/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 If the mass number of an isotope... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

If the mass number of an isotope is more than twice the atomic number, is the neutron-to-proton ratio less than, greater than, or equal to \(1 ?\)

Short Answer

Expert verified
Answer: The neutron-to-proton ratio is greater than 1 when the mass number is more than twice the atomic number.

Step by step solution

01

Expressing Neutron-to-Proton Ratio in Terms of A and Z

To express the neutron-to-proton ratio in terms of the mass number (A) and atomic number (Z), we will use the equation A = Z + N. Rearrange the equation to solve for N: N = A - Z Now find the neutron-to-proton ratio as \(\frac{N}{Z}\):
02

Evaluating the Neutron-to-Proton Ratio under the Condition A > 2Z

Now, we will substitute the expression for N derived in the previous step into the neutron-to-proton ratio and evaluate it under the given condition: Neutron-to-Proton ratio = \(\frac{N}{Z}\) = \(\frac{A-Z}{Z}\) = \(\frac{A}{Z}-1\) The question states that A > 2Z, so we can rewrite the inequality as: \(\frac{A}{Z} > 2\) (Divide both sides by Z, since Z > 0 for any element) Now, subtracting 1 from both sides: \(\frac{A}{Z} - 1 > 1\) We see that: Neutron-to-Proton ratio = \(\frac{A}{Z}-1\) > 1 Thus, the neutron-to-proton ratio is greater than \(1\) when the mass number (A) is more than twice the atomic number (Z).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Number
The mass number of an isotope is a crucial concept in understanding the composition of an atom. It is represented by the symbol \(A\) and defines the total number of protons and neutrons in the nucleus of an atom. Protons and neutrons, together, are called nucleons. The more nucleons an atom has, the heavier its nucleus becomes.
This number is always a whole number, as it is simply the sum of discrete particles, and it helps distinguish one isotope from another of the same element. While the atomic number stays constant among isotopes of an element, their mass numbers can vary, leading to different isotopes.
  • Mass Number Formula: \(A = Z + N\), where \(Z\) is the atomic number (number of protons), and \(N\) is the number of neutrons.
A very high mass number compared to the number of protons results in a high neutron-to-proton ratio, indicating nuclear stability characteristics, which can explain natural isotopic distribution and stability.
Atomic Number
The atomic number, symbolized as \(Z\), is one of the most fundamental properties of an atom. It indicates the number of protons in the nucleus of an atom. As each element has a unique number of protons, the atomic number becomes the identifier of the element within the periodic table.
The atomic number is crucial because:
  • It defines the chemical properties of an atom.
  • It determines the element's position in the periodic table.
  • The number of electrons in a neutral atom equals the number of protons.
For example, the element with \(Z = 6\) is carbon, meaning every carbon atom has 6 protons in its nucleus. This consistent number across all atoms of the same element provides coherence to chemical reactions and bonding.
An interesting point is that while isotopes of an element differ in their mass number due to variations in neutrons, their atomic number remains unchanged, preserving the chemical nature of the element.
Isotopes
Isotopes are variants of a particular chemical element that have the same number of protons but different numbers of neutrons, leading to different mass numbers. This concept plays a significant role in understanding atomic structure and nuclear chemistry.
Despite their differences in mass, isotopes of the same element are generally chemically similar because they share the same number of electrons and protons.
  • Stable Isotopes: Do not undergo radioactive decay.
  • Radioactive Isotopes: Are unstable and decay over time, emitting radiation.
These differences in neutron count among isotopes lead to variations in their physical properties.
Natural samples of elements typically contain a mix of isotopes, the ratio of which can be very specific and consistent across samples. These isotopic distributions are crucial in applications like radiometric dating, medical diagnostics, and nuclear power, each relying on the unique characteristics of specific isotopes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Why is \(^{40} \mathrm{K}\) dating \((t_{1 / 2}=1.28 \times 10^{9}\) years) useful only for rocks older than 300,000 years?

For each of the following fission reactions, determine th identity of the unknown nuclide: a. \(^{235} \mathrm{U}+_{0}^{1} \mathrm{n} \rightarrow^{131} \mathrm{I}+?+2_{0}^{1} \mathrm{n}\) b. \(^{233} \mathrm{U}+_{0}^{1} \mathrm{n} \rightarrow^{103} \mathrm{Ru}+?+3_{0}^{1} \mathrm{n}\) c. \(^{235} \mathrm{U}+_{0}^{1} \mathrm{n} \rightarrow^{95} \mathrm{Zr}+?+3_{0}^{1} \mathrm{n}\)

In a treatment that decreases pain and reduces inflammation of the lining of the knee joint, a sample of dysprosium-165 with a radioactivity of 1100 counts per second was injected into the knee of a patient suffering from rheumatoid arthritis. After \(24 \mathrm{h}\), the radioactivity had dropped to 1.14 counts per second. Calculate the half-life of \(^{165} \mathrm{Dy}\)

Colorectal Cancer Treatment Cancer therapy with radioactive rhenium-188 shows promise in patients with colorectal cancer. a. Write the symbol for rhenium- 188 and determine the number of neutrons, protons, and electrons. b. Are most rhenium isotopes likely to have fewer neutrons than rhenium-188? c. The half-life of rhenium-188 is 17 h. If it takes 30 min to bind the isotope to an antibody that delivers the rhenium to the tumor, what percentage of the rhenium remains after binding to the antibody? d. The effectiveness of rhenium-188 is thought to result from penetration of \(\beta\) particles as deep as \(8 \mathrm{mm}\) into the tumor. Why wouldn't an \(\alpha\) emitter be more effective? e. Using an appropriate reference text, such as the \(C R C\) Handbook of Chemistry and Physics, pick out the two most abundant isotopes of rhenium. List their natural abundances and explain why the one that is radioactive decays by the pathway that it does.

Iodine- 137 decays to give xenon- 137 , which decays to give cesium-137. What are the modes of decay in these two reactions?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.