Some indoor air-purification systems work by converting a little of the oxygen
in the air to ozone, which oxidizes mold and mildew spores and other
biological air pollutants. The chemical equation for the ozone generation
reaction is,$$3 \mathrm{O}_{2}(g) \rightarrow 2 \mathrm{O}_{3}(g)$$.It is
claimed that one such system generates \(4.0 \mathrm{g}\) of \(\mathrm{O}_{3}\)
per hour from dry air passing through the purifier at a flow of \(5.0
\mathrm{L} / \mathrm{min.}\) If 1 liter of indoor air contains \(0.28
\mathrm{g}\) of \(\mathrm{O}_{2}\).
a. what fraction of the molecules of \(\mathrm{O}_{2}\) is converted to
\(\mathrm{O}_{3}\) by the air purifier?
b. what is the percent yield of the ozone generation reaction?