{Sn}^{2+} \) will react with one ion of \( \mathrm{Pt}^{4+} \) to form the product. Understanding this 1:1 relationship is crucial to determining the final concentration of the compound in solution, as we assume all the limiting reactant will be used up to make the product.
Solution Concentration
Solution concentration, most commonly expressed in molarity \( (M) \), refers to the amount of solute present in a given volume of solution. It's like figuring out how strong your coffee is by knowing how many scoops of coffee grounds you've added to the water. In chemistry, it's a bit more precise — we calculate molarity by dividing the number of moles of solute by the volume of the solution in liters.

In our example, following the stoichiometry steps, we calculate the initial molarity of the \( \mathrm{Pt}^{4+} \) and \( \mathrm{Sn}^{2+} \) ions and then determine the molarity of the resulting Pt-Sn compound, which is crucial for using the Beer-Lambert law. Understanding how to accurately calculate solution concentration is a fundamental skill in chemistry that applies to preparing solutions, analyzing reaction yields, and conducting titrations.
Spectrophotometry
Spectrophotometry is a technique that measures how much light a chemical substance absorbs by passing light through a solution. Think of it like sunglasses for chemicals – it tells us how much light the 'sunglasses' can block or absorb. This tool is invaluable in the chemistry lab for figuring out the concentration of substances in a solution.

By shining a light of a specific wavelength through a solution and measuring the intensity of light that passes through, we can use the Beer-Lambert law to relate the absorption to the concentration of the solution. The absorbance measured can be directly related to concentration if the path length and molar absorptivity are known. In the exercise we're discussing, spectrophotometry would be the method used to measure the absorbance of the yellow-orange solution, leading us to determine the concentration of the Pt-Sn compound formed from the reaction.

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