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A reaction vessel for synthesizing ammonia by reacting nitrogen and hydrogen is charged with \(6.04 \mathrm{kg}\) of \(\mathrm{H}_{2}\) and excess \(\mathrm{N}_{2} .\) A total of \(28.0 \mathrm{kg}\) of \(\mathrm{NH}_{3}\) is produced. What is the percent yield of the reaction?

Short Answer

Expert verified
Answer: The percent yield of the reaction is approximately 82.34%.

Step by step solution

01

Write the balanced chemical equation.

The balanced chemical equation for the synthesis of ammonia is: $$ \mathrm{N}_{2} + 3\mathrm{H}_{2} \rightarrow 2\mathrm{NH}_{3} $$
02

Convert the initial amount of hydrogen gas to moles.

Given that the initial amount of hydrogen gas is \(6.04 \mathrm{kg}\), first we will convert it to grams and then moles using the molar mass of \(\mathrm{H}_{2}\) (\(2.016 \mathrm{g/mol}\)). $$ \text{moles of }\mathrm{H}_{2} = \frac{6.04 \cdot 1000 \mathrm{g}}{2.016 \mathrm{g/mol}} = 2996.04 \mathrm{mol} $$
03

Calculate the theoretical amount of ammonia produced.

Using the balanced chemical equation, we can calculate the theoretical amount of ammonia produced from the given amount of hydrogen gas. For every \(3\) moles of \(\mathrm{H}_{2}\), \(2\) moles of \(\mathrm{NH}_{3}\) will be formed. $$ \text{theoretical moles of }\mathrm{NH}_{3} = \frac{2}{3} \times 2996.04 \mathrm{mol} = 1997.36 \mathrm{mol} $$
04

Convert the theoretical amount of ammonia to mass.

Using the molar mass of \(\mathrm{NH}_{3}\) (\(17.031 \mathrm{g/mol}\)), we can convert the theoretical amount of ammonia produced from moles to mass. $$ \text{theoretical mass of }\mathrm{NH}_{3} = 1997.36 \mathrm{mol} \times 17.031 \mathrm{g/mol} = 34,015.07 \mathrm{g} = 34.015 \mathrm{kg} $$
05

Calculate the percent yield of the reaction.

Finally, we will calculate the percent yield using the actual mass of ammonia produced (\(28.0 \mathrm{kg}\)) and the theoretical mass of ammonia. $$ \text{percent yield} = \frac{\text{actual yield}}{\text{theoretical yield}} \times 100\% = \frac{28.0 \mathrm{kg}}{34.015 \mathrm{kg}} \times 100\% \approx 82.34\% $$ Thus, the percent yield of the reaction is approximately \(82.34\%\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Balanced Chemical Equation
Understanding balanced chemical equations is crucial for analyzing and predicting the outcomes of chemical reactions. A balanced chemical equation has the same number of atoms of each element on both sides, ensuring that mass is conserved according to the Law of Conservation of Mass.
In the given problem, the chemical reaction involved is the synthesis of ammonia (\(\text{NH}_3\)) from nitrogen (\(\text{N}_2\)) and hydrogen (\(\text{H}_2\)). The balanced equation for this reaction is:

  • \(\text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3\)

This equation tells us that one molecule of nitrogen reacts with three molecules of hydrogen to produce two molecules of ammonia. By counting and matching the number of atoms for each element (N and H) on both sides, we can confirm that the equation is balanced.
Molar Mass
Molar mass is the mass of one mole of a given substance. It allows us to convert between the mass of a substance and the number of moles, which are the units typically used in chemical equations and stoichiometry.
To find the molar mass, we add the atomic masses of all the atoms in a molecule. For example, the molar mass of hydrogen gas (\(\text{H}_2\)) is calculated by adding the atomic mass of two hydrogen atoms:

  • \(\text{Molar mass of } \text{H}_2 = 2.016 \text{ g/mol}\)

Similarly, for ammonia (\(\text{NH}_3\)), the molar mass is:

  • \(\text{Molar mass of } \text{NH}_3 = 17.031 \text{ g/mol}\)

These values are essential in converting mass to moles and vice versa, which is a fundamental step in calculating theoretical yields in chemical reactions.
Stoichiometry
Stoichiometry is the study of the quantitative relationships in chemical reactions, based on the balanced equation. It allows us to predict how much of each reactant is needed and how much product will be formed.
For our problem, stoichiometry helps us calculate the theoretical yield of ammonia from a given amount of hydrogen. Using the balanced equation:

  • 3 moles of \(\text{H}_2\) produce 2 moles of \(\text{NH}_3\)

We use the stoichiometric ratio to find how many moles of ammonia can be produced from the moles of hydrogen available. This theoretical yield is indispensable when calculating the percent yield of a reaction, comparing the actual outcome to ideal conditions.
Chemical Reactions
Chemical reactions involve the transformation of reactants into products, often releasing or absorbing energy. Tracking these transformations requires an understanding of both the physical and quantitative aspects of reactants and products.
In the example of ammonia synthesis, nitrogen and hydrogen gases react to form a new compound, ammonia. This process is a combination reaction, where multiple reactants come together to form a single product.
By analyzing chemical reactions, we are able to predict and control chemical processes in real-world applications, such as manufacturing fertilizers, which involve synthesizing ammonia in large quantities.
Mastering the concepts of balanced equations, molar mass, and stoichiometry empowers students to delve deeper into the intricate world of chemical reactions.

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