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How much energy is required to remove a neutron from the nucleus of an atom of carbon- 13 (mass \(=13.00335\) amu)? (Hint: The mass of an atom of carbon-12 is exactly \(12.00000 \text { amu. })\)

Short Answer

Expert verified
Answer: The energy required to remove a neutron from the nucleus of a carbon-13 atom is approximately 1.501 脳 10鈦宦光伆 Joules.

Step by step solution

01

Determine the mass difference between carbon-13 and carbon-12 atoms

In order to find the energy required to remove a neutron from carbon-13, first find the mass difference between a carbon-13 atom (mass = 13.00335 amu) and a carbon-12 atom (mass = 12.00000 amu). The mass difference will give the mass of a neutron. The mass difference can be found by subtracting the mass of a carbon-12 atom from a carbon-13 atom. Mass difference = Mass of carbon-13 - Mass of carbon-12 Mass difference = 13.00335 amu - 12.00000 amu Mass difference = 1.00335 amu
02

Calculate the mass of a neutron

Now that the mass difference has been found, it will be considered as the mass of a neutron. In this problem, it is assumed that the mass difference between carbon-13 and carbon-12 is entirely due to the presence of a neutron in the carbon-13 nucleus. Mass of a neutron = 1.00335 amu
03

Convert the mass of a neutron to energy using the mass-energy equivalence principle

To determine the energy required to remove a neutron from carbon-13, the mass of the neutron needs to be converted to energy. The mass-energy equivalence principle is given by the equation: Energy = Mass 脳 c虏 Where c is the speed of light in a vacuum, which is approximately \(3.0 \times 10^8 \text{ m/s}\). However, the mass is given in atomic mass units (amu). To convert the mass to energy, first, convert amu to kilograms using the conversion factor: 1 amu = 1.66054 x 10鈦宦测伔 kg So, mass of a neutron = 1.00335 amu 脳 (1.66054 脳 10鈦宦测伔 kg/amu) = 1.66563 脳 10鈦宦测伔 kg Now, find the energy using the mass-energy equivalence equation: Energy = (1.66563 脳 10鈦宦测伔 kg) 脳 (3.0 脳 10鈦 m/s)虏 Energy = 1.501 脳 10鈦宦光伆 J
04

Present the final answer

The energy required to remove a neutron from the nucleus of a carbon-13 atom is approximately 1.501 脳 10鈦宦光伆 Joules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass-Energy Equivalence
One of the intriguing aspects of nuclear chemistry is the mass-energy equivalence principle. This principle, formulated by Albert Einstein as part of his theory of relativity, tells us that mass and energy are two sides of the same coin. It can be expressed mathematically with the famous equation: \(E = mc^2\). Here, \(E\) represents energy, \(m\) is mass, and \(c\) is the speed of light in a vacuum, approximately \(3.0 \times 10^8\) meters per second.

This equation shows us how a small amount of mass can be converted into a huge amount of energy. It's the reason why nuclear reactions can release such significant energy, and also why the tiny mass difference you encounter in nuclear reactions can have enormous effects. In the context of removing a neutron from a carbon-13 atom, we apply this principle to convert the neutron's mass into energy.

  • The conversion factor from atomic mass units (amu) to kilograms is crucial because it allows us to use the mass-energy equivalence equation.
  • Every step in this conversion process highlights how intertwined mass and energy truly are in the atomic realm.
Carbon Isotopes
Carbon isotopes are variants of the carbon element that have different numbers of neutrons in their nuclei, leading to variations in their atomic masses. The most well-known isotopes include carbon-12 and carbon-13.

Carbon-12 is the most abundant isotope, making up about 98.9% of carbon found naturally. It is stable, meaning it does not undergo radioactive decay. Carbon-12 has 6 protons and 6 neutrons, leading to its precise atomic mass of 12 amu.

Carbon-13, on the other hand, is a stable isotope as well, but it contains one more neutron than carbon-12, with 6 protons and 7 neutrons, resulting in an atomic mass of around 13.00335 amu. Although less common, carbon-13 is significant in scientific studies, particularly in organic chemistry and environmental science.

  • Differences in neutron number create isotopes, which influence the atomic mass without altering chemical properties.
  • The mass difference is key to calculations involving neutron removal or energy conversion.
Neutron Removal
In nuclear chemistry, the process of neutron removal involves eliminating a neutron from an atom's nucleus. Neutron removal is significant because it can change the isotope of an element, as experienced with carbon-13 when it transforms into carbon-12.

When removing a neutron from an atom, you are effectively changing its nuclear composition. This involves calculations to determine the energy required, which is often done using the concepts of mass-energy equivalence. The energy needed depends on the nuclear binding energy, which holds the nucleus together.

  • Neutron removal alters the mass and identity of isotopes, a fundamental aspect of nuclear transformations.
  • Understanding neutron removal helps in analyzing nuclear reactions and isotopic applications in research.
Atomic Mass Unit
The atomic mass unit (amu) is a standard unit of mass that quantifies atomic and molecular mass. It is defined as one-twelfth of the mass of an unbound carbon-12 atom, in its ground state.

In the exercise we discussed, the masses of carbon-12 and carbon-13 are given in amu. This allows us to perform calculations involving isotopes and nuclear reactions efficiently. The amu is crucial in converting mass into energy because it provides a baseline for mass measurements.

For example, the mass difference between carbon isotopes is expressed in amu, enabling the determination of the neutron's mass in such units. This mass is then converted into kilograms, a necessary step for applying the mass-energy equivalence equation.

  • Using amu helps in maintaining consistency and accuracy when dealing with atomic-scale masses.
  • It eases understanding and handling numerical values in nuclear chemistry calculations.
Energy Conversion
Energy conversion in nuclear reactions is a fascinating process that connects minuscule mass changes to vast energetic releases. Employing the equation \(E = mc^2\), we translate the small mass of a neutron into a measurable quantity of energy.

In the exercise scenario, the energy required for neutron removal from carbon-13 is calculated. By converting the neutron's mass from amu to kilograms, we can compute the energy using the speed of light squared. This conversion is not only theoretical but also practical, aiding in determining reaction feasibility and safety.

  • Energy conversion from mass plays a pivotal role in theory and application鈥攅xplaining processes from radioactive decay to nuclear power generation.
  • Understanding this conversion enables harnessing of energy, allowing advancements in technology and energy sectors.

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Most popular questions from this chapter

The ratio of neutrons to protons in stable nuclei increases with increasing atomic number. Use this trend to explain why multiple \(\alpha\) decay steps in the \(^{238} \mathrm{U}\) decay series are often followed by \(\beta\) decay.

Periodic outbreaks of food poisoning from E. coli-contaminated meat have renewed the debate about irradiation as an effective treatment of food. In one newspaper article on the subject, the following statement appeared: "Irradiating food destroys bacteria by breaking apart their molecular structure." How would you improve or expand on this explanation?

A former Russian spy died from radiation sickness in 2006 after dining at a London restaurant where he apparently ingested polonium-210. The other people at his table did not suffer from radiation sickness, even though they were very near the radioactive tea the victim drank. Why were they not affected?

Geologists who study volcanoes can develop historical profiles of previous eruptions by determining the \(^{14} \mathrm{C} /^{12} \mathrm{C}\) ratios of charred plant remains entrapped in old magma and ash flows. If the uncertainty in determining these ratios is \(0.1 \%,\) could radiocarbon dating distinguish between debris from the eruptions of Mt. Vesuvius that occurred in the years 472 and \(512 ?\) (Hint: Calculate the \(^{14} \mathrm{C} /^{12} \mathrm{C}\) ratios for samples from the two dates.)

Tiny concentrations of radioactive tritium \(\left(_{1}^{3} \mathrm{H}\right)\) occur naturally in rain and groundwater. The half-life of \(_{1}^{3} \mathrm{H}\) is 12 years. Assuming that tiny concentrations of tritium can be determined accurately, could the isotope be used to determine whether a bottle of wine with the year 1969 on its label actually contained wine made from grapes that were grown in \(1969 ?\) Explain your answer.

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